วีดีโอ

Maja aaya aur ye jo maja hai mai hindustaan ke har student ko dena chahta hu

Sir jo aapne kraya ye yhi h kya -> Drive and expression for Total energy of Simple Harmonic motion and also plot it diagram ? Please tell me sir 🙏 kal ka exam h mera

Thank you sir ik baar me hi samajh gaya😍👍

Very nice explanation ❤❤

Savita Patwa Too good sir loved your explanation😂🙌🏻

Wherrs the link of your playlist????

At 11:30 divided by m/d not d/m

Let’s break this down step by step to explain how the solution works for the given positions in simple harmonic motion (SHM). --- ### 1. **Key Concepts in SHM:** - **Total Energy (E):** The total energy in SHM is constant and is the sum of Kinetic Energy (K.E) and Potential Energy (P.E): \[ E = \text{K.E} + \text{P.E} \] \[ E = \frac{1}{2}kA^2 \] where \( k \) is the spring constant and \( A \) is the amplitude. - **Kinetic Energy (K.E):** \[ \text{K.E} = \frac{1}{2}k(A^2 - x^2) \] It depends on the displacement \( x \) from the mean position. - **Potential Energy (P.E):** \[ \text{P.E} = \frac{1}{2}kx^2 \] It also depends on \( x \) and is maximum at the extreme position \( x = A \). --- ### 2. **Analyzing Specific Positions:** #### **Case 1: \( x = 0 \) (Mean Position)** - At the mean position, the displacement \( x = 0 \). - **P.E = 0**, because: \[ \text{P.E} = \frac{1}{2}kx^2 = \frac{1}{2}k(0)^2 = 0 \] - **K.E = E**, because all the energy is kinetic at \( x = 0 \): \[ \text{K.E} = \frac{1}{2}k(A^2 - 0^2) = \frac{1}{2}kA^2 \] --- #### **Case 2: \( x = A \) (Extreme Position)** - At the extreme position, \( x = A \). - **P.E = E**, because all the energy is stored as potential: \[ \text{P.E} = \frac{1}{2}kx^2 = \frac{1}{2}kA^2 \] - **K.E = 0**, because the object is momentarily at rest. --- #### **Case 3: \( x = \frac{A}{\sqrt{2}} \)** - At this point, **K.E = P.E**: \[ \frac{1}{2}k(A^2 - x^2) = \frac{1}{2}kx^2 \] Simplify: \[ A^2 - x^2 = x^2 \implies A^2 = 2x^2 \implies x = \frac{A}{\sqrt{2}} \] - Both K.E and P.E are 50% of the total energy: \[ \text{K.E} = \text{P.E} = \frac{1}{2}E \] --- #### **Case 4: \( x = \frac{\sqrt{3}A}{2} \)** - At this position: - **P.E:** \[ \text{P.E} = \frac{1}{2}kx^2 = \frac{1}{2}k\left(\frac{\sqrt{3}A}{2} ight)^2 = \frac{3}{4}E \] So, P.E is 75% of the total energy. - **K.E:** \[ \text{K.E} = E - \text{P.E} = E - \frac{3}{4}E = \frac{1}{4}E \] So, K.E is 25% of the total energy. --- ### 3. **Summary Table of Results** | Position | \( x \) | P.E (% of E) | K.E (% of E) | |----------------------|------------------------------------|--------------|--------------| | Mean position | \( x = 0 \) | 0% | 100% | | Point of equal energy| \( x = \frac{A}{\sqrt{2}} \) | 50% | 50% | | Intermediate position| \( x = \frac{\sqrt{3}A}{2} \) | 75% | 25% | | Extreme position | \( x = A \) | 100% | 0% |

One day before exam 🗿

Thnks 😊

Here,Direction of force and displacement is opposite to each other so W=-f.dx

Tnx so mch sr❤❤

Those who are watching before 1 hour of exam 👊🏽🙌🏽🔥

Thankue sir❤❤

In 2nd tds equation u used 4th Maxwell equation

Before exam

Why we multiply it with 2dx/dt Kindly reply fast

❤❤❤❤

You're a lifesaver sir!! This experiment went over my head and watching this video is no different than actually performing it! I have my lab exam tomorrow. Thankyou so much

Very nicely explained sir 🙏

1 hr before practical

Very nice explanation.....carry on bro your channel will grow one day

Thanks you sir bhot acche se samjh aa gaya derivation

Best video on maxwell's relations

Pro level explanation 😊🎉

Sink kya hai

last ka samaj nahi aya

Saved my life😂

Thanks sir very helpful video❤

9 बजे मेरा एग्जाम है , मै 4 बजे पड़ रहा हूं ।

doubt clear sir😄😄

Where is the video of short trick

Thanku sir

Video accha laga aur paper ki bhi Kami lag rahe hai 😢

Thanks for this easy explanation sir....... Love from UP❤❤❤❤

Thank 😊

Thanks sir 12 video dekhne kee bad sirf yaha pee samaj Aaya....🙏🙏

0:59😂😂😂😂😂😂 magnifine glass

20 min before practical

Bohot badhiya ara 👍🏻🔥🔥

🫡

Thanks teacher

Thank you sir very helpful ❤️❤️❤️

🎉

At

Timestamps (Powered by Merlin AI) 00:03 - Maxwell relations connect internal energy, temperature, pressure, and volume. 00:56 - Derivation of Maxwell's relations in thermodynamics. 02:40 - Comparison of thermodynamic equations reveals key relationships. 03:48 - Explores thermodynamics relations involving constant volume and entropy. 05:27 - Derivation of Maxwell's second relation using Helmholtz free energy. 06:21 - Applying dual identities for deriving thermodynamic functions. 08:21 - Comparison of thermodynamic quantities related to volume and temperature derivatives. 09:26 - Derivation of Maxwell's thermodynamic relations using temperature and pressure. 11:18 - Gibbs free energy and its thermodynamic implications are discussed. 12:11 - Free energy relates to pressure and temperature in thermodynamics.

bohot badhiya bhai...kal exam hai aur 10 minute me samajh aagaya pura conceptt!!!!!!!!!!!!

In the exam 💀 watching vedio

Studying 2 hour before exam

9 mins =Concepts clarity ❤