For PDF Notes and best Assignments visit @ physicswallahalakhpandey.com/ To support me in my journey you can donate (Paytm@ 9161123482) or Alakh Pandey ,Bank of Baroda, Rajrooppur, Allahabad,U.P IFSC: BARB0RAJROO Account No: 19210100020819 A small amount of Rs 100 even will be of great help. Follow us on: Instagram instagram.com/physicswallah/ Facebook: facebook.com/physicswallah Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!!
What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on TH-cam) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chapter 7 | Equilibrium | Chemical Equilibrium 01 : Introduction | IIT JEE MAINS / NEET th-cam.com/video/sCUgeC5ACv8/w-d-xo.html Equlibrium | Chemical Equilibrium 02 | Equilibrium Constant Kp and Kc | IIT JEE MAINS /NEET th-cam.com/video/oyr7q5BrGEA/w-d-xo.html&pbjreload=10 Equilibrium | Chemical Equlibrium 03 | Law Of chemical Equilibrium Numericals IIT JEE / NEET th-cam.com/video/z2G52O_7nd4/w-d-xo.html Equlibrium | Chemical Equilibrium 04 | Degree of Dissociation and Observed density IIT JEE / NEET th-cam.com/video/x13K19_JwgY/w-d-xo.html Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET || th-cam.com/video/NVZ4Jb9tLX4/w-d-xo.html ----------------- IONIC EQUILIBRIUM ------------- Class 11 chapter 7 | Equilibrium | Ionic Equilibrium 01 | Theories Of Acids and Bases JEE MAINS/NEET th-cam.com/video/Uql1eQGq9Dg/w-d-xo.html Ionic Equilibrium 02 | Ionisation Constant Of Weak Acid and Base | Ionic Product of Water JEE /NEET th-cam.com/video/Dgdz6bfRMdc/w-d-xo.html Ionic Equilibrium 03 || PH Of Solutions | How to find PH | How to calculate PH of any Solution th-cam.com/video/uuGl5o8b3Zk/w-d-xo.html Ionic Equilibrium 04 || Common - Ion Effect IIT JEE MAINS/ NEET || th-cam.com/video/xqq78GsLXSA/w-d-xo.html Equilibrium | Ionic Equilibrium 05 | Buffer Solutions JEE MAINS/NEET /JEE ADVANCE -Part 1 th-cam.com/video/KH0w5TZnJaA/w-d-xo.html Equilibrium | Ionic Equilibrium 06 | Buffer Solutions JEE MAINS/ NEET/ JEE ADVANCE -Part 2 th-cam.com/video/30eFAm74wp0/w-d-xo.html Ionic Equilibrium 07 || Salt Hydrolysis IIT JEE MAINS / JEE ADVANCE / NEET || pH of Salts th-cam.com/video/I33BwmAz1sY/w-d-xo.html Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET || th-cam.com/video/1tRdbmroncE/w-d-xo.html
For the last Question, N204 = 2N02; 1)Temp = Since, its a decomposition reaction [DIMER - MONOMER] heat should be supplied to it, which means It is ENDOTHERMIC, there temp should be high 2)Pressure = should be lower as, high pressure means eq. shifts towards lower mole side 3)Inert material = should be Added as, eq shifts to the side having more moles of substance
Ans for the last question: Pressure = low Inert material should be added. Is it exo or endo, it,s not mentioned in the equation , so, temp isn't defined.
It is decomposition reaction...so heat should be supplied to break the compound...this information will most likely be not given in the question, so you have to know it...hope this helps
N2O4 is being converted to NO2.. Dimer to monomer ..i.e. heat has to be supplied which implies forward direction reaction is endothermic. Hence increasing the temperature will yield more NO2
I am watching this video after 3 yrs . I must say that this man is genius . I have never seen a teacher even in coachings also who can teach both physics and chemistry with so much fun and feel . I wonder that how this video got 728 dislikes
Bro u are watching this video for last 3 years but unfortunately u didn't learn that's why u are watching this video continuously couples of years 😅😅 Just kidding 😂😂
Answer for the last question... 1) Increase the concentration of N2O4 2) high temperature is required 3) Low pressure is required 4) addition of inert material at constant pressure is also required... Thank you sir, you are doing a great job...
Temperature : High (since it is an endothermic reaction although not mentioned) Pressure: Low Inert material : we will use as it shifts the equilibrium forward towards more no of moles.
Sir hamara toh 12th khatam ho gaya lekin aap jo kar rahe ho woh laakho ki zindagi badlega yeh tution walle ne sab cheezo ko apna buisness bana rakha hai zyaada aur education kam...aap jo karr rahe ho wohh karte rehna pls rukna matt aapko saari tution industry ko karara jawab dena hai aur unko batana hai that education is same for all wheather a person is average or class topper
Vandit Vasoya that “expensive internet” would still be cheaper than what tuitions and coachings cost. Also, 600 dollar for 10 minutes.. yeah that’s an absolutely made-up number. Even the biggest youtubers on the platform don’t get paid that much. So please, do some research before you spew absurd statements
1. Temprature high (bcz : N2O4 do heat absorb than convert in NO2) 2. Pressure low 3. Inert material was like advantage for this reaction 🙏... ..........🙇 Tx so much sir 🙇.......... .....🙇for solve all type of doubts🙇.......
commando offical At 1:01:10 sir stated that if no delta H is given, the reaction is forward. So in order to increase the production of NO2 temperature has to be increased.
