Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET ||
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Class 11 chapter 7 | Equilibrium | Chemical Equilibrium 01 : Introduction | IIT JEE MAINS / NEET
• Class 11 chapter 7 | E...
Equlibrium | Chemical Equilibrium 02 | Equilibrium Constant Kp and Kc | IIT JEE MAINS /NEET
• Equlibrium | Chemical ...
Equilibrium | Chemical Equlibrium 03 | Law Of chemical Equilibrium Numericals IIT JEE / NEET
• Equilibrium | Chemical...
Equlibrium | Chemical Equilibrium 04 | Degree of Dissociation and Observed density IIT JEE / NEET
• Equlibrium | Chemical ...
Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET ||
• Equilibrium || Chemica...
---------------- IONIC EQUILIBRIUM ------------
Class 11 chapter 7 | Equilibrium | Ionic Equilibrium 01 | Theories Of Acids and Bases JEE MAINS/NEET
• Class 11 chapter 7 | E...
Ionic Equilibrium 02 | Ionisation Constant Of Weak Acid and Base | Ionic Product of Water JEE /NEET
• Ionic Equilibrium 02 |...
Ionic Equilibrium 03 || PH Of Solutions | How to find PH | How to calculate PH of any Solution
• Ionic Equilibrium 03 |...
Ionic Equilibrium 04 || Common - Ion Effect IIT JEE MAINS/ NEET ||
• Ionic Equilibrium 04 |...
Equilibrium | Ionic Equilibrium 05 | Buffer Solutions JEE MAINS/NEET /JEE ADVANCE -Part 1
• Equilibrium | Ionic Eq...
Equilibrium | Ionic Equilibrium 06 | Buffer Solutions JEE MAINS/ NEET/ JEE ADVANCE -Part 2
• Equilibrium | Ionic Eq...
Ionic Equilibrium 07 || Salt Hydrolysis IIT JEE MAINS / JEE ADVANCE / NEET || pH of Salts
• Ionic Equilibrium 07 |...
Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET ||
• Ionic Equilibrium 08 |...
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2)Live Classes and recorded Video Lectures (New, different from those on TH-cam)
3)PDF Notes of each class.
4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.
5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.
6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
7)In case you missed a live class, you can see its recording.
8)You can view the videos any number of times.
9)Each chapter will be discussed in detail with all concepts and numericals
10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.
****Test Series for XI & XII****
We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.
Class 11 chapter 7 | Equilibrium | Chemical Equilibrium 01 : Introduction | IIT JEE MAINS / NEET
th-cam.com/video/sCUgeC5ACv8/w-d-xo.html
Equlibrium | Chemical Equilibrium 02 | Equilibrium Constant Kp and Kc | IIT JEE MAINS /NEET
th-cam.com/video/oyr7q5BrGEA/w-d-xo.html&pbjreload=10
Equilibrium | Chemical Equlibrium 03 | Law Of chemical Equilibrium Numericals IIT JEE / NEET
th-cam.com/video/z2G52O_7nd4/w-d-xo.html
Equlibrium | Chemical Equilibrium 04 | Degree of Dissociation and Observed density IIT JEE / NEET
th-cam.com/video/x13K19_JwgY/w-d-xo.html
Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET ||
th-cam.com/video/NVZ4Jb9tLX4/w-d-xo.html
----------------- IONIC EQUILIBRIUM -------------
Class 11 chapter 7 | Equilibrium | Ionic Equilibrium 01 | Theories Of Acids and Bases JEE MAINS/NEET
th-cam.com/video/Uql1eQGq9Dg/w-d-xo.html
Ionic Equilibrium 02 | Ionisation Constant Of Weak Acid and Base | Ionic Product of Water JEE /NEET
th-cam.com/video/Dgdz6bfRMdc/w-d-xo.html
Ionic Equilibrium 03 || PH Of Solutions | How to find PH | How to calculate PH of any Solution
th-cam.com/video/uuGl5o8b3Zk/w-d-xo.html
Ionic Equilibrium 04 || Common - Ion Effect IIT JEE MAINS/ NEET ||
th-cam.com/video/xqq78GsLXSA/w-d-xo.html
Equilibrium | Ionic Equilibrium 05 | Buffer Solutions JEE MAINS/NEET /JEE ADVANCE -Part 1
th-cam.com/video/KH0w5TZnJaA/w-d-xo.html
Equilibrium | Ionic Equilibrium 06 | Buffer Solutions JEE MAINS/ NEET/ JEE ADVANCE -Part 2
th-cam.com/video/30eFAm74wp0/w-d-xo.html
