Momentum and Force

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  • เผยแพร่เมื่อ 30 ก.ย. 2024

ความคิดเห็น • 47

  • @yoprofmatt
    @yoprofmatt  9 ปีที่แล้ว +2

    Sean, no I'm not. Check it out here: th-cam.com/video/CWHMtSNKxYA/w-d-xo.html
    Cheers, Dr. A

  • @jr13763
    @jr13763 8 ปีที่แล้ว +13

    Great! I loved your clear explanation. I can also follow all the math myself with pen and paper. The Learning Glass is fantastic, congrats!

    • @yoprofmatt
      @yoprofmatt  8 ปีที่แล้ว +6

      +Ismael Jr
      Thanks Ismael, we are having a blast with Learning Glass. I do really like the idea that people can follow with only pen and paper.
      Cheers,
      Dr. A

    • @josuejeremias2774
      @josuejeremias2774 4 ปีที่แล้ว

      @@yoprofmatt where can you buy this Learning glass?

  • @c1inward346
    @c1inward346 5 ปีที่แล้ว +2

    Yes I have a question... if we consider the closed system to be the ball itself, then momentum is not conserved right? Cause according to the law of conservation of momentum, the change in momentum itself is not equal to zero? Also if we didn’t want to violate the law of conservation of momentum, we have to consider the interaction between the ball and the impart force to be a closed system right? I’m genuinely curious about this

  • @frederickambaritaa8057
    @frederickambaritaa8057 7 ปีที่แล้ว +4

    thanks. you are an exquisitely intelligent individual (smart person XD )

  • @NishantKumar-xw3lg
    @NishantKumar-xw3lg 4 ปีที่แล้ว +4

    Thanks a lot Dr Anderson I have never seen such a teacher.

  • @budekins542
    @budekins542 6 ปีที่แล้ว +5

    Explained in plain English!

  • @MathematicsUniversalLanguage
    @MathematicsUniversalLanguage 2 ปีที่แล้ว +2

    Great sir. need more videos from you. stay healthy. have a wonderful life.

  • @rodrigoarce4165
    @rodrigoarce4165 8 ปีที่แล้ว +4

    Dr. Anderson I have to say that this video is super helpful. I really wish my teacher explained things with this much clarity.

    • @yoprofmatt
      @yoprofmatt  8 ปีที่แล้ว +1

      +rodrigo arce
      Thanks, Rodgrigo. Sorry the sound was not great on this one. But glad you found it helpful.
      Cheers, Dr. A

  • @wenjunwang8763
    @wenjunwang8763 5 ปีที่แล้ว +2

    Dear Professor Anderson, very clear explanations! I took an online Physics class and your lectures helped me understand the textbook better. Thanks for your sharing.

  • @fethierbaybuyuk6266
    @fethierbaybuyuk6266 ปีที่แล้ว

    Hello. I would like to ask a question with your permission. Let any object move in the horizontal plane for a certain period of time. Is an impulse defined for the normal force acting on the object perpendicular to the horizontal plane during this period, or for the weight of the object? In other words, there is no velocity change in the direction of these forces during the motion period, but this is because the impulse transmitted by the normal force to the object and the impulses transmitted by the weight vectors to the object are negative of each other. They do not contribute to the total impulse. Is this thought correct? It is defined as the product of impulse force and the duration of action of the force. Is this definition valid only for forces in the direction of motion of the object? If the net thrust transferred to an object can be calculated as the vectorial sum of the thrusts transferred to the object by each force separately, can we think that the thrust transferred to the object by a force that is not in the direction of motion of the object is also defined? Thanks.

  • @arinalikes5911
    @arinalikes5911 4 ปีที่แล้ว +1

    Thank u for uploading those videos. They are lucid and easy to understand

  • @aashishkarki7867
    @aashishkarki7867 4 ปีที่แล้ว +2

    You are the best Teacher in this whole cosmos. Your student from Nepal.

    • @diyadahal5384
      @diyadahal5384 3 ปีที่แล้ว

      I am here too👊

    • @binitaroka53
      @binitaroka53 6 หลายเดือนก่อน

      The time period of a charged particle undergoing a circular motion in a uniform magnetic field is independent of its
      ​@@diyadahal5384

  • @yeonhojung7185
    @yeonhojung7185 6 ปีที่แล้ว +2

    Thank you Dr. Anderson for your help!
    The best physics professor in youtube!

    • @yoprofmatt
      @yoprofmatt  6 ปีที่แล้ว +1

      You're too kind. Thanks for the comment.
      Cheers,
      Dr. A

  • @flippert0
    @flippert0 2 ปีที่แล้ว

    "Bueller, Bueller..." In case you forgot (or, god forbid, don't know): Matt is referring to this: th-cam.com/video/yUjhSBjxuXA/w-d-xo.html

    • @yoprofmatt
      @yoprofmatt  2 ปีที่แล้ว

      Thanks for the clip! Great scene, great movie. And yes, we're old.
      Cheers,
      Dr. A

  • @manuboker1
    @manuboker1 ปีที่แล้ว

    BEST PHYSICS LECTURES EVER !!!