@@bijitdas208 Yes,here we don't know either it is exothermic or endothermic,so go by the basic thumb rule.....that is on high temp molecules will gain kinetic energy hence the molecules can easily collide with each other thus resulting NO2.... or do generally consider it to be endothermic [PLEASE DO CORRECT ME IF IAM WRONG]
sir poore you tube pe kyaaa aap jaise teacher poore desh duniya mei ginee chunee hotey hai aap ke andar josh aur jazbaa hai aaap karate hai concepts ko crystal clear ...!! may god bless you. your each and every lucture's explanation is awesome..aapse padhkar physics aur chemistry se har student ko pyaar ho jayee agar kisi bhi bacche ko aapse naa smjh aaye tohh wo phir mann buddhi hai...you are one of the best teacher in the world🤩👍 aapko bharat ke bacho jaur usse jude uske padosi desh kee bacho ki dil se dua nikalti hai may you acheive more success in your life ...!! stay happy and healthy ...!! and stay the same sir as you are thank uh so much...!!😊 jitni tareef karein aapki utni kam hai hai you are the best teacher...!! thankss alakh sir😊💖
Temp:- not defined cuz it's not that reaction is endo or exo. Pressure :- low Inert gas should be added. *Sir aap hum bachcho ke liye vardan ho.* 🙏🏻🙏🏻😁😁
Reaction endothermic hogi na....kyu ki bond break ho rhe h......! Or hume energy deni pdegi(endothermic) bond break krane k lie..... Hence to favour endothermic reaction we hv to Inc the temperature.. 🙋🏼♂️🙋🏼♂️
Hey but if we increase the temp pressure also rises n if pressure increases the equilibrium shifts backward so we can say that the conditions are: Low temp Low pressure Addition of inert gas
I usually understand this principle by using the " Mad man method " where it is said that mad man will do the opposite you do.. You increase pressure, mad man tries to decrease it, he goes there.. You increase conc., mad man tries to decrease it, he goes to less moles... You increase temp. , mad man tries to decrease it, he goes to less temp. system... like that it can be easy..
U are the best teacher I have ever met in my life...u r just awesome and your examples just strike on my mind in few micro seconds😎😂 hope that meet u soon...lots of love alakh sir😍
Hats off to you sir... You are inspiration for millions.. one day i will also become successful and will definitely help those in need whether economically or through teaching free of cost just like you..
Actually physics lectures' questions are pretty hard which definitely is an issue with my IQ but concept wise i feel he has benefited me A LOT in Chemistry than physics. In a nutshell , he's definitely one of the best teachers on TH-cam platform.
Favorable conditions for the last reaction :- 1 : By increasing the concentration of [N2O4] or by removing [NO2] 2 :Pressure should be low 3 :Can't define temperature 4: at ∆P=0 then forward reaction (which will not help in increasing the production )
School me teachers toppers ke liye partiality show karte hai aur baki bacho ko ignore karte hai sirji aapko dil se thanks bol rahe hai me aur mere friends aapka lecture hi dekhte hai hum 12 me hai par 11 ki study kar rahe hai sirf aapki wajah se hume poora bharosa hai ki hum jee clear kar lenge
answer of homework question PRESSURE ----- PRESSURE SHOULD BE LOW TEMP----- TEMPERATURE SHOULD BE HIGH AS ENERGY IS REQUIRED TO BREAK BOND --- N204 IS DIMER OF NO2 AND ENERGY IS REQUIRED TO BREAK THE N---N BOND SO THE RXN IS ENDOTHERMIC AND TEMP SHOULD BE HIGH INERT MATERIAL---- SHOULD BE ADDED
@@naveensoni5771N2O4->2NO2 mai 100% n2o4 colorless at -11 degree celsius and 100% brown fumes of No2 at 140 degree Celsius so obviously this reaction is endothermic that's why high temperature is favorable.
Watched Amit mahajan sir's lecture, didn't understand much... Watched Shishir mittal sir's lecture, feel nhi aayii... Watched Alakh Pandey sir's lecture, concept is now coming into my dreams too.. 😂❤❤ alakh sir OP
Kml ho giya sir ji Ur teaching method is too much Awesome keep it sir All concept clear after hearing ur lecture I'm from Pakistan 🇵🇰 Bundle of love and great wishing for u from Pakistan 🇵🇰 May Allah bless u with more success in your life جزاک اللّٰہ 😍
Home work Temp- high, ( heat acts as rectant in the decomposition of dinitrogen tetroxide, the reaction is endothermic) Pressure_low Inert material -needed with constant pressure
46:50 Those who didn't understand fully . Addition of inert material would increase volume, Hence pressure decreases and we know when pressure decreases , equilibrium shifts towards side with higher no. of moles .