Ionic Equilibrium 07 || Salt Hydrolysis IIT JEE MAINS / JEE ADVANCE / NEET || pH of Salts
th-cam.com/video/I33BwmAz1sY/w-d-xo.html
Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET ||
th-cam.com/video/1tRdbmroncE/w-d-xo.html
Chuha kon khata h sir😁😁
@@mitanshrathi855 tum😂😂😂🤣🤣🤣
@@partha3322 app kon
@@mitanshrathi855 Don😎😎😂😂😂
sir reaction quotient pr bna do video
For the last Question,
N204 = 2N02;
1)Temp = Since, its a decomposition reaction [DIMER - MONOMER] heat should be supplied to it, which means It is ENDOTHERMIC, there temp should be high
2)Pressure = should be lower as, high pressure means eq. shifts towards lower mole side
3)Inert material = should be Added as, eq shifts to the side having more moles of substance
Yes,,i got the same but got confused in temp
@@sumantraks7639same
but while adding inert material pressure should be constant but here we already decreased the pressure
Correct...Thanks for confirming
You are correct
Ans for the last question:
Pressure = low
Inert material should be added.
Is it exo or endo, it,s not mentioned in the equation , so, temp isn't defined.
It is decomposition reaction...so heat should be supplied to break the compound...this information will most likely be not given in the question, so you have to know it...hope this helps
N2O4 is being converted to NO2..
Dimer to monomer ..i.e. heat has to be supplied which implies forward direction reaction is endothermic.
Hence increasing the temperature will yield more NO2
u r right
Yes I was confused here...
@@hawkhcr2445 thanks dude...has this question in my mind 👍
I am watching this video after 5years (2023) full crystal clear concepts explain by sir (salute)
khatarnak bhai hai ALAKH SIR
Effect of:
Conc- 11:42
Pressure- 18:29
Temp- 31:16
Inert Material- 42:35
Thanks sis
Thanks sis
Thank you
You rocked
@@havishbalaga9397 how u know person is female???? 🐶
Sir hamara toh 12th khatam ho gaya lekin aap jo kar rahe ho woh laakho ki zindagi badlega yeh tution walle ne sab cheezo ko apna buisness bana rakha hai zyaada aur education kam...aap jo karr rahe ho wohh karte rehna pls rukna matt aapko saari tution industry ko karara jawab dena hai aur unko batana hai that education is same for all wheather a person is average or class topper
You are absolutely right
Vandit Vasoya that “expensive internet” would still be cheaper than what tuitions and coachings cost. Also, 600 dollar for 10 minutes.. yeah that’s an absolutely made-up number. Even the biggest youtubers on the platform don’t get paid that much. So please, do some research before you spew absurd statements
Chupp bee
Aisa nahi bolnaa
Well done .your thought is 100% correct
Answer for the last question...
1) Increase the concentration of N2O4
2) high temperature is required
3) Low pressure is required
4) addition of inert material at constant pressure is also required...
Thank you sir, you are doing a great job...
Bilkul shi bachaa..correct answer temp wala concept explain kro
Temperature increases hoga hi nhi other wise everything is correct except temperature vala factor
Temp. Except all correct
I also have the same answer....😎
@@shaikhumer662 yes u are right temperature is not mentioned in the question.
I am watching this video after 3 yrs . I must say that this man is genius . I have never seen a teacher even in coachings also who can teach both physics and chemistry with so much fun and feel . I wonder that how this video got 728 dislikes
dont wonder , go do your work
By the other coaching.
Me too.. 😂😂
@@anmol.1338 instead of responding go do ur work
Bro u are watching this video for last 3 years but unfortunately u didn't learn that's why u are watching this video continuously couples of years 😅😅
Just kidding 😂😂
Sir I love your T-shirts 😂 "Rise above Stereotypes" ✌️✌️
What about his knowledge??
