I am an Engineering student and love the way you explain tough concepts easily. I could not understand it in my classes and now with the help of yours it has became so easy. Love your videos very much sir. Please continue the good work.
@Fernando Yael and u know what dude.. i saw the very same comment in some other video and somehow same reply by somebody who's either your friend or better say your other id, saying that it works... And someone had pointed this out there too.. so just stop doing this foolish act.. noone cares ..not even about your lies.. now FO!!
Bahut bahut dhanyawad sir, 2002 me instrumentation engineering me kabhi samajh nahi aaya, lekin aaj aap ki videos dekh kar bahut kuch aasani se samjh aa gaya
Sir hume aaj tk aapke jaisa teacher nhi ..milaa .. sir .. aapke liye mere pas vo word nhi dictionary me. ..jisse aapka sukriyaada kru.........👌👌👌👌👌👌🙏🙏🙏🙏🙏🙏
I have done my diploma in electrical engineering in 2020. But I did not clear my basic electronics doubt when I saw your classes everything clear . Thank u so much sir . I got clarity in my doubts.
Case 1: Vi < 0.7 V When the input voltage (Vi) is less than the threshold voltage of 0.7 V, the base-emitter junction is reverse-biased, and the transistor is essentially turned off. In this case, both Ib and Ic are approximately zero, and the transistor acts like an open switch. The voltage drop across the collector-emitter junction (Vce) is equal to the supply voltage (Vcc). Now, suppose we gradually increase Vi. As Vi increases, the base-emitter junction becomes increasingly forward-biased, and the transistor begins to turn on. The base current (Ib) starts to flow, which in turn causes the collector current (Ic) to flow. As Ic increases, the voltage drop across the collector-emitter junction (Vce) decreases, according to the formula Vce = Vcc - Ic*Rc. Eventually, at some Vi value above 0.7 V, the transistor enters the active region, where it is able to amplify the input signal. In this region, the collector current is proportional to the base current, and the voltage drop across the collector-emitter junction is much smaller than Vcc. Case 2: Vi > 0.7 V When the input voltage (Vi) is greater than the threshold voltage of 0.7 V, the base-emitter junction is forward-biased, and the transistor is turned on. In this case, both Ib and Ic are nonzero, and the transistor acts like a current amplifier. The voltage drop across the collector-emitter junction (Vce) is given by the formula Vce = Vcc - Ic*Rc. Now, suppose we gradually decrease Vi. As Vi decreases, the base-emitter junction becomes less forward-biased, and the transistor starts to turn off. The base current (Ib) decreases, which in turn causes the collector current (Ic) to decrease. As Ic decreases, the voltage drop across the collector-emitter junction (Vce) increases, according to the formula Vce = Vcc - Ic*Rc. Eventually, at some Vi value below 0.7 V, the transistor enters the cutoff region, where both Ib and Ic are negligible. In this region, the voltage drop across the collector-emitter junction is equal to Vcc, and the transistor acts like an open switch.
Thank you so much sir.. i see many videos on this topic.. but you are the one that diffentiated between the input voltage and the barrier potential.. most of rhe time many take Vbe as the input potential.. Making so much confusion.. hatts off to sir..👍👍👍
Thank you sir i have searched the whole youtube on forward and reverse baisee but couldn't visualise it but then i saw your video and got it clearly sir
sir, we take v input Vbb and then we take Vbb as .7v but for breaking the barrier potential we want Vbe as .7v not Vbb 🧐i.e the potential across the junction should be equal to the barrier potential.
Sir bjt as switch me power electronics me btate hai ke current collector to emitter flow hota hai saturation me par base current ko kyu nhi consider krte collector current to base aur emmiter dono me flow hota hai
There are so many physics teachers on youtube but no one is not having clarity in concept like you !
Hats off to u sir for your dedication:)
Pranav sharma vai dil ki baat bol di
I am an Engineering student and love the way you explain tough concepts easily.
I could not understand it in my classes and now with the help of yours it has became so easy.
Love your videos very much sir.
Please continue the good work.
I am From Bangladesh, you are such a brilliant teacher.. And your every class is mind blowing.... 🥰🥰🇧🇩🇧🇩🇧🇩🇧🇩🇧🇩
Hi I'm Bangladeshi from puran Dhaka..
@@ব্যাঙএরছাতা me also from
Bangladesh 🙂
Me tooo
Me too from notre dame college, Dhaka🇧🇩🇧🇩🇧🇩
Congratulations Ur GDP per capita is more than our shiiiuut holll country india
Tough se bhi tough concept ko aap easy bana dete hai sir . Thank you so much🙏
Transistor as an *Oscillator* plzz
Hit like 😎
i think damped oscilator
@Fernando Yael and u know what dude.. i saw the very same comment in some other video and somehow same reply by somebody who's either your friend or better say your other id, saying that it works...
