Cross Retinoscopy | Retinoscopy Procedure

[@ugochinnamdi9275]

Best video on retinoscopy so far. Now I can do this confidently. Thank you Sir

[@kulbhushansahi1529]

At 66cm with homatropin
-0.5Ds/+1D at 90

[@mahaswetabhattacharjee1458]

To be an optometry student this video is really very helpful sir.

[@OptometryAcademy]

Thank you 😊

[@RamkumarSingh-pk8xv]

Can tell me scope of during optometry course

[@radhikarittu7049]

​@@OptometryAcademy😢

[@aapzeeevlog5162]

Iam A Optometrist Student No Idea In Retinoscope Watch Your Video Helpful Sir Thankuuu😍😍😍💯%

[@OptometryAcademy]

😊

[@muslehuddinnayeem]

This video is very much helpfu for us.

[@OptometryAcademy]

Thank you 😊

[@u2b_india_gaming]

Sir aapne to retinoscopy ki faad🤗 hi di
sir bilkul maza a gya sir.
🤩❤

[@OptometryAcademy]

Thank you so much 😊

[@MosesFrancisFaingaa]

+2.50DS/-1.00DC x 180
+1.50DS/+1.00DC x 090

[@wardazulfqar6523]

Can u explain how

[@rajrashika1744]

Transpose kiya h​@@wardazulfqar6523

[@varshavishwakarma9153]

I never seen this type of helping vdo and very very very easy to understand. Thankuu so muchh

[@OptometryAcademy]

Thank you so much 😊

[@ajazalam4403]

It's really helpful video sir,,, Tusi great ho ,,,, Thanks alot ,,,, I got it Cross form,

[@OptometryAcademy]

😊👍

[@NN-uc6kp]

Thank you for a very well explained video, sir.

[@nikitaraut8965]

Khup chan mahiti dili sir

[@rameshkumarca]

Very nice ppt👌👌👌

[@mohammadtahir9310]

Very important ppt ....👍👌👌

[@dr.pavaneeswarreddy8039]

-0.50ds/+1.00dc*90, +0.50ds/-1.00dc*180.

[@yasireye]

Homatropine -> 2% = 0.50 DS
Working distance = 1.50 Ds
So net Result is
-0.50/+0.50×90°

[@birkishandebbarma5041]

working distance 66cm so deducting +1.50ds
then used homatropine +0.50
ans is -0.50DS
Please check if its correct or not!

[@HunnyBunny0722]

Correct

[@habibabbaskhan]

I am MLOP student your video helpful ❤

[@aryabrahma8640]

Best video on retinoscopy

[@crystalnonye6932]

For the first time in practice, I got to understand retinoscopy 😁😁😁😁 Thank you so much

[@OptometryAcademy]

👍

[@smartboypeshwalodhi5903]

V. Helpful, thank you sir

[@ayeend6635]

omgggg!!! tysm, very informative and detailed discussion. I'm so happy I finally found your video after hours of searching the net about this topic.

[@OptometryAcademy]

Thank you so much 😊🙏

[@rakibulmolla3420]

Love u sir...total concept clear I am really happy.... Thank u very much sir....please do more video like this...

[@OptometryAcademy]

Thank you so much 🙏

[@sunilbhati3936]

Sir your video is super se bhi upar

[@OptometryAcademy]

Thank you 😊

[@iffy3836]

Very useful video thanks sir

[@OptometryAcademy]

😊🙏

[@AK-yu4tf]

Amazing video sir thankyou so much ❤❤

[@hinditoontv4319]

Without subtracting working distance and cycloplegic
+1.50 / +1.00 X 90

[@shreyamaity3959]

Thankyou so much sir..very helpful video ...

[@husaintyagi833]

Sir thanks good information

[@OptometryAcademy]

😊

[@snehaljadhav2769]

Working distance is 1 meter
Tonus allowance is +0.75 DS
The answer is : -0.25/+1.00 @ 90⁰

[@hdmoviestudio1775]

Thank u sir. Very helpful video.❤

[@iftekharoptom]

Valuable ppt👍👍

[@devarshimehta9991]

Sph= +1.50 -(+1.50working dist)=0.00
Cyl= +2.50-(+1.50working dist)=+1.00
Now final power={+0.00/+1.00×90°}
Now changing cylinder power (+ to -)
Given,{ +0.00/+1.00×90°}
Now,{ +1.00/-1.00×180°}
Final power to be prescribed:
+1.00dsph/-1.00dcyl×180°

[@mohammadibrahim3413]

+1.00*90°

[@HashimKhan-bc7jc]

At the end you done transposition I think 🤔

[@shwetnisha5889]

@@HashimKhan-bc7jc yes it is transposition. But this makes the Rx more complicated one.. always prescribe the simple one.. and rest depends on patient that which power he/she prefers or accepts during subjective refraction.

[@drm.haroonwazir8798]

You did not subtract tone Allowance.
If you subtract tone Allowance your answer will wrong

[@santosheelokhande9982]

But minus /plus is minus Then how come 0 the spherical value ?

[@mubimubeena3140]

Thank u so much sir.....

