Hello Sir, enjoyed watching your tutorials. I would like to know if we have co officiant to our *sins* in type *c* how to apply the formula ? Thank you in advance
Anil Kumar I recommend you read text books about numerical analysis as well. It’s really interesting and involves mostly calculus, linear algebra and some knowledge of computer programming! At university I chose to do complex analysis and numerical analysis, and I didn’t referent either of them!
THIS WAS THE MOST UNDERSTANDABLE LIMIT VIDEO IVE EVER WATCHED
this is more clear than a 1 hour class in school.
Important video for IIT JEE Test
You sir are a legend.
I really understood.....thanks a lot sir
Tq sir a very helpful video✨
Thank you sir ,you just helped me there 🇿🇦
Simple and clear 👍👍👍
Thank you for this video you literally saved my life
This man's pen is so good
Nice explained sir 👍🏼
❤😮😮 this is great!!!
Woow sir🎉❤❤
can someone tell how 7:42 worked?
THANK YOU SIR
Amazing 🤩
Thank you sir
Thanks for appreciation
You are genius 🙂🙂
Thankyousomuchh sirr!🤞💜
good
Good i like it
Thank you
my question is in 2nd problem how the (sinx cosx) becomes (1-cosx). i know we take the sinx in common but where does the 1 came from in (1-cosx)
[ sinx * ( 1 - cosx ) ] = [ sinx - (sinx*cosx) ]
Distribute the sinx to (1-cosx) and you will see it's equivalent to [ sinx - sinx*cosx ]
@@neidan4437 thank you, i appreciate it.
I don't know
how did sin x over cos mins sin x turned into sin x - sin x cos x? please detailed explaination
The cos x becomes the lcm. eg4/3 + 2 becomes 4+2*3/3
I need advice on how to study
Arre sir hindi mai hi bol rete ❤
Toh jayada view aate but it's ok ❤
Happy with few. At least you saw it.
I have more than 100 videos in Hindi. Hindi Videos have even less views: th-cam.com/video/fXSwhR0Bb5k/w-d-xo.html
Can someone tell me on 7:17 how did "sinx-sinx" become "sinx-sinxcosx"....
same problem D:
they are making the denominators equal
Taking lcm
how did the sinx on the right got a cox 7:10
Thank you for this video my friend, what pen you use?
Renyolds Trimax
indian morgan freeman
Condition n nest pas nulle
sir please help me in solving 1 problem. :: lim x approaches 0 [1-cos(-ax)]/[sin^2 bx/2]
Hello Sir, enjoyed watching your tutorials.
I would like to know if we have co officiant to our *sins* in type *c* how to apply the formula ?
Thank you in advance
PLS CONTIINUE DOING THIS OK
Sir can you recommend me books to self study math(Algebra II,Precalculus,Calculus(university level))
Thanks in advance !B--))
Algebra 2: Prentice Hall Mathematics,
Calculus: James Stewart
Anil Kumar I recommend you read text books about numerical analysis as well. It’s really interesting and involves mostly calculus, linear algebra and some knowledge of computer programming! At university I chose to do complex analysis and numerical analysis, and I didn’t referent either of them!
There is a mistake on first exercise it should be 1 as answer
For the second one how come the denominator is cosx*sin^3x
cosx came from the numerator. Hope that helps. Thanks
(a÷b)÷c gives as a÷b.c
Hope that helps
@@nutansingh648 sirr....what is the name of that method in algebra .... Thank you sir❤
محمد الممثل امداك على هذا الدكتور
Can anyone explain to me how 7:32 works?
Joshua Macuna tan x = sin x/cos x
so..
sin x/cos x - sin x (simplify) you’ll get (sin x -sinxcosx)/cosx then all divided by sin^3x
@@arnoldlegarte9224 I get that.... what im asking for is where did he get the (1-cosx)
he factored out sin x
@@joshuamacuna6196 pythagorean identities, sin^2 theta + cos^2 theta = 1
You are a lifesaver mister🫡