@@MohammadAsif-dh7ik wo toh under stood hai
I want a stock of sir's t shirts... Especially that light dogla hai one...😂😂
@tricky ishu escape velocity wala mein kya likha hein??
@tricky ishu yup...😂😂
Temperature : High (since it is an endothermic reaction although not mentioned)
Pressure: Low
Inert material : we will use as it shifts the equilibrium forward towards more no of moles.
How do you know that it is an endothermic rxn
Ho w did u get the temp hidh
It is #DecompositionReaction and also N2O4 is a dimer of NO2.
Temp= high
Pressure= low
Inert material is required at constant pressure
Aap ko kasa malum hua ka ya decompostion reaction hh plzz bata do mako sab ka ans mil gaya par temp. ma samj nahi aarha hh
Search it on google yaar ....,mostly it would be given in question
commando offical At 1:01:10 sir stated that if no delta H is given, the reaction is forward.
So in order to increase the production of NO2 temperature has to be increased.
Temp kyun high chahiye
@@bijitdas208 Yes,here we don't know either it is exothermic or endothermic,so go by the basic thumb rule.....that is on high temp molecules will gain kinetic energy hence the molecules can easily collide with each other thus resulting NO2....
or do generally consider it to be endothermic
[PLEASE DO CORRECT ME IF IAM WRONG]
There is one more point
.
.
.
5. The addition of catalyst: it doesn't effect the concentration of equilibrium mixture, as it only increases or decrease the time to attain equilibrium.
As catalyst is inert to the reaction (because it increases the rate of reaction but doesn't itself react with any product /reactant) , it is hence included in 4th point
EXPLAINED IN 2nd LECTURE
@@wildeagle3778 yes
catalyst will always decrease the time to attain equilibrium
@@anusha1586 not ture
it caan affect both ways
Me every time “lechatle” principle 😂😂
😂😂
😂😂😂
👌👍😝
Ssme
Same
Alakh sir teaches chemistry extremely good... i almost forgot that his name actually is physics wallah
Oh wow!
Good one!😂
His name actually is ALAKH SIR
So true me too😁
Are unka naam alakh pandey hai.unke channel ka naam physics wallah hai
Ans.
temperature should be high as it is a decomposition reaction.
pressure should be low.
inert material should be added at constant pressure.
Same ans
Same
@@princejagane7008 temp kyu high karenge
+Gaurav Jain kyu ki reaction ko forward direction me le Jana hai or NO2 form krna hai
Same ans
1:07:46
N2O4 2NO2
Temp : High (Cuz bond breaking..i.e endothermic)
Pressure: Low
Inert material: Should be added
सर आप तो केमिस्ट्री और फिजिक्स दोनों के प्रोफेसर हैं 😯😯😯✌️😚🇮🇳🔥❤️
The person who disliked this video please remove it ,,,,,,,,,,,please like it ,,,it's request from physics walla channel followers😈😈😈😈😇😇😇😇
bhavya j you are right . my favorite channel neet or board
CBSE ke li.
@@dr.vaishnavisharma7298 jee k liye bhi
bhavya j yes me toh only board or agri BSC ki prepare best of luck . good night sweet dreams
Exactly..
Sir aap ionic equilibrium ka video kab tak banaoge
Plz answer me
1)Exothermic kee liye-temp low
Endothermic ke liye temp High
2) pressure-low
3)inert material
1) constant vol no effect
2) constant pressure
Pressure low
Inert material: Const Volume no effect
Constant Pressure
Temperature I am confused sir.
Thank you
After 5 years also this video is a boon ❤
Exactly 💯
Truee
answer of homework question
PRESSURE ----- PRESSURE SHOULD BE LOW
TEMP----- TEMPERATURE SHOULD BE HIGH AS ENERGY IS REQUIRED TO BREAK BOND --- N204 IS DIMER OF NO2 AND ENERGY IS REQUIRED TO BREAK THE N---N BOND SO THE RXN IS ENDOTHERMIC AND TEMP SHOULD BE HIGH
INERT MATERIAL---- SHOULD BE ADDED
Thanks brother
decomposition rxn is reason and thus requires high temperature
Stay blessed sir( From Pakistan)
Me too bri❤
Here's Pakistan 🎉
Huge respect for this extraordinary personality his lectures are mind-blowing
Army 💜
@@sathvikachowdary3752 💜💜💜
12 nahi sir 11th ka hona
Pressure=low
Inert material should be added
Temp exo or endo not mention in this equation
Yeah....pre low
Inert material added...
