That is the formula for calculating the force ‘felt’ between two charges (electrostatic force). We are looking for the electric field strength in this question. 👍
Because it is an absolute value into the formula ... E3 = K |Q3|/R^2 ... Whenever you're solving with coulomb's law or any vector problems, you don't insert the sign of charges into the formula :) I hope you got the concept.
in 9:20 about how you come with the degree, it should be 26 degree, 33 minutes not 26.57 degree, after i entered the value in tan-1 it will give a value of 2.65650512x10 and i pressed degree mode which in turn gives me a degree of 26 degree and 33 minutes, it really is confusing, my prof tells that we should enter after the value in tan-1 degree mode, to give the exact degrees, really appreciate if you gonna answer my Q, btw thnx for the lesson though
We're really thankful for the support may God bless you and all your family
Very clear and understandable. Thank you!
Bless this video, it helped me so much
Why are the answers different in your text?
@Coffee mug that equation is to determine the force. Thanks Mike for the video. I found it extremely helpful.
You're not totally using the formula E=kq/r^2 ?
That's for electrostatic force between point charges. For the electric field it's that equation divided by q, so I just one q
doing the same problem but with electrostatic forces, we would use the formula k(q1q2)/r^2?, and do the exact same thing?? HELP
Why are the answers different from the ones n the questions?
please correct me if im wrong, but isnt the formula k(q1q2)/r^2?
That is the formula for calculating the force ‘felt’ between two charges (electrostatic force). We are looking for the electric field strength in this question. 👍
Thank you soo much!
Thank you so much :)
a point charge is a small charge right(area is negligible). correct me if i am wrong.
supraj hegde Yes it has a negligible area as well as negligible charge on it. So it has got no effect on the source charge.
Thank you!!
Why isn't E3 a negative value since its -4x10^-6 C?
because where finding the magnitude, bro.
Because it is an absolute value into the formula ... E3 = K |Q3|/R^2 ... Whenever you're solving with coulomb's law or any vector problems, you don't insert the sign of charges into the formula :) I hope you got the concept.
Reymark Renigen The negative sign is only for the direction :) We use the absolute value on the magnitude
in 9:20 about how you come with the degree, it should be 26 degree, 33 minutes not 26.57 degree, after i entered the value in tan-1 it will give a value of 2.65650512x10 and i pressed degree mode which in turn gives me a degree of 26 degree and 33 minutes, it really is confusing, my prof tells that we should enter after the value in tan-1 degree mode, to give the exact degrees, really appreciate if you gonna answer my Q, btw thnx for the lesson though