derivation of work done in isothermal process|| work done in Carnot's engine.phy in hindi class 11th

[@manojrar034]

Ideal gas equation is PV=NRT sir

[@vgyan4u525]

Yes
But for 1 mole of gas
It will be PV=RT.

[@laxminarayanswayn1900]

@@vgyan4u525 sir it for n mole

[@laxminarayanswayn1900]

Thank you so much sir

[@skipupstuff8436]

@@laxminarayanswayn1900 ha

[@shubhamverma567]

Brother but here the no. Of mole is 1 only . Therefore equation become PV=RT.🙏

[@gkau4337]

great explanation, this is the first derivation in physics that uses integration that I have done so your video was the only one I found beginner-friendly

[@jashwant9adilaxmi391]

Sir your explaining is very good u clear my all douts...thank u sir

[@JanaviMore001]

It's too easy to understand explained....❤

[@amishapatial9887]

Who else here , near exams😅

[@vatanchouhan1302]

Me

[@raboo3391]

Me too🙄

[@dilettarebello8781]

Me

[@jyotidhankhar1354]

Me

[@Faiz15686]

Tomorrow is my physics exam😐

[@HarshSingh-hc4fv]

Kasam se sir Maza aa gaya thank u sir💗💗💗

[@noornagpal8503]

Sir uh just explained it amazinglyy ...thankuh sir 🙏❤️

[@Jatin_connect]

Even after 5 years , it is helping students 🗿

[@pawanSharma-gi8ox]

nice explained plus best handwriting.....thanku sir

[@vgyan4u525]

🤣🤣🤣 handwriting.
Thankyou

[@mathmacho6542]

Thanku sir, and kindly make more videos in future related to physics😊

[@kajalkumarikajalkumari325]

thank you sir for helping us🙏🙏🙏.and your teaching style is osome 😍🥰🥰 🥰🙂 m

[@akairrationalchess7667]

Osome 😂😂 it is awesome

[@piyushchoudhary3225]

Awesome

[@Thevivekchoudharyvlogs]

Omg what a great explanation 😁😁❤❤❤ thanku sir 💕😉

[@pawanmadhad4306]

Very very nice video....

[@Ashu-vg7fh]

Very nice sir
Your video and voice

[@laxminarayanswayn1900]

Super sir May bahuth pasand aye

[@sagarhgowda4808]

Thank you very much sir for clearing our doubts.🙏🙏🙏

[@ranipandey5829]

Sir there is a mistake in last during isothermal expansion work done will bhi negative because work is done by the gas 👍but thanks for explanation

[@ramkanojiya1099]

Ur video is best 👌 for me

[@vgyan4u525]

Let's hope dusro ke liye bhi ho ☺☺

[@taranpreetsingh1951]

Very nice sir merai teacher hi bnjo

[@samimmollah986]

I am watching this video after 1 year it's nice explained....

[@999movement]

😂 that tumbnail got me

[@rishusingh7307]

Thank you very much sir...for your best explanation...on this topic.

[@nausheenbaby6314]

Thank you sir ap bohat aache se explain kar te hai

[@shashipratapsingh0202]

Very nice explanation 😊

[@ankushranout6123]

🙏🙏🙏 best teacher 👍❤️❤️

[@gourvipawar7361]

Sir ap bhot bhot accha padate ho really 👍😊😊

[@vatanchouhan1302]

Plz make a video on Bernoulli's theorem .... 🙏🏻🙏🏻 And triangle law of vector addition .... Also..🙏🏻

[@RahulYadav-wj8ws]

Very well sir

[@homeprojects5152]

Very nice explination sir u beat PW

[@leenasingh7731]

Clear explanation 💖

[@vgyan4u525]

More videos are upcomming
Full syllabus
Stay connected

[@technicalsg6181]

Thanks sir for helping us💯

[@infinixgaming4864]

It was awesome
THANK YOU SIR

[@NavneetKaur-xu5tm]

It’s very helpful

[@lifefacts6891]

Thnku soo much sir....🥰

[@karanveerseniarey2840]

Nice explanation 👌

[@swagatika4250]

Sir iss equation main 2.303 bhi aata hai
To vo kahan se aata hai?
Coz book main jo equation given hai vo hai -2.303nRT logVf/Vi

[@karamjitsadhar3669]

Awesome sir thanks very much 👍

[@PreetiChaudharyTejaswani]

Ekdam acha laga video

[@Unmsachdeva_]

3:03 cheente OP... 😂😂😂😂 In the left most😂😂

[@RohitPensiadharodi]

❤ sir thanks you so much
Today my exam 😊😂

[@ayushkumar373]

So much simple but easily recognisible

[@ruwndarangbaanal2812]

Well explained sir, 😃

[@sandeepbrar3470]

Thnkewww so much 🥰❤️sir

[@asmamohamed2322]

thank you sir it' very easy to understand

[@fanindra735]

The vedio was really helpful for me just one doubt in some book why it is given w= 2.303*RT*logV2/V1
2.303 ?