And for tem not mention reaction is exothermic or endothermic...
right
But due to increase in temp the production should have been increase right
Temp:- not defined cuz it's not that reaction is endo or exo.
Pressure :- low
Inert gas should be added.
*Sir aap hum bachcho ke liye vardan ho.* 🙏🏻🙏🏻😁😁
Reaction endothermic hogi na....kyu ki bond break ho rhe h......!
Or hume energy deni pdegi(endothermic) bond break krane k lie.....
Hence to favour endothermic reaction we hv to Inc the temperature..
🙋🏼♂️🙋🏼♂️
Hey but if we increase the temp pressure also rises n if pressure increases the equilibrium shifts backward so we can say that the conditions are:
Low temp
Low pressure
Addition of inert gas
yes exactlly
@@neerajmistry9279 I think you are right
Pressure ke low kese last baale questions ka ,
Best lecture on Le- Chatelier's Principle you'll find on youtube 😊👍👍👍👍
Ans of H.W ques:
1. Pressure should be low
2. Inert material should be added at constant pressure
3. Temperature is not defined
Correct👍
Absolutely correct
Correct
temperature is increased as it is a decomposition reaction and forward reaction is endothermic
Perfect
Alakh sir teaches really good.
His videos helped in building concepts for mdcat and were helpful in cracking it.
Respect from Pakistan 🇵🇰
hi brother in which med clg are you ?
11:08 Sir hum to forever ready hain aapke sath antakshari khelne ke liye bas aap live aa jao😅
1. Pressure - Decrease
2. Temperature - Increase ( because it is an endothermic reaction with ∆H = +57)
3. Inert Material - It should be added.
Temperature increases
Decomposition reaction is endothermic..not exo-
@@hawkhcr2445 Thank you bhai.👍👍
MCQth-cam.com/channels/F5ie8yBPVZxVAhx8jKWxtg.html
Bhai kaise pta Chala ki ye endothermic reaction h
Guys have u noticed,at 26:00 jo sir ne example dia tha usme reaction ka direction phle forward bataya tha,but after some seconds sir ne usko edit krke backward krdia.?isse ye pta chlta hai sir bhi kbi kbi confuse hote hai.no problem sir hota hai : )
Haan....nice observation haan ...
Bhai wo pressure decrease ka tha phle air bad mein pressure increase ka tha
No change in temperature would be required as the reaction is not endothermic or exothermic
By decreasing pressure
By adding inert material
Sir, you are a great teacher in the world.And you have proved that old is gold.Your old videoes help me a lot .
Thank you sir 🙂🙂🙂
👍😊😊😊
diksha aap instagram chalate ho??
@@UpscLover-AB420 HI brother 😊👍
Same ❤
@@epicshorts8076 yes😇
These videos can never be got old.
After 3 years.........
Thank you very much sir🙏🙏🙏🙏🙏🙏
relatable
😄😄
after 4 years bro😁😁
@@अंशुलउज्जवलकर mai bhi
Koi kaha se hai kiuna parlo selection hoga to shirf Alakh sir video se hi.
It will never get old till 1000s of years
11:58 i) concentration
ii) 18:02 Change in Pressure
iii) 31:20 Chnage of Temperature
iv) 44:39 Addition of inert
This channel is literal the best for chemistry and physics . Love this
Well... There are many intro sounds nowadays
But alakh sir's intro sound is the best of them all
U are the best teacher I have ever met in my life...u r just awesome and your examples just strike on my mind in few micro seconds😎😂 hope that meet u soon...lots of love alakh sir😍
Which college?
Answer is
Pressure low
Yes inert material should be used
No think about temp because there is no heat relevant information
After five years, still video is relevant. Hats off to the legend.Thanks sir. Never will I ever forget your contribution. 😥😥😓😓
1:07:02 ans is temperature increase
And pressure decreed and
Const volume =0 and const pressure =forward shifting .