Guys have u noticed,at 26:00 jo sir ne example dia tha usme reaction ka direction phle forward bataya tha,but after some seconds sir ne usko edit krke backward krdia.?isse ye pta chlta hai sir bhi kbi kbi confuse hote hai.no problem sir hota hai : )
Sar there is something magic in ur teaching.... Jo apke course ke teacher nhi smjha paye vo apne smjha dia sirji.... Aab chap gya dmg me.... So easy way❤️❤️
@Vladimir Vladimirovich Putin You are right bro, but not all the boys are the same here. I am also a guy but I never do that and yeah i am a fan of PewDiePie.🔥🔥🔥
U r really great both as teacher and as a person,although I am teacher but I admit I have learnt a lot of conception in chemistry from ur classes,I am ur fan ....May God bless u and give u enough strength for continuing ur work.
N2O4 is a stable than NO2 ( Dimer), hence Backward reaction Energy releases - Exothermic therfore low temp is favoured for backward reaction. But Question is about Forward reaction . Obviously forward reaction is endothermic Hence temp must be high @Aakash Nigam
There is one more point . . . 5. The addition of catalyst: it doesn't effect the concentration of equilibrium mixture, as it only increases or decrease the time to attain equilibrium.
As catalyst is inert to the reaction (because it increases the rate of reaction but doesn't itself react with any product /reactant) , it is hence included in 4th point
Answers of the last question • Pressure - Should be low • Temperature - Not given • Inert material - should be added , which leads to more forward reaction
Sir my name is Farheen .I am from Andhra Pradesh .....I know Hindi..... When I didn't understand any topic then I first prefers your channel only .... because your teaching is amazing.....I really like your teaching.....♥️ I wish this teaching will goes 1000 s of years💐💐💐thank you so much sir ....🥰🥰
@@RajendraKumar-br9gj decomposition reaction mein heat is required to break bonds so reaction will proceed in forward direction as N2O4 + ∆ ------> 2NO2 Reaction will proceed in the direction of heat absorption (NO2 production increases) 😊
Temp---decrese Pressure---decrese Ya I know heat is not given And even not that it is exo or Endo But pressure directly proportional ...to temp And even Inert material should be added 💖🔥 Thx sir for your love and support 👍
Answer of last question: Production of NO2 can be increased by: 1-By D decreasing the Pressure. 2-By the addition of inert material at constant pressure. Thanks for your Well explanation sir, love you 🙂🙂
For PDF Notes and best Assignments visit @ physicswallahalakhpandey.com/
To support me in my journey you can donate (Paytm@ 9161123482) or
Alakh Pandey ,Bank of Baroda, Rajrooppur, Allahabad,U.P
IFSC: BARB0RAJROO Account No: 19210100020819
A small amount of Rs 100 even will be of great help.
Follow us on:
Instagram instagram.com/physicswallah/
Facebook: facebook.com/physicswallah
Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App.
Download the App from Google Playstore ( bit.ly/2SHIPW6 )
Physicswallah Instagram Handle : instagram.com/physicswallah/
Physicswallah Facebook Page: facebook.com/physicswallah
Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20
Physicswallah App on Google Play Store : bit.ly/2SHIPW6
Physicswallah Website: physicswallahalakhpandey.com/
LAKSHYA Batch(2020-21)
Join the Batch on Physicswallah App bit.ly/2SHIPW6
Registration Open!!!!
What will you get in the Lakshya Batch?
1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey.
2)Live Classes and recorded Video Lectures (New, different from those on TH-cam)
3)PDF Notes of each class.
4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.
5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.
6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
7)In case you missed a live class, you can see its recording.
8)You can view the videos any number of times.
9)Each chapter will be discussed in detail with all concepts and numericals
10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.
****Test Series for XI & XII****
We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.
