DC Nortons Theorem
ฝัง
- เผยแพร่เมื่อ 17 เม.ย. 2015
- In this lesson we'll learn to employ Norton’s Theorem in an effort to simplify a complicated linear two terminal network into its Norton’s equivalent circuit. Ideally, the original and Norton’s equivalent circuit will behave identical to each other, however, the Norton’s equivalent circuit will be notably easier to build and solve for desired electrical quantities.
___________________
If you wish to support this project please visit the Patreon page at: / bigbadtech
___________________
Copyright information: Use this lecture. Use it at home, at work, or at school. Put it in a playlist, embed it in a website, share it with your coworkers, family, friends, and enemies. I made this lecture and posted it on TH-cam so users everywhere have free access to this information.
This being said, this TH-cam channel is meant to be the sole point of distribution for this lecture. Users are not authorized to download it, change it, or charge for access. Don’t even think of downloading it and uploading to your own channel and pretending it’s your own work. Not cool. Use this lecture and let your friends know this free resource exists.
Use it. Don't steal it. Be cool.
__________________
For more FREE online technical training check out the following playlists available at the bigbadtech channel:
Basic Electricity and Electronics: DC Circuit Analysis • DC Circuit Analysis
Basic Electricity and Electronics: Single Phase AC Circuit Analysis • Single Phase AC Circui...
Basic Electricity and Electronics: 3 Phase AC Circuit Analysis • 3 Phase AC Circuit Ana...
Hydraulics • Hydraulics and Electri...
Motor Control • Motor Control
Motors and Generators • Motors and Generators
Motor Drives/Variable Frequency Drives (VFD) • Motor Drives
Programmable Logic Controllers (PLCs) • Programmable Logic Con...
Additionally, check out the compiled lectures and study guides at:
openoregon.pressbooks.pub/ele...
openoregon.pressbooks.pub/ele...
openoregon.pressbooks.pub/ele...
openoregon.pressbooks.pub/hyd...
Like you, I greatly prefer Thevenin's equivalent circuit to Norton's; nevertheless there are some circuit topologies where finding the Norton current is simpler than finding the Thevenin voltage. In such cases, working out the Thevenin circuit first and then transforming it into the Norton circuit is superfluous. For instance in your opening example problem Isc = 40 volts ÷ 680 ohms = 1/17 amps.
True dat. Use the right tool for the occasion!
Ahhh, Norton's Theory brings the fun of explosions with an AM to the party... So its cool in my eyes hehe... But yeah I do prefer Thevenin's Theory. But both are quite easy really, though mostly due to as others have said.. The best teacher on the planet never mind the internet... ty :)
Thanks for the great content . You truly understand the common struggles with each topic and really explain it in its fundamental form . I have never seen a teacher like you . The closest comparison I can make to you is the organic chemistry tutor (also my life saver) . Teachers just can't be bothered...
best circuits videos EVER
why was the 220 Ω resistor cancelled in 9:30 ??
Thanks for your videos in general they have been really helpful
If given the choice between battling through a 220ohm resistor or taking the 0ohm path through the ammeter all current will travel through the 0ohm ammeter and the 220ohm resistor can be removed from consideration.
i guess im missing the intuition of why electricity behaves the way it does. Ive seen many animations about electricity being a mountain and other ways but it still doesnt make sense to me on what electricity really is and why it behaves the way it does. thanks for your answer either way (:
Check out some of the earlier lectures in the "Basic Electronics 1: DC Circuit Analysis" playlist where I discuss some ways to visualize basic electrical quantities. My recommendation would be:
Basic Electrical Quantities th-cam.com/users/edit?o=U&video_id=b1c2oEyogss
and Ammeters th-cam.com/users/edit?o=U&video_id=AQRRl1ReeFo
Another recommendation is to really build these circuits using real hardware and real instrumentation. Although these lectures discuss the theory they can't replace actual experience in a lab.
Getting my degree based of TH-cam lol
For the problem ar 20:07:
First I converted the 40v and series 200ohm to a current source of 200ma in series with 200 ohm. Then you just have 2 current sources (opposite direction) and two parallel resistors. Finding Norton current is easy since the load is shorted and both parallel resistors are shorted. Then you just have 2 current sources canceling each other out with superposition.
Let me know how you'll feel about this please
If it's stupid and it works .... it's not stupid! Yes, source conversion is a great way of simplifying circuits, especially ones with multiple sources.
LOL. You needlessly complicated this problem. No need to use superposition and do 2 separate calculations when one will do. Simply do a source transformation on the 40 V / 200 Ohm series to come up with an equivalent 200 mA / 200 ohm parallel circuit. Now everything is in parallel. You then have 200 mA going right to left bypassing the 200 and 500 ohm resisters and shedding 50 mA down that one leg leaving 150 mA through the short circuited path which is your Norton current. Your Norton equivalent resistance is then easily calculated as the parallel combination of 500 and 200 ohm resisters = 142.85.
Yes , you are very good and right . But since these videos are for beginners, that could have really confused them . He really wants people to understand what they are doing . Suoer position really broke down the problem to parts