High temp
As this reaction is endothermic in forward direc
Low pressure
Yes inert material dalna haii
Hats off to you sir... You are inspiration for millions.. one day i will also become successful and will definitely help those in need whether economically or through teaching free of cost just like you..
I usually understand this principle by using the " Mad man method " where it is said that mad man will do the opposite you do..
You increase pressure, mad man tries to decrease it, he goes there..
You increase conc., mad man tries to decrease it, he goes to less moles...
You increase temp. , mad man tries to decrease it, he goes to less temp. system...
like that it can be easy..
Nice sir 👍
@@tunseducation2561 great 👏,Bangladesh er kothai bari vii?
Great trick its made my day ❤
1) Temp - increase ( decomposition reaction)
2) pressure - low (eq shifts right , more moles)
3) inert material (const pressure) - required
Temperature increase Kyu karegaaa?
@@RajendraKumar-br9gj decomposition reaction mein heat is required to break bonds so reaction will proceed in forward direction as
N2O4 + ∆ ------> 2NO2
Reaction will proceed in the direction of heat absorption (NO2 production increases) 😊
@Saurabh Mishra see 👆🏻👆🏼👆🏽👆🏾👆🏿
Anyone who thinks(must think😉😉😉) alakh sir is the best hit the like button.
I love you
You are so beautifull..
So cutte
Shameless people
@Vladimir Vladimirovich Putin You are right bro, but not all the boys are the same here. I am also a guy but I never do that and yeah i am a fan of PewDiePie.🔥🔥🔥
Like to respect ALAK SIR .👍
.
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.👍
Sir Temp Not Defined
Inert material add
Pressure Low
Correct ✅
Sir temp. should be high
Pressure should be low
Inert material at cons. pressure should be added
Can you tell me about the temperature?..i am confused bacause sir ne toh temp mention hi nahi kya....please help me?
@@Rohitsharma-wy8nt Shi bhai
@Shyamala Sundari ....thank you...where are you from?
@@Rohitsharma-wy8nt tharki to puro sa bhai koi choro hogo dekh liye pahlya..... M to mere bhai n salah de rya su.....😋😋
Yes I hope That's correct Even I thought that..👍
Thank you soo much Alakh Sir for making Le Chatelier's Principle so crystal clear!Hats off to you Sir!Lots of Love and Respect...👏😎👌👌🤓😌🙏🙏😎😁😉
Watched Amit mahajan sir's lecture, didn't understand much...
Watched Shishir mittal sir's lecture, feel nhi aayii...
Watched Alakh Pandey sir's lecture, concept is now coming into my dreams too.. 😂❤❤ alakh sir OP
Temp not defined
Pressure low means high vol therefore no of mole production high
Inter gas c vol no effect
And c pressure more no of moles therefore in the forward direction sir❤
Temperatur should ne high because atoms will vibrate faster and wil collide
Sir doesn't need to tell people to like the video, we automatically after watching it like it immediately
IT IS NOT ONLY PHYSICS WALLAH BUT ALSO CHEMISTRY WALLAH
*TEACHER*- *Le -Chatelier's principle*
*ME*- *Le chat le re ye principle*
The same thing we say this in school 😂😂😂
But le chaat le yarr 😅😅
Yup same me also says this
Haha😇 same in my school
arre bhai...tujhe kaise pta...mai bhi ise...le chaat le principle bolta hu😂
Ha chata khub chata apni principal ko😂😃
sir poore you tube pe kyaaa aap jaise teacher poore desh duniya mei ginee chunee hotey hai aap ke andar josh aur jazbaa hai aaap karate hai concepts ko crystal clear ...!! may god bless you. your each and every lucture's explanation is awesome..aapse padhkar physics aur chemistry se har student ko pyaar ho jayee agar kisi bhi bacche ko aapse naa smjh aaye tohh wo phir mann buddhi hai...you are one of the best teacher in the world🤩👍 aapko bharat ke bacho jaur usse jude uske padosi desh kee bacho ki dil se dua nikalti hai may you acheive more success in your life ...!! stay happy and healthy ...!! and stay the same sir as you are thank uh so much...!!😊 jitni tareef karein aapki utni kam hai hai you are the best teacher...!! thankss alakh sir😊💖
Inert material
Constant pressure forward
i am blessed to find this channel. i dont have words to thank u sir.
th-cam.com/video/pP04V0d_QbI/w-d-xo.html
Same here 😌
Same with me . I am so lucky to got this channel.