Class 11 chapter 7 | Equilibrium | Chemical Equilibrium 01 : Introduction | IIT JEE MAINS / NEET
th-cam.com/video/sCUgeC5ACv8/w-d-xo.html
Equlibrium | Chemical Equilibrium 02 | Equilibrium Constant Kp and Kc | IIT JEE MAINS /NEET
th-cam.com/video/oyr7q5BrGEA/w-d-xo.html&pbjreload=10
Equilibrium | Chemical Equlibrium 03 | Law Of chemical Equilibrium Numericals IIT JEE / NEET
th-cam.com/video/z2G52O_7nd4/w-d-xo.html
Equlibrium | Chemical Equilibrium 04 | Degree of Dissociation and Observed density IIT JEE / NEET
th-cam.com/video/x13K19_JwgY/w-d-xo.html
Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET ||
th-cam.com/video/NVZ4Jb9tLX4/w-d-xo.html
----------------- IONIC EQUILIBRIUM -------------
Class 11 chapter 7 | Equilibrium | Ionic Equilibrium 01 | Theories Of Acids and Bases JEE MAINS/NEET
th-cam.com/video/Uql1eQGq9Dg/w-d-xo.html
Ionic Equilibrium 02 | Ionisation Constant Of Weak Acid and Base | Ionic Product of Water JEE /NEET
th-cam.com/video/Dgdz6bfRMdc/w-d-xo.html
Ionic Equilibrium 03 || PH Of Solutions | How to find PH | How to calculate PH of any Solution
th-cam.com/video/uuGl5o8b3Zk/w-d-xo.html
Ionic Equilibrium 04 || Common - Ion Effect IIT JEE MAINS/ NEET ||
th-cam.com/video/xqq78GsLXSA/w-d-xo.html
Equilibrium | Ionic Equilibrium 05 | Buffer Solutions JEE MAINS/NEET /JEE ADVANCE -Part 1
th-cam.com/video/KH0w5TZnJaA/w-d-xo.html
Equilibrium | Ionic Equilibrium 06 | Buffer Solutions JEE MAINS/ NEET/ JEE ADVANCE -Part 2
th-cam.com/video/30eFAm74wp0/w-d-xo.html
Ionic Equilibrium 07 || Salt Hydrolysis IIT JEE MAINS / JEE ADVANCE / NEET || pH of Salts
th-cam.com/video/I33BwmAz1sY/w-d-xo.html
Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET ||
th-cam.com/video/1tRdbmroncE/w-d-xo.html
Chuha kon khata h sir😁😁
@@mitanshrathi855 tum😂😂😂🤣🤣🤣
@@partha3322 app kon
@@mitanshrathi855 Don😎😎😂😂😂
sir reaction quotient pr bna do video
For the last Question,
N204 = 2N02;
1)Temp = Since, its a decomposition reaction [DIMER - MONOMER] heat should be supplied to it, which means It is ENDOTHERMIC, there temp should be high
2)Pressure = should be lower as, high pressure means eq. shifts towards lower mole side
3)Inert material = should be Added as, eq shifts to the side having more moles of substance
Yes,,i got the same but got confused in temp
@@sumantraks7639same
but while adding inert material pressure should be constant but here we already decreased the pressure
Correct...Thanks for confirming
You are correct
I am watching this video after 5years (2023) full crystal clear concepts explain by sir (salute)
khatarnak bhai hai ALAKH SIR
BEST CHEMISTRY TEACHER I HAVE EVER SEEN
selection hua bhai
Ans for the last question:
Pressure = low
Inert material should be added.
Is it exo or endo, it,s not mentioned in the equation , so, temp isn't defined.
It is decomposition reaction...so heat should be supplied to break the compound...this information will most likely be not given in the question, so you have to know it...hope this helps
N2O4 is being converted to NO2..
Dimer to monomer ..i.e. heat has to be supplied which implies forward direction reaction is endothermic.
Hence increasing the temperature will yield more NO2
u r right
Yes I was confused here...
@@hawkhcr2445 thanks dude...has this question in my mind 👍
I am watching this video after 3 yrs . I must say that this man is genius . I have never seen a teacher even in coachings also who can teach both physics and chemistry with so much fun and feel . I wonder that how this video got 728 dislikes
dont wonder , go do your work
By the other coaching.
Me too.. 😂😂
@@anmol.1338 instead of responding go do ur work
Bro u are watching this video for last 3 years but unfortunately u didn't learn that's why u are watching this video continuously couples of years 😅😅
Just kidding 😂😂
Answer for the last question...
1) Increase the concentration of N2O4
2) high temperature is required
3) Low pressure is required
4) addition of inert material at constant pressure is also required...
Thank you sir, you are doing a great job...
Bilkul shi bachaa..correct answer temp wala concept explain kro
Temperature increases hoga hi nhi other wise everything is correct except temperature vala factor
Temp. Except all correct
I also have the same answer....😎
@@shaikhumer662 yes u are right temperature is not mentioned in the question.
Effect of:
Conc- 11:42
Pressure- 18:29
Temp- 31:16
Inert Material- 42:35
Thanks sis
Thanks sis
Thank you
You rocked
@@havishbalaga9397 how u know person is female???? 🐶
Temperature : High (since it is an endothermic reaction although not mentioned)
Pressure: Low
Inert material : we will use as it shifts the equilibrium forward towards more no of moles.
How do you know that it is an endothermic rxn
Ho w did u get the temp hidh
After 5 years also this video is a boon ❤
Exactly 💯
Truee
सर आप तो केमिस्ट्री और फिजिक्स दोनों के प्रोफेसर हैं 😯😯😯✌️😚🇮🇳🔥❤️
Stay blessed sir( From Pakistan)
Me too bri❤
Here's Pakistan 🎉
Sir hamara toh 12th khatam ho gaya lekin aap jo kar rahe ho woh laakho ki zindagi badlega yeh tution walle ne sab cheezo ko apna buisness bana rakha hai zyaada aur education kam...aap jo karr rahe ho wohh karte rehna pls rukna matt aapko saari tution industry ko karara jawab dena hai aur unko batana hai that education is same for all wheather a person is average or class topper
You are absolutely right
Vandit Vasoya that “expensive internet” would still be cheaper than what tuitions and coachings cost. Also, 600 dollar for 10 minutes.. yeah that’s an absolutely made-up number. Even the biggest youtubers on the platform don’t get paid that much. So please, do some research before you spew absurd statements
Chupp bee
Aisa nahi bolnaa
Well done .your thought is 100% correct
These videos can never be got old.