[@amangupta-1958]

Same dude....where is 2.303

[@vllogy3501]

In this video ... He used work done in reversible process for isothermal
W = RT log(base e ) V2/V1
We know
log( base e ) = ln
ln = 2.303 log ( base 10 )
Hence , 2.303 nrt log ( base 10 ) V2/V1
[ For 1 mol of gas ]
W = 2.303 rt log ( base 10 ) V2/V1

[@nmmn4204]

You teach very well its very easy to get understand. ....... Thank you so much sir😍😍😍

[@aarchigupta7856]

Good 👍explanation

[@aaravrathod1844]

Superb work sir. Please make more videos

[@shubhamverma567]

Excellent sir 😊🙏🙏😊🙏👌

[@RavinderSingh-entertain]

Sir Carnot cycle explain with work done in Isothermal and adiabatic process

[@vgyan4u525]

Carnot Engine(A2Z): th-cam.com/play/PLR1Nl40RkLO_pQUw-Pi5pmIc-9d6K7L50.html

[@sabaakhtar1528]

Superb sir

[@smilewithjass]

Thank u very much sir .🙏🙏🙏

[@VaibhavAhlawat-x4u]

Sir nrt ke aage 2.302rt×logevf\vi bhi to aata h

[@Harsh_pillani]

Mza AA gya ❤️🙏🙏

[@arijitvlogs4042]

Nice explaintion sir

[@arpitakhurana6634]

Best explanation 👣

[@vgyan4u525]

Why this foot prints

[@arpitakhurana6634]

@@vgyan4u525 this is step towards success

[@vgyan4u525]

Ok thankyou

[@bipulgamer07]

​@@vgyan4u525 😆

[@anjalimalik6223]

Thanks a lot sir 💜💜💜

[@jeevansharma3036]

Thanks sir for
this video

[@MOHAMED_51206-n]

IDEAL GAS EQUATION IS PV=nRT

[@vgyan4u525]

For one mole of gas n=1

[@amitkour163]

Keep it up bro very good

[@hey_aly_here_.]

Thank u so much sir 🙏

[@sukhvirsingh797]

Well explained sir

[@SaritaKumari-nx2fw]

Sir ne mehendi lagai hui hai

[@DineshKumar-sb5yu]

Thank you sir nice explanation

[@zaidabbasi9120]

Thanks sir for nice explaination 🙂🙂

[@abhishekRajput-hl7zi]

Bhot accha samjhaya

[@akashdeep_chahxl]

Kll paper hai ajj pdd rhe hai who are ultralegend like me👇😂

[@dilnadilna3766]

Perfectly explained sir 👏👏👏👏👏🙏🙏

[@nandkishormeghwal407]

Sir make video of First Law Of Thermodynamics.I hope you will make video.

[@biswajitbarui5246]

In my book, V2>V1, work is negative, work done by the system

[@vgyan4u525]

There are are two things work done by the system
And work done on the system

[@biswajitbarui5246]

@@vgyan4u525 sir,in your video, u said that work done by the system,w-positive

[@vgyan4u525]

You can do correction as per your book

[@biswajitbarui5246]

@@vgyan4u525 sir please solve this question, i have exm in Friday
Deduce the standard free energy of the following chemical reaction: pP+qQ---->rR+sS. (2mrks)

[@vgyan4u525]

Send me book photo of this topic [e-mail]

[@Kiran-ps1ut]

Thanku Sir😊

[@zainimalik3603]

Is it for diatomic gas ???

[@mohit__rohtakiya_]

Na

[@ChamkaurSingh-kz8vi]

Thank you so much sir

[@Sahin-333]

Thank you❤ sir

[@SurjeetSingh-ft8hi]

Sir We Need a Derivation Video on Newtons Formula for velocity of sound of aur and by using Laplace Correctness

[@chemworldbyfarhan847]

Sir, during expansion work done will be negative ...u mentioned positive

[@vishaljaiswal4713]

Bahut accha he sir

[@renuyadav690]

Legends watching this video before 4 hours😎😎😎

[@snelovesaestov6312]

Thank you❤️

[@HARPREETKAUR-jv7ek]

Thanks sir

[@pritisoni991]

Nice explained

[@akanshatiwari7190]

Sir hume to logrithm class 12 me padhna hai to hume log concept samajh aayega please tell?

[@aanchalrai9677]

The result is that any compression will have a positive work term, and any expansion will have a negative work term..... isn't it?????????

[@vgyan4u525]

Nope
In compression work is negativ since final volume is less
And vice versa

[@manojshrivastav2545]

2hrs bad paper h 😅 thanks sir

[@paranormalactivities7914]

I am watching this video 2 hours before exam

[@justkcworld4796]

And this came in section D how u know?? This will come??

[@truebeliever9300]

Sir aap bsc physics Hons ka videos banate ho ??

[@piyushchoudhary3225]

Video better play in 1.25 x

[@prakashhvhv7289]

Super sir

[@theallrounder8653]

Amazing

[@gurvirsingh4190]

Great sir

[@owaismuzaffar3235]

Legends watching this video one day. Before exams
One like plz

[@arcreative4433]

Thnx sir

[@papusingh4361]

Thank you sir

[@mohit__rohtakiya_]

Sir integration ka video dall rakha h Kya

[@vgyan4u525]

Check my videos.

[@juice.88]

Thank u

[@nausheenaqeel8093]

Who notice the ant at 1:20 ...raise your hand

[@mjokergamer5706]

3bjne wale hai aur kal Mera exam hai

[@ibhawesh]

thnks

[@shubhamchauhan2490]

2bje exam 12bje padhai 🙂🙂

[@komalpreetkaurearth3507]

thanks sir it's very helpful

[@abhishekRajput-hl7zi]

Nyc sir