And someone had pointed this out there too.. so just stop doing this foolish act.. noone cares ..not even about your lies.. now FO!!
@Fernando Yael it's a scam
I am from pakistan I have never seen such a conceptual teacher in my life ur way of teaching,Great teacher...
Im *PAKISTANI*
Ur Way Of Teaching Is Full Of Clearity...
*JAZAKALLAH*
Alhamdulillah ❤
apke sllybus me bhi ye hai kya👏
I also
@rahug bahi sab kuch haljpv123
From u r teaching i got 98/100 in an lab experimental test thank you❤️
You are best for me. Kyu Ki aap tough Se tough concept kaphi aashni Se batla dete hai. Thanks sir.
Bahut bahut dhanyawad sir, 2002 me instrumentation engineering me kabhi samajh nahi aaya, lekin aaj aap ki videos dekh kar bahut kuch aasani se samjh aa gaya
Dhoni of Physics😉....Cool and Calm...but so muchh affective
Sir hume aaj tk aapke jaisa teacher nhi ..milaa .. sir .. aapke liye mere pas vo word nhi dictionary me. ..jisse aapka sukriyaada kru.........👌👌👌👌👌👌🙏🙏🙏🙏🙏🙏
Sir,
Seriously aap critical bate bhi badi asani se samjhate h
Really you are a great teacher
Please introduce load line & q point also
I have done my diploma in electrical engineering in 2020. But I did not clear my basic electronics doubt when I saw your classes everything clear . Thank u so much sir . I got clarity in my doubts.
No problem Sir.
Case 1: Vi < 0.7 V
When the input voltage (Vi) is less than the threshold voltage of 0.7 V, the base-emitter junction is reverse-biased, and the transistor is essentially turned off. In this case, both Ib and Ic are approximately zero, and the transistor acts like an open switch. The voltage drop across the collector-emitter junction (Vce) is equal to the supply voltage (Vcc).
Now, suppose we gradually increase Vi. As Vi increases, the base-emitter junction becomes increasingly forward-biased, and the transistor begins to turn on. The base current (Ib) starts to flow, which in turn causes the collector current (Ic) to flow. As Ic increases, the voltage drop across the collector-emitter junction (Vce) decreases, according to the formula Vce = Vcc - Ic*Rc.
Eventually, at some Vi value above 0.7 V, the transistor enters the active region, where it is able to amplify the input signal. In this region, the collector current is proportional to the base current, and the voltage drop across the collector-emitter junction is much smaller than Vcc.
Case 2: Vi > 0.7 V
When the input voltage (Vi) is greater than the threshold voltage of 0.7 V, the base-emitter junction is forward-biased, and the transistor is turned on. In this case, both Ib and Ic are nonzero, and the transistor acts like a current amplifier. The voltage drop across the collector-emitter junction (Vce) is given by the formula Vce = Vcc - Ic*Rc.
Now, suppose we gradually decrease Vi. As Vi decreases, the base-emitter junction becomes less forward-biased, and the transistor starts to turn off. The base current (Ib) decreases, which in turn causes the collector current (Ic) to decrease. As Ic decreases, the voltage drop across the collector-emitter junction (Vce) increases, according to the formula Vce = Vcc - Ic*Rc.
Eventually, at some Vi value below 0.7 V, the transistor enters the cutoff region, where both Ib and Ic are negligible. In this region, the voltage drop across the collector-emitter junction is equal to Vcc, and the transistor acts like an open switch.
such a great teacher. explained every single concept in great way.
sir amazing lecture ncert ke topic jo grasp nahi kar sakte wo ab crystal clear ho gaya hain thank u so much sir
One of the best videos I have ever seen
Literally..u have a great knowledge of the topic..
kaur ?
Sir, this is out of syllabus for us in this year. Still I am learning from you because your lectures are awesome.
Sir we respect your journey to teaching
Thank you so much sir.. i see many videos on this topic.. but you are the one that diffentiated between the input voltage and the barrier potential.. most of rhe time many take Vbe as the input potential.. Making so much confusion.. hatts off to sir..👍👍👍
Best video on transistor as a switch
Thankyou so much sir !!
Wakai bohat ache se bataya h
Alakh sir semiconductor pura ni padhaye tabhi ham yaha aaye hai .........its also good
Thankyou so much uh explained it in the best way !!!