After 3 years.........
Thank you very much sir🙏🙏🙏🙏🙏🙏
relatable
😄😄
@@अंशुलउज्जवलकर mai bhi
Koi kaha se hai kiuna parlo selection hoga to shirf Alakh sir video se hi.
It will never get old till 1000s of years
Sir I love your T-shirts 😂 "Rise above Stereotypes" ✌️✌️
What about his knowledge??
@@MohammadAsif-dh7ik wo toh under stood hai
I want a stock of sir's t shirts... Especially that light dogla hai one...😂😂
@tricky ishu escape velocity wala mein kya likha hein??
@tricky ishu yup...😂😂
1)Exothermic kee liye-temp low
Endothermic ke liye temp High
2) pressure-low
3)inert material
1) constant vol no effect
2) constant pressure
Pressure low
Inert material: Const Volume no effect
Constant Pressure
Temperature I am confused sir.
Thank you
Huge respect for this extraordinary personality his lectures are mind-blowing
Army 💜
@@sathvikachowdary3752 💜💜💜
12 nahi sir 11th ka hona
1. Temprature high (bcz : N2O4 do heat absorb than convert in NO2)
2. Pressure low
3. Inert material was like advantage for this reaction 🙏...
..........🙇 Tx so much sir 🙇..........
.....🙇for solve all type of doubts🙇.......
Alakh sir teaches chemistry extremely good... i almost forgot that his name actually is physics wallah
Oh wow!
Good one!😂
His name actually is ALAKH SIR
So true me too😁
Are unka naam alakh pandey hai.unke channel ka naam physics wallah hai
This channel is literal the best for chemistry and physics . Love this
Ans.
temperature should be high as it is a decomposition reaction.
pressure should be low.
inert material should be added at constant pressure.
Same ans
Same
@@princejagane7008 temp kyu high karenge
+Gaurav Jain kyu ki reaction ko forward direction me le Jana hai or NO2 form krna hai
Same ans
1:07:46
N2O4 2NO2
Temp : High (Cuz bond breaking..i.e endothermic)
Pressure: Low
Inert material: Should be added
Why temp High?
@@user-saheen999 cuz rxn is endothermic...temp should be made high
Ok
Well... There are many intro sounds nowadays
But alakh sir's intro sound is the best of them all
11:08 Sir hum to forever ready hain aapke sath antakshari khelne ke liye bas aap live aa jao😅
It is #DecompositionReaction and also N2O4 is a dimer of NO2.
Temp= high
Pressure= low
Inert material is required at constant pressure
Aap ko kasa malum hua ka ya decompostion reaction hh plzz bata do mako sab ka ans mil gaya par temp. ma samj nahi aarha hh
Search it on google yaar ....,mostly it would be given in question
commando offical At 1:01:10 sir stated that if no delta H is given, the reaction is forward.
So in order to increase the production of NO2 temperature has to be increased.
Temp kyun high chahiye
@@bijitdas208 Yes,here we don't know either it is exothermic or endothermic,so go by the basic thumb rule.....that is on high temp molecules will gain kinetic energy hence the molecules can easily collide with each other thus resulting NO2....
or do generally consider it to be endothermic
[PLEASE DO CORRECT ME IF IAM WRONG]
sir poore you tube pe kyaaa aap jaise teacher poore desh duniya mei ginee chunee hotey hai aap ke andar josh aur jazbaa hai aaap karate hai concepts ko crystal clear ...!! may god bless you. your each and every lucture's explanation is awesome..aapse padhkar physics aur chemistry se har student ko pyaar ho jayee agar kisi bhi bacche ko aapse naa smjh aaye tohh wo phir mann buddhi hai...you are one of the best teacher in the world🤩👍 aapko bharat ke bacho jaur usse jude uske padosi desh kee bacho ki dil se dua nikalti hai may you acheive more success in your life ...!! stay happy and healthy ...!! and stay the same sir as you are thank uh so much...!!😊 jitni tareef karein aapki utni kam hai hai you are the best teacher...!! thankss alakh sir😊💖
Temp:- not defined cuz it's not that reaction is endo or exo.
Pressure :- low
Inert gas should be added.
*Sir aap hum bachcho ke liye vardan ho.* 🙏🏻🙏🏻😁😁
Reaction endothermic hogi na....kyu ki bond break ho rhe h......!
Or hume energy deni pdegi(endothermic) bond break krane k lie.....
Hence to favour endothermic reaction we hv to Inc the temperature..
🙋🏼♂️🙋🏼♂️
Hey but if we increase the temp pressure also rises n if pressure increases the equilibrium shifts backward so we can say that the conditions are:
Low temp
Low pressure
Addition of inert gas
yes exactlly
@@neerajmistry9279 I think you are right
Pressure ke low kese last baale questions ka ,
I usually understand this principle by using the " Mad man method " where it is said that mad man will do the opposite you do..