Hi
@@pranjulkumar3999 tere se puchi kisi ne?
Sir ka favourite dialogue
" Hello baccho,kya haal chaal?
Haaa. Chuha kana band Kar do even is his favourite dialogue.
@@mamathark2547 it's little bit cringy 😬😬
Badhiya ekdum
@@mamathark2547 yes😂😂
@@Morningstarintheroses hao
38:16 sir has committed mistake there, as in habers process the forward reaction is exothermic and not endothermic so low temp is favorable instead of high temp.
1. Temprature high (bcz : N2O4 do heat absorb than convert in NO2)
2. Pressure low
3. Inert material was like advantage for this reaction 🙏...
..........🙇 Tx so much sir 🙇..........
.....🙇for solve all type of doubts🙇.......
Dislike krne wale wo teachers hai jo itta accha kbi padha nhi payenge..jlte h sb.
teachers are teachers u cant insult them
@@rushilboligarla6955 chutia sala
@@rohitmohammad9074 gaali mat de
@@_shailendra27_ you are partially right
@@rushilboligarla6955 chal whanru
Last question, pressure low , temp high, inert material, forward rxn
For last question ∆H= 58 Kj/mole
Ans= N2O4 add,p low,T high,in constant p inert materials should be added.
Pressure-low
At constant pressure- Inert material addition will increase yield
Temp - High
N2O4 is a stable than NO2 ( Dimer), hence Backward reaction Energy releases - Exothermic therfore low temp is favoured for backward reaction.
But Question is about Forward reaction . Obviously forward reaction is endothermic Hence temp must be high @Aakash Nigam
@@karthikheyaakurra1801 thanks
reaction exothermic h Toh to get more product, temperature should be decreased.....
Right?
@@zebra3260 no it's endothermic so the temperature should be increased
Sir, I am studying bsc however I am watching your videos to solve my doubts and concept.....
Thank you so much physics walhaa
yrr BSc me kuch ni h koi concept ni bante...isse acha toh Btech krlo knowledge to banti h aur technical knowledge badh jati h
I am from same course there's no scope
Favorable conditions for the last reaction :-
1 : By increasing the concentration of [N2O4] or by removing [NO2]
2 :Pressure should be low
3 :Can't define temperature
4: at ∆P=0 then forward reaction (which will not help in increasing the production )
Right 👍
Sir aapne to kaha tha ki inert gases ko add krne se koi change nhi aata
M also ex allen student
Lekin vaha samjh ne aaya tha
Aapne sari problem he solve kar de sir g thanku
Alakh pandey is the best teacher for physics as well as chemistry amongst all the teachers I have seen so far 🤗🤗🤗
What is ur opinion guys 🤔🤔
The amount of views on his videos obviously tell that
I am agree with you bro☺☺☺
Absolutely🙌😎
I am also a FF player
Actually physics lectures' questions are pretty hard which definitely is an issue with my IQ but concept wise i feel he has benefited me A LOT in Chemistry than physics. In a nutshell , he's definitely one of the best teachers on TH-cam platform.
1:07:45 - Sir, i) Temp. decrease karenge kyunki, increase karne se reaction backward jayega { since, np > nr }, jo hume nhi chahiye. Pressure decrease karenge kyunki phirse reaction warna backward jayega { since, np > nr }, nhi chahiye. Inert material daalna parega taaki reaction forward jaaye { since, n of NO2 > n of N2O4 }, wahi chahiye.