What an explanation so nice.... U made me understand the whole concept... God bless u🙏🙏🙏🙏
Assalam u alikum please sir teach us omp as comparator because our board exams are near.Your teaching method is excellent
Really thank you sir for giving best lecture on transistor....you are the best teacher of physics...🙏🙏
So helpful Sir....
I love ur all videos sir
Ur teaching skills are amazing 🤩
You are best teacher genius
MANY MANY THANX TO U...EXPLAINED IT SO NICELY
Starts from 4:00 who knows basic
Simple and easy explanation
It helped me a lot 🙏🏻
Than you so much 👍🏻
This explaination realy helped...thank you sir
Concept crystal clear ho gy sir thanks a lot 😍
Sir awesome explanation. First of all your voice is awesome and also you have explained this concept in such an easy way. Love you sir.
After watching videos for nearly 2 hours this video cleared the concept in 20 mins😂❤
I am from Bangladesh, Nice explanation...
Really ur great teacher...
It's a good explanation but if you putt any device instead of resistance then it will be better understood by everybody
Please upload more before my exams!
Very helpful video, Thanks
Thank you sir i have searched the whole youtube on forward and reverse baisee but couldn't visualise it but then i saw your video and got it clearly sir
Thank you sir.. awesome video hai.🖤🖤🖤
Sir please make video on
Transistor as a amplifer
Really sir kya gazab ka padate h app
You are life saver ☺️ 🙏
Great way of teaching
world's best illustration on that topic...... 🙏🙏🙏🙏
Physics become easier after watching ur video
True I agree that he explains with detail by the way are you on instagram
sir, we take v input Vbb and then we take Vbb as .7v but for breaking the barrier potential we want Vbe as .7v not Vbb 🧐i.e the potential across the junction should be equal to the barrier potential.
But sir not take VBB as 0.7 V
VBB is always greater than VBE(voltage drop)
sir pls make video on power amplifiers
Best teacher ever thanks a lot 🙏🎉🎉🎉🎉🎉❤️❤️❤️
😀Thank you sir🙏🙏
Sach keh raha hu me...Allen ke teachers se acha explanation he sir ka..Me allen me hi hu..
Sir your explanation is very good
Sir transistor as a current source par bhi lecture banao
Sir breadbord pr practical krwa dete to clear ho jata .thanks
Thanks sir
Made it easy
Sir plzz upload transistor as a amplifier and oscillator as soon as possible since we have our boards on 5 plzz sir u are a great teacher
Hello Mrityunjay Dubey,
I shall try my best.
Thanks sir and I m genuinely fan of ur teaching
Yes sir please.By the way a big fan of your teaching.
It's good .complex to easy
Sir amplifiers pe bhi video's banaye please🙏
Thankyou very much sir
For that much elaboration
sir, you are great, and your writing is clear. Please tell me which software is that?
Exam ke pehle dekha ye video, bacha liya sir aapne.
Sir bjt as switch me power electronics me btate hai ke current collector to emitter flow hota hai saturation me par base current ko kyu nhi consider krte collector current to base aur emmiter dono me flow hota hai
Thank you sirjii
Very nice sir , mow I am clear with this topic
Take love from Bangladesh ❤️
Sir, aap physics ki vagban ho.... 🙏🏼🙏🏼🙏🏼🙏🏼
Best explaination
Nice knowledge thanks sir
Sir could you please make vdos on power amplifiers and opam ... please
Loved your video
Highly informative sir.thanks🥀💙.
Thank you sir ❤️
HELLO
PHYSICISTS....
Hats off sir😍 God bless u
Thank you for such clear explanation
Rc resistor Wala part to reverse bias me h to usme se current kaise flow hoga jab transistor ka potential >0.7V hoga to
Plz answer
Reverse bias ka breakdown voltage hi 0.7V hai , jab input usse zyada ho ga toh current flow karne lagega
Shukriya sir🥺🥺
Hats off sir best explanation
The background sound is spooky 6:10 6:11 6:20 6:24
nice this helps me to understand well
Thanks... Very nice
This is a best video thanks
Saturation region m transistor on hoga ya off???
Thanks
Thanks sir for the very easy explanation..
Always waiting for the next upload..
Sir, please make a video on transistor as an amplifier.
Nice explanation
Very nice explained 🙏🙏🙏
Superb explanation 👏👏👏
Gr8 explanation
Can you please make video on switch mode power supply
So what difference in diode and transistor? Means we can use transistor as switch also?
Thanks a lot
Superb sir ji😘😘
amazingly explained