You increase pressure, mad man tries to decrease it, he goes there..
You increase conc., mad man tries to decrease it, he goes to less moles...
You increase temp. , mad man tries to decrease it, he goes to less temp. system...
like that it can be easy..
Nice sir 👍
@@tunseducation2561 great 👏,Bangladesh er kothai bari vii?
Great trick its made my day ❤
Rather understand the Science
11:58 i) concentration
ii) 18:02 Change in Pressure
iii) 31:20 Chnage of Temperature
iv) 44:39 Addition of inert
Pressure=low
Inert material should be added
Temp exo or endo not mention in this equation
Yeah....pre low
Inert material added...
And for tem not mention reaction is exothermic or endothermic...
right
But due to increase in temp the production should have been increase right
Alakh sir teaches really good.
His videos helped in building concepts for mdcat and were helpful in cracking it.
Respect from Pakistan 🇵🇰
hi brother in which med clg are you ?
Me every time “lechatle” principle 😂😂
😂😂
😂😂😂
👌👍😝
Ssme
Same
Sir, you are a great teacher in the world.And you have proved that old is gold.Your old videoes help me a lot .
Thank you sir 🙂🙂🙂
👍😊😊😊
diksha aap instagram chalate ho??
@@UpscLover-AB420 HI brother 😊👍
Same ❤
@@epicshorts8076 yes😇
Sir doesn't need to tell people to like the video, we automatically after watching it like it immediately
U are the best teacher I have ever met in my life...u r just awesome and your examples just strike on my mind in few micro seconds😎😂 hope that meet u soon...lots of love alakh sir😍
Which college?
Best lecture on Le- Chatelier's Principle you'll find on youtube 😊👍👍👍👍
1:07:37
1) Temperature - High
2) pressure -low
3)a) Constant volume - no change
b) constant pressure - high
Hats off to you sir... You are inspiration for millions.. one day i will also become successful and will definitely help those in need whether economically or through teaching free of cost just like you..
Alakh pandey is the best teacher for physics as well as chemistry amongst all the teachers I have seen so far 🤗🤗🤗
What is ur opinion guys 🤔🤔
The amount of views on his videos obviously tell that
I am agree with you bro☺☺☺
Absolutely🙌😎
I am also a FF player
Actually physics lectures' questions are pretty hard which definitely is an issue with my IQ but concept wise i feel he has benefited me A LOT in Chemistry than physics. In a nutshell , he's definitely one of the best teachers on TH-cam platform.
I have seen very few teacher which revise all topic which they explain and Alakh Sir is one of them.
Answer is
Pressure low
Yes inert material should be used
No think about temp because there is no heat relevant information
Aap se concept clear Karna matlab khud physics ke god se sikhna🤩🤩🤩🤩♥️💖💖💖💓
Tuhada teacher coaching sir SaDa teacher one and only ALAkh SiR,🙏🙏😁😁😁👍👍👍👍🙏
Bekkar😑😑😑😑😒😒😒
LoL par nevermind utna bhi acha nahi that par well tried👍🔥
Favorable conditions for the last reaction :-
1 : By increasing the concentration of [N2O4] or by removing [NO2]
2 :Pressure should be low
3 :Can't define temperature
4: at ∆P=0 then forward reaction (which will not help in increasing the production )
Right 👍
I learnt this chapter so perfect by seeing your lectures sir...we're paying alot on tution and actually learning from you without anything..
1:07:46 For maximum yield of NO2
Pressure - low
And inert gas should be added
And temperature???
आप ने आने वाली कई पुश्ते सुधार दी ❤
Indiya me sabse best teacher ➡️sir aise hi concept chahiye sir hamesha 👍🏼👍🏼➡️💯
Sir . It was really helpful. All misconceptions are cleared...!! Best teacher . 👍👍😁😁
i am blessed to find this channel. i dont have words to thank u sir.
th-cam.com/video/pP04V0d_QbI/w-d-xo.html
Same here 😌
Same with me . I am so lucky to got this channel.
Hi
@@pranjulkumar3999 tere se puchi kisi ne?
1. Pressure - Decrease
2. Temperature - Increase ( because it is an endothermic reaction with ∆H = +57)
3. Inert Material - It should be added.
Temperature increases
Decomposition reaction is endothermic..not exo-
@@hawkhcr2445 Thank you bhai.👍👍
MCQth-cam.com/channels/F5ie8yBPVZxVAhx8jKWxtg.html
Bhai kaise pta Chala ki ye endothermic reaction h
Temp-high(endothermic)
Pressure-low
Inert material should be added
👍👌
How to know that this reaction is endothermic 😶 or where heat is being added ?
