Impulse problem

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  • เผยแพร่เมื่อ 25 ธ.ค. 2024

ความคิดเห็น • 16

  • @pipertripp
    @pipertripp 6 ปีที่แล้ว +1

    I like how the kinematic equation Vf = Vo + at just falls out of the impulse concept. The latter is obviously more powerful since the force applied doesn't have to be constant.

    • @yoprofmatt
      @yoprofmatt  6 ปีที่แล้ว +1

      Pretty cool, eh.
      Note: Here we used a constant force so we could bring it out of the integral, and then of course we end up with a kinematic equation. If the force is not constant, then you can't bring it out of the integral, you don't get constant acceleration, and you can't use the kinematic equations.
      Cheers,
      Dr. A

    • @pipertripp
      @pipertripp 6 ปีที่แล้ว +2

      yep. that what I meant by the last bit. Thanks for all of these vids. Very helpful, esp I'm just learning this stuff on my own for fun.

  • @yoprofmatt
    @yoprofmatt  10 ปีที่แล้ว +3

    Because that was a mistake. Good catch!

  • @williamcashion5262
    @williamcashion5262 2 ปีที่แล้ว

    Did you ever do (like) a water jet on a wall or like air molecules on a piston? Ie, a high collision rate?

    • @yoprofmatt
      @yoprofmatt  2 ปีที่แล้ว

      No, I'll have to put that on the to do list. Great idea.
      Cheers,
      Dr. A

  • @ArcanumObscura
    @ArcanumObscura 10 ปีที่แล้ว +5

    How did you get 24 m/s using (2.5-.98)(10) ?
    I got 15.2 m/s

    • @maxsolar1139
      @maxsolar1139 6 ปีที่แล้ว +2

      I know it was three years ago but I definitely should have read the comments xD... I spent a good ten minutes redoing my work to see why I wasn't getting 24m/s

  • @RavinderKumar-os8wn
    @RavinderKumar-os8wn 4 ปีที่แล้ว

    👍👍💯💯

    • @yoprofmatt
      @yoprofmatt  4 ปีที่แล้ว

      Vishal Rao,
      Thanks for the comment, and keep up with the physics!
      You might also like my new website: www.universityphysics.education
      Cheers,
      Dr. A

  • @RavinderKumar-os8wn
    @RavinderKumar-os8wn 4 ปีที่แล้ว

    Bhai kati zhr

  • @jntmisra
    @jntmisra 6 ปีที่แล้ว

    I am confused about this situation where in a cart there is a bob hanging through a string and a bullet hits the bob horizontally ( the cart is open from one end) so will momentum be conserved in cart + bob + bullet system or just in bob + bullet....i thought that momentim will be conserved in first system but in the solution givwn in my book they chose second system and i sont understand why

    • @yoprofmatt
      @yoprofmatt  6 ปีที่แล้ว

      This is what you want: th-cam.com/video/h_rnqo7XB2U/w-d-xo.html
      Cheers,
      Dr. A

  • @igml1145
    @igml1145 8 ปีที่แล้ว

    in the first problem, could we use newton's second law and find a, a=F/m=2.5 m/s^2
    then v_f=v_i+a*t=a*t=2.5*10=25 m/s... we get the same thing

    • @yoprofmatt
      @yoprofmatt  8 ปีที่แล้ว

      +ig ml
      Ig,
      Absolutely you can! Well done.
      Cheers,
      Dr. A