  • @catherinethomas2568
    @catherinethomas2568 4 ปีที่แล้ว

    F=ma and an additional +x. X being over spill or detached force, which is exponentially increased while gravitating. The earth grabs it. Even sound's effective force. Flying vessels, especially space shuttles push force into the earth, that F=ma doesn't cover. Ground wiring is the path of the water and gas that is effected by displaced momentous effects. Compressors, attics and the stomach carry the displaced force constantly. Gravity and the so known speed of light, are quick. The force is hidden by lack of interest. Force is also linked to cancelled voltages as a constant. Part of the equation that proves +x. I booked the generations that now light the world, I am God, so don't doubt what I speak. My name:
    Charlie John Thomas

  • @gandhiraman.k9824
    @gandhiraman.k9824 3 ปีที่แล้ว

    Sir...pls make a video about aberrations and aplanatic points in geometrical optics briefly...sir

  • @shivam-ug2xk
    @shivam-ug2xk 4 ปีที่แล้ว +1

    Amazing explanation Anderson 🤗🤗keep it up

    • @yoprofmatt
      @yoprofmatt  4 ปีที่แล้ว +1

      Shivam Pandey,
      Thanks for the comment, and keep up with the physics!
      You might also like my new website: www.universityphysics.education
      Cheers,
      Dr. A

  • @melodymichaela7464
    @melodymichaela7464 4 ปีที่แล้ว

    I don’t understund

  • @mustafasuzun
    @mustafasuzun 6 ปีที่แล้ว +1

    You smile like Benedict Cumberbatch

  • @254medhat
    @254medhat 8 ปีที่แล้ว +1

    Really helpful

  • @saralove3762
    @saralove3762 8 ปีที่แล้ว +1

    i like it alot .. thnk uu ... prof. anderson

    • @yoprofmatt
      @yoprofmatt  8 ปีที่แล้ว +4

      Sara,
      thnk uu for watching
      hope you found them helpful
      Cheers,
      Dr. A

  • @rabishaw2373
    @rabishaw2373 4 ปีที่แล้ว

    I love your simple way of explanation why don't you upload new videos.

  • @rakkun2844
    @rakkun2844 4 ปีที่แล้ว

    In the reflection, there is a guy with a Nike T-shirt...

  • @mohfa1806
    @mohfa1806 2 ปีที่แล้ว

    i salute you prof...you are amazing in teaching and delivering science concepts...thank you

    • @yoprofmatt
      @yoprofmatt  2 ปีที่แล้ว

      Thank you very much. It makes me very happy knowing these videos are being put to good use.
      Cheers,
      Dr. A

  • @rxseqvartz5679
    @rxseqvartz5679 6 ปีที่แล้ว

    the glass sound is like ;/ its really disgusting

    • @yoprofmatt
      @yoprofmatt  6 ปีที่แล้ว

      Agreed, it's awful. Usually means my pen is running dry. Later videos are better.
      Cheers,
      Dr. A

  • @roteroktober360
    @roteroktober360 4 ปีที่แล้ว

    I thought Impuls and momentum were the same thing...

    • @yoprofmatt
      @yoprofmatt  4 ปีที่แล้ว

      roteroktober420,
      Almost. Impulse is change in momentum.
      Thanks for the comment, and keep up with the physics!
      You might also like my new website: www.universityphysics.education
      Cheers,
      Dr. A

    • @carultch
      @carultch 4 ปีที่แล้ว

      Impulse is the cumulative effect of a force applied through time. In simple terms, it is the product of force and the time it is applied. In complete terms, it is the integral of force over a time interval with respect to time.
      Momentum is what the object possesses once in motion.
      Impulse is to momentum, as work is to kinetic energy. There is an impulse-momentum theorem, relating the net applied impulse to a change in momentum. Just like there is a work-energy theorem, relating work done on an object to its change in kinetic energy.

  • @meenurani2240
    @meenurani2240 6 ปีที่แล้ว

    very good ,sir

    • @yoprofmatt
      @yoprofmatt  6 ปีที่แล้ว

      Thank you. Keep up with the physics.
      Cheers,
      Dr. A

  • @ammachammach2353
    @ammachammach2353 6 ปีที่แล้ว

    I love it..

    • @yoprofmatt
      @yoprofmatt  6 ปีที่แล้ว +1

      I love it too.
      Wait, what do we love?
      Cheers,
      Dr. A

  • @asmaomran5931
    @asmaomran5931 6 ปีที่แล้ว

    Thx!!

    • @yoprofmatt
      @yoprofmatt  6 ปีที่แล้ว

      You're very welcome.
      Cheers,
      Dr. A