@@prakharsingh5111 n2o4 ka bond break hoga uske liye bond dissociation energy deni padegi isliye endothermic 😅😊
Thank you soo much Alakh Sir for making Le Chatelier's Principle so crystal clear!Hats off to you Sir!Lots of Love and Respect...👏😎👌👌🤓😌🙏🙏😎😁😉
He is absolutely amazing ..... Mashallah ...❤️ God bless him .... Such an amazing teacher.........
hiii
Finally Chemical equilibrium Done 👍
Your T-Shirt "RISE ABOVE" is a strong motivation for every pwians 🌠🔥
*Rise above stereostypes
*Rise above stereotypes
School me teachers toppers ke liye partiality show karte hai aur baki bacho ko ignore karte hai sirji aapko dil se thanks bol rahe hai me aur mere friends aapka lecture hi dekhte hai hum 12 me hai par 11 ki study kar rahe hai sirf aapki wajah se hume poora bharosa hai ki hum jee clear kar lenge
Hua clear
thankyou sir, mujhe chemical equilirium kabi samaj me nahi aata tha par ab mera sara consept clear ho gaya
Sir, I am studying bsc however I am watching your videos to solve my doubts and concept.....
Thank you so much physics walhaa
yrr BSc me kuch ni h koi concept ni bante...isse acha toh Btech krlo knowledge to banti h aur technical knowledge badh jati h
I am from same course there's no scope
answer of homework question
PRESSURE ----- PRESSURE SHOULD BE LOW
TEMP----- TEMPERATURE SHOULD BE HIGH AS ENERGY IS REQUIRED TO BREAK BOND --- N204 IS DIMER OF NO2 AND ENERGY IS REQUIRED TO BREAK THE N---N BOND SO THE RXN IS ENDOTHERMIC AND TEMP SHOULD BE HIGH
INERT MATERIAL---- SHOULD BE ADDED
Thanks brother
decomposition rxn is reason and thus requires high temperature
Homework question
Temprature= no change
Pressure= decrease
Inert matrial = at constant pressure should be added
Bond dissociation nahi hoga kya??
@@YashYadav-xq2lh bond dissociation kha se leke a gya
Areyy hoga
@@YashYadav-xq2lh hoga hoga bilkul hoga, endothermic reaction hai
@@Ipshitaaaas tum dbps wali Ipsita ho kya just asking
I am studying in PW offline but although I am watching these old videos of alakh sir❤
1: 07: 37
Temperature = high
Pressure =low
Inert material required at constant pressure
Bruh at 1:07:52 in that question tempr dont given
@@naveensoni5771N2O4->2NO2 mai 100% n2o4 colorless at -11 degree celsius and 100% brown fumes of No2 at 140 degree Celsius so obviously this reaction is endothermic that's why high temperature is favorable.
After five years, still video is relevant. Hats off to the legend.Thanks sir. Never will I ever forget your contribution. 😥😥😓😓
Truly the best lecture on Le Chatelier's Principle
Anshika ?
1:07:02 ans is temperature increase
And pressure decreed and
Const volume =0 and const pressure =forward shifting .
HW answer:
Temperature:high
Pressure:low
Inert material:added
Temp high kese
@@deekshaverma9532 agar temp question mai diya naa ho tb hme temp high leni chahiye...
@@rumki8617 ye compulsory rule h kya?
The respect towards his teaching technique can not be expressed in words.
Watched Amit mahajan sir's lecture, didn't understand much...
Watched Shishir mittal sir's lecture, feel nhi aayii...
Watched Alakh Pandey sir's lecture, concept is now coming into my dreams too.. 😂❤❤ alakh sir OP
Ans of H.W ques:
1. Pressure should be low
2. Inert material should be added at constant pressure
3. Temperature is not defined
Correct👍
Absolutely correct
Correct
temperature is increased as it is a decomposition reaction and forward reaction is endothermic
Perfect
Kml ho giya sir ji
Ur teaching method is too much Awesome keep it sir
All concept clear after hearing ur lecture
I'm from Pakistan 🇵🇰
Bundle of love and great wishing for u from Pakistan 🇵🇰
May Allah bless u with more success in your life
جزاک اللّٰہ 😍
Pakistan ma bhi chemistry padhai jati ha kya😮😮
Home work
Temp- high, ( heat acts as rectant in the decomposition of dinitrogen tetroxide, the reaction is endothermic)
Pressure_low
Inert material -needed with constant pressure
46:50 Those who didn't understand fully . Addition of inert material would increase volume, Hence pressure decreases and we know when pressure decreases , equilibrium shifts towards side with higher no. of moles .
Thanks 🥰👍
thanks man
Who noticed sir's shirt "RISE ABOVE STEREOTYPES" Wowwwwwww❤❤❤❤❤❤❤❤❤❤
Inert material- present
Pressure- low
Temp.- high
How did u get the temp?
@@kermit2676 thank you so much.. for clearing this
Temp. doesn't matter
Temp should be low there as temperature is directly proportional to pressure
Last question answer:
Pressure: low
Inert material: forward
Temprature: no effect
Really that's a halva topic 😂✌️😎,,,BCzzz of you thanks sir 🎉🎈
😁😂🤣🤣
Sir ka favourite dialogue
" Hello baccho,kya haal chaal?
Haaa. Chuha kana band Kar do even is his favourite dialogue.