Temp kyun decrease karna sir ne heat/temp ke bare me kuch mention hi nahi kiya he ki ye endothermic ya exothermic he
@@ksuhanidas3226 Arrey sir ne temp., pressure aur inert material ke baare pucha he, to Maine bata diya to, ha bas bola he ki conc. to hum bata denge kyunki easy he to woh mana kiya he
@@arpitsuman4010 haan thik he par sir ne question me mention nahi kiya he ki ye kis type ka rxn he
Toh I think temp constant rahega
@@ksuhanidas3226 N2O4 is breaking into No2 it's a decomposition reaction hence endothermic
Heat is required to break N2O4
@@memeboii1493 okay I agree👍
Sir the answer of the last question :
Low pressure
Addition of inert gas
And temperature is high
I learnt this chapter so perfect by seeing your lectures sir...we're paying alot on tution and actually learning from you without anything..
Last question's answer :- HIGH TEMP , LOW PRESSURE, INERT GAS AT CONSTANT PRESSURE
1:07:46 For maximum yield of NO2
Pressure - low
And inert gas should be added
And temperature???
Home work
Temp- high, ( heat acts as rectant in the decomposition of dinitrogen tetroxide, the reaction is endothermic)
Pressure_low
Inert material -needed with constant pressure
Homework question
Temprature= no change
Pressure= decrease
Inert matrial = at constant pressure should be added
Bond dissociation nahi hoga kya??
@@YashYadav-xq2lh bond dissociation kha se leke a gya
Areyy hoga
@@YashYadav-xq2lh hoga hoga bilkul hoga, endothermic reaction hai
@@Ipshitaaaas tum dbps wali Ipsita ho kya just asking
Exceptional teaching style sir...best teacher of physics and chemistry ever...especially for classes 11th and 12th..🙏🙏❤❤
Watchth-cam.com/channels/F5ie8yBPVZxVAhx8jKWxtg.html
I have seen very few teacher which revise all topic which they explain and Alakh Sir is one of them.
Forward direction
Inert material- present
Pressure- low
Temp.- high
How did u get the temp?
@@kermit2676 thank you so much.. for clearing this
Temp. doesn't matter
Temp should be low there as temperature is directly proportional to pressure
Pressure low
Temperature should be high
Addition of inert material at constant pressure
Bro i think temp. Should low acc to
Pv= nrt p is directly proportional to t so if p decrease so T must be decreases
thankyou sir, mujhe chemical equilirium kabi samaj me nahi aata tha par ab mera sara consept clear ho gaya
Last question answer:
Pressure: low
Inert material: forward
Temprature: no effect
Temp should be high bcoz this is decomposition reaction.
Pressure should be low.
And inert material should be added at const. Pressure
Our True HERO Sir Alakh Panday😊😊 ... Respect and gratitude from Pakistan
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PKMKB
@@bakaraaprasad4952 hii
1: 07: 37
Temperature = high
Pressure =low
Inert material required at constant pressure
Bruh at 1:07:52 in that question tempr dont given
@@naveensoni5771N2O4->2NO2 mai 100% n2o4 colorless at -11 degree celsius and 100% brown fumes of No2 at 140 degree Celsius so obviously this reaction is endothermic that's why high temperature is favorable.
Temperature high
Presure low
Inert material at constant pressure
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Yes bro 🤜🤜🤜🤜🤜 you are right
there is no effect of temp.
the reaction is preferred at low pressure
addition of inert material will result in more productivity
.
.
thank you
Sir Ji, pressure should be low,
Inert material should be added at const. Pressure,
And Temp. Should be high...
is this exothermic or endothermic? u ve nt given
An extremely intelligent teacher who cleared all my queries regarding this chapter - Respect from Pakistan 🇵🇰
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Sir for N2O4=2NO
Pressure Should be low
Temperature Should be High
Inert Material for constant Pressure should be added..
Last question answer
Temp- Not given
Pressure - At low pressure
Inert material required for yield of the reaction
I am studying in PW offline but although I am watching these old videos of alakh sir❤
Temp-high(endothermic)
Pressure-low
Inert material should be added
👍👌
How to know that this reaction is endothermic 😶 or where heat is being added ?
@@prakharsingh5111 n2o4 ka bond break hoga uske liye bond dissociation energy deni padegi isliye endothermic 😅😊
Temp---decrese
Pressure---decrese
Ya I know heat is not given
And even not that it is exo or Endo
But pressure directly proportional ...to temp
And even
Inert material should be added 💖🔥
Thx sir for your love and support 👍
Bro I thought the same thing
Great explanation easily understood!!