holy cow...i learnt so much in this 20 mins than i learnt in the whole module of linear circuits...it's so boring learning in a classroom...i hope i had a teacher like you...you rock man...thanks for your time and effort :)
I learned more about op-amps in these 20 minutes than from months of EE classes. That's what happens when the teacher actually enjoys what's being taught. Great job Pete.
A loads current requirements has to be meet. I don't know if I understand your question completely, but I might be able to help you. As your question stands, the answer is to check the datasheet of the component, that is connected to the opamp output, and look for I sub c equals value.
Speaking of transistors, I never understood how the gates are controlled. Like, who and how are controlloing those millions of gates to turn on/off the source and drain？
Awesome video! My question is in a typical op amp circuit (using your model at 13:27 as an example), how do you ensure electricity doesn't go through the path of R1 -> C1 -> Op Amp Output? Or is that part of the design?
Check out your comments at time 10:40 in the video. I think you did not follow through when you mentioned the audio signal is low at the inverting input. You did not mention anywhere in the video how the calculated gain of 10 is amplified at the output of the op amp. So are you saying you will not get a signal when looking with an oscilloscope between inverting and non inverting inputs or are you saying you will not get a signal when looking at your inverting input in reference to ground?
Could Anyone shed some light on how to do that calculation he put on the board c1=2pifc I can't figure out how to do that properly. thx, ( yes I'm a noob)
i don't like the way you teach. you start off by drawing a circuit, then say what will happen (huge gain), but never put values in, or show a typical output. you seem to think you saying something makes it so. how about a little corroboration ? when i ran your first circuit in TINA, i did not get a HUGE gain. but then i had to guess at values because you didn't supply them.
I think the presentation is OK, but is not prepared, it's like he is figuring out what to say in the middle of the presentation. In general I like a more structured lesson, with more order, etc. but also, this is free so can't complain too much :)
holy cow...i learnt so much in this 20 mins than i learnt in the whole module of linear circuits...it's so boring learning in a classroom...i hope i had a teacher like you...you rock man...thanks for your time and effort :)
I learnt how to derive all this from scratch two years ago, but only NOW does it make practical sense!!!
I learned more about op-amps in these 20 minutes than from months of EE classes. That's what happens when the teacher actually enjoys what's being taught. Great job Pete.
شكرا سيد بيت...
thank you from saudi...
thanks pete. this is a good refresher for us novices.
The world is analogic, the knowledge of the op qmp is essential for a electronic designer, good job Pete
Good presentation -great style
Yes you are correct.
Inverting op amp=> A=-R2/R1
Non-Inverting op amp=> A= 1+(R2/R1)
(I would presume the resistance of the op amp input is smaller than that of the cap, but I want to make sure.)
A loads current requirements has to be meet. I don't know if I understand your question completely, but I might be able to help you. As your question stands, the answer is to check the datasheet of the component, that is connected to the opamp output, and look for I sub c equals value.
Great presentation
You just Amplified my Knowledge Pete!
because an op amp is multi staged, so you get voltage and current through a bunch stages
Speaking of transistors, I never understood how the gates are controlled. Like, who and how are controlloing those millions of gates to turn on/off the source and drain？
Awesome video!
My question is in a typical op amp circuit (using your model at 13:27 as an example), how do you ensure electricity doesn't go through the path of R1 -> C1 -> Op Amp Output? Or is that part of the design?
With the feedback loop configuration, how does one find out how much current shall be drawn by the load at the output of the opamp?
Check out your comments at time 10:40 in the video. I think you did not follow through when you mentioned the audio signal is low at the inverting input. You did not mention anywhere in the video how the calculated gain of 10 is amplified at the output of the op amp. So are you saying you will not get a signal when looking with an oscilloscope between inverting and non inverting inputs or are you saying you will not get a signal when looking at your inverting input in reference to ground?
i love you pete
Good stuff bro, good stuff.
Well played Pete
Pete. This is the best.
YOUR DESK LOOKS LIKE MINE!!!!
Pete. You make me whole.
pretty cool bro!
Could Anyone shed some light on how to do that calculation he put on the board
c1=2pifc I can't figure out how to do that properly. thx, ( yes I'm a noob)
You CAPacified the whole circuit!(if thats a word)
M0AR!!
cool
guy .
nice unintended pun
felt like taught by Johnny Depp...!!!...
You don't really want to go below 1x Gain, because, well, you might not like ghosts and related paranormal stuff :3 , so yeah , keep it > 10x :3
This is why Electronic Engineers are awesome... THEY CAN WEAR FLIP FLOPS TO WORK!
(No pun intended... seriously...)
The noise in this video is distracting :(
9:48: " Rk over 10k" lol
skool got nothing on you dawg
I LIKE YOUR VID BRO I WISH I KNEW MORE ABOUT ELECTRONICS.
nm I figured it out
i don't like the way you teach. you start off by drawing a circuit, then say what will happen (huge gain), but never put values in, or show a typical output. you seem to think you saying something makes it so.
how about a little corroboration ? when i ran your first circuit in TINA, i did not get a HUGE gain. but then i had to guess at values because you didn't supply them.
I think the presentation is OK, but is not prepared, it's like he is figuring out what to say in the middle of the presentation. In general I like a more structured lesson, with more order, etc. but also, this is free so can't complain too much :)