@@mamathark2547 it's little bit cringy 😬😬
Badhiya ekdum
@@mamathark2547 yes😂😂
@@Thecannibalfrombeyond hao
Guys have u noticed,at 26:00 jo sir ne example dia tha usme reaction ka direction phle forward bataya tha,but after some seconds sir ne usko edit krke backward krdia.?isse ye pta chlta hai sir bhi kbi kbi confuse hote hai.no problem sir hota hai : )
Haan....nice observation haan ...
Bhai wo pressure decrease ka tha phle air bad mein pressure increase ka tha
Sar there is something magic in ur teaching.... Jo apke course ke teacher nhi smjha paye vo apne smjha dia sirji.... Aab chap gya dmg me.... So easy way❤️❤️
Anyone who thinks(must think😉😉😉) alakh sir is the best hit the like button.
I love you
You are so beautifull..
So cutte
Shameless people
@Vladimir Vladimirovich Putin You are right bro, but not all the boys are the same here. I am also a guy but I never do that and yeah i am a fan of PewDiePie.🔥🔥🔥
M also ex allen student
Lekin vaha samjh ne aaya tha
Aapne sari problem he solve kar de sir g thanku
U r really great both as teacher and as a person,although I am teacher but I admit I have learnt a lot of conception in chemistry from ur classes,I am ur fan ....May God bless u and give u enough strength for continuing ur work.
Alakh sir u are genius teacher. I mean chahe physics ho ya chem sare concepts crystal clear kaise kar dete ho hats off to u
Pressure-low
At constant pressure- Inert material addition will increase yield
Temp - High
N2O4 is a stable than NO2 ( Dimer), hence Backward reaction Energy releases - Exothermic therfore low temp is favoured for backward reaction.
But Question is about Forward reaction . Obviously forward reaction is endothermic Hence temp must be high @Aakash Nigam
@@karthikheyaakurra1801 thanks
reaction exothermic h Toh to get more product, temperature should be decreased.....
Right?
@@zebra3260 no it's endothermic so the temperature should be increased
There is one more point
.
.
.
5. The addition of catalyst: it doesn't effect the concentration of equilibrium mixture, as it only increases or decrease the time to attain equilibrium.
As catalyst is inert to the reaction (because it increases the rate of reaction but doesn't itself react with any product /reactant) , it is hence included in 4th point
EXPLAINED IN 2nd LECTURE
@@wildeagle3778 yes
catalyst will always decrease the time to attain equilibrium
@@anusha1586 not ture
it caan affect both ways
Answers of the last question
• Pressure - Should be low
• Temperature - Not given
• Inert material - should be added , which leads to more forward reaction
Sir my name is Farheen .I am from Andhra Pradesh .....I know Hindi..... When I didn't understand any topic then I first prefers your channel only .... because your teaching is amazing.....I really like your teaching.....♥️ I wish this teaching will goes 1000 s of years💐💐💐thank you so much sir ....🥰🥰
Mee to I'm also from Andhra. P and I'm Anjali and I only understand sir ki videos only none of my lecturers can explain like this.😅😊
pressure - low , inert material - high
Temperature ka kya hoga bro
@Pratyush Jha chal chal baap ko mat sikha. Haa haa malum hai
@Pratyush Jha par temperature to de hi nhi rakha h toh fir kese endothermic ya exo
@@NotMixedTape bond break krne k liye heat chahiye hota hai
Alakh Sir always give feel in every lecture💗💗
Thank u Alakh sir
your explaination power about any topic are mind blowing, excellent.
Crystal clear👍👍 amazing lecture... wonderful teacher 👏👏👏
Last question, pressure low , temp high, inert material, forward rxn
1) Temp - increase ( decomposition reaction)
2) pressure - low (eq shifts right , more moles)
3) inert material (const pressure) - required
Temperature increase Kyu karegaaa?
@@RajendraKumar-br9gj decomposition reaction mein heat is required to break bonds so reaction will proceed in forward direction as
N2O4 + ∆ ------> 2NO2
Reaction will proceed in the direction of heat absorption (NO2 production increases) 😊
@Saurabh Mishra see 👆🏻👆🏼👆🏽👆🏾👆🏿
Sir you are not only master of physics
You are also master of physical chemistry😊
One of the best lecture on utube for chatlier's principle...
Lots of love.. Alakh sir.. 🥰🥰
Temperature - Moderate
Pressure - Low
Inert Material - Should be added
Temp moderate no change
Pressure low is opposite to pressure high
His lectures is very useful for bsc students also.
Temp---decrese
Pressure---decrese
Ya I know heat is not given
And even not that it is exo or Endo
But pressure directly proportional ...to temp
And even
Inert material should be added 💖🔥
Thx sir for your love and support 👍
Bro I thought the same thing
Answer of last question:
Production of NO2 can be increased by:
1-By D decreasing the Pressure.
2-By the addition of inert material at constant pressure.
Thanks for your Well explanation sir, love you 🙂🙂
He clear all the concept very beautifully ❤❤❤❤