Your channel is a gem! You don't shy away from deep diving into the math behind everything while most other channels on TH-cam seems to only provide procedural pedagogy for the application of any concept to solve problems. Thank you so much!
@@EasyTheory yeah it is i have seen that proof in stackoverflow but couldn't understand they using grammar but it is time consuming(at the time of exam) but explain with example or using STACK would be helpful Thanks
@@akshatsharma9527 this is not a CFL you can easily observe that because we cant do double comparison using a single sta ck.Either |x|=|y| or x!=y could be performed. Pda cant perform both hence its a CSL.
![[กูเพิ่งซื้อมึงปิดหนี] 20 นาที ผมรีวิวเกมที่แย่ที่สุดในโลก CONCORD](http://i.ytimg.com/vi/XhC-3q3Ii7I/mqdefault.jpg)
![How to Parse a Sentence with the CYK Algorithm [Lecture]](/img/n.gif)
Your channel is a gem! You don't shy away from deep diving into the math behind everything while most other channels on TH-cam seems to only provide procedural pedagogy for the application of any concept to solve problems. Thank you so much!
Now I finally understand why the run time is N^3. Thank you!
would love to see an example as well!
oh god i love you so much life saver
Garcia Jessica Johnson Larry Garcia Jose
can you go over a python implementation?
This is a theory channel, so prob not :) you can go to the Discord server (or Facebook group, etc.) and discuss there.
on prevous video {xy x,y>(a,b)* |x|=|y| x!=y } it will be cfl why ?? can you make a video on doubt about wether it is csl or cfl Thanks
Guess what video is coming Saturday! ;) (and it is indeed CFL)
@@EasyTheory yeah it is i have seen that proof in stackoverflow but couldn't understand they using grammar but it is time consuming(at the time of exam) but explain with example or using STACK would be helpful Thanks
@@akshatsharma9527 this is not a CFL you can easily observe that because we cant do double comparison using a single sta ck.Either |x|=|y| or x!=y could be performed.
Pda cant perform both hence its a CSL.