[@denyrobert4586]

Without any tonus allowance subtraction ,our ans would be
+1.00×90

[@blessingchibundu8232]

It's really a good video

[@OptometryAcademy]

Thank you so much 😊

[@denyrobert4586]

By deducting tonus allowance our answer would be
+0.50/-1.00×180

[@Prettysoull08]

Howw

[@shilpapunihani8242]

Very helpful video thanks u so so much sir ❤

[@Cheppuz3009]

Thnkyuu sir helpful video 👍👍

[@OptometryAcademy]

Thank you 😊

[@ushaverma9218]

Thanku so much for this vedios

[@umer51_]

Answer of last question is +0.5DS / -1.0DC x180°
Another possible answer is -0.5DS / +1.0DC x 90°

[@akshithaangel5569]

very very helpful to me

[@saraswathi6637]

Thank u sir well explained

[@aryarajeev6313]

Very useful video sir

[@talibsuhana4778]

Thku sir realy good plz show video in different meridians on same eye

[@OptometryAcademy]

Ok😊
Thank you 😊

[@shreyashdeshmukh3278]

Thanks sir 🤗

[@goldenraj4161]

Nice video sir

[@OptometryAcademy]

Thank you 😊

[@akashagarwal6425]

Very good video

[@indusharma7890]

Thank you my dear Akhilesh 😊

[@OptometryAcademy]

Thank you 😊🙏

[@intopages...7981]

Helpful...🥰👍

[@otiebrown9999]

Very informative!

[@dr.h.mgolamazam6280]

Very Good

[@smackslam6939]

Sir eye Diseases ke uppar bhi ek play list bnaiye

[@sunshine.a3452]

Really helpful I recommend.. thank you

[@tbg1199]

+0,5-1.0/180 or - 0.5+ 1.0/90

[@anshulverma01]

Awesome video

[@drx.sanjnapatel7538]

Thank you sir, very easy understood 😊

[@tabishaftab8224]

+150+100×90
W.D_150
0 +100×90 if we doing with cyclo..
Then it will be _0.50 +100 ×90 or
+050_100×180

[@rinkikumari1579]

Thank you for your help

[@thusbikathusbi1188]

Its amazing sir... thank you so much...

[@OptometryAcademy]

Thank you 😊

[@lavanyachinnasamy6038]

Sir we subtract only in horizontal meridian so power is +0.50DC × 180

[@OptometryAcademy]

We subtract working distance from both the meridian

[@lavanyachinnasamy6038]

Sir we subtrat Working distance both meridian and in cyclo allowance subtract horizontal meridian only sir so the power is +0.50DC × 180

[@OptometryAcademy]

Cyclo allowance also subtract from both the meridian.

[@OptometryAcademy]

Please watch this video again. It is clearly mentioned in the video.
Thank you for your comment 😊

[@dr.dishasahoo3093]

Beautiful video

[@OptometryAcademy]

Thank you 😊

[@muralisah7958]

Not spoken on sleeve which is first thing..plz explain sr

[@BeerBahdoor]

With working distance 66cm -1.00dc 90

[@faizanadeem1107]

Very well explained 👌🏻

[@OptometryAcademy]

Thank you so much 🙏

[@anjana2600]

Working distance= 2
Tones allounce =+0:50
Rough estimation=+0:50@90

[@ranjukushanth2737]

Final answer is +0.50/-0.50@90

[@meenasalve6265]

Thnxx a lott💯🙏🏼

[@OptometryAcademy]

Thank you 😊

[@KasHiFkHaN-tb5lk]

Thank You Sir Well Explained

[@richlady4020]

thank you soo much ❤❤❤❤❤❤

[@Nagu-ud1rw]

Thank you sir 😊 this video is very useful for me 😊

[@saadkhattak8446]

very helpful video .. thank you for sharing ur knowledge with us 👍🏻

[@OptometryAcademy]

Thank you so much 😊.
Keep supporting me 😊

[@saadkhattak8446]

@@OptometryAcademy you are welcome sir 😊 please also share cycloplegic refraction procedure step by step

[@OptometryAcademy]

Ok😊

[@yowamapu7657]

Thank you sir , this video help me a lot 🥰

[@3--M--E--D]

-0.5 sphere /+1 cylinder 90°

[@sandippanda3893]

sahi hai ❤️

[@jeevikanagula9296]

Very nicely explained

[@monojsau4230]

-0.50D/+1.00D x 90°

[@mohanapriya8356]

Sphere = +1.50, cyl = A-B =+2.50 -(+1.50) = +2.50 - 1.50 = +1.00cyl...So the answer is +1.50Ds/+1.00cyl/90°

[@vishaldey5513]

The Only right answer here

[@amaefulemiracle6829]

Did you subtract your working distance?

[@sandhi1991]

No the right answer is Plano/+1.00 x 90
Or, +1.00/-1.00x180

[@danielkipkosgei244]

Plano/+0.50@90

[@purnimatadingi9161]

Thank you sir

[@optm.pritamsharma1806]

Thnx sir

[@aisha.alkhateb6696]

with cycloplegics = +0.5Dsph/-1.00c ×180

[@lavanyachinnasamy6038]

Is it correct sir

[@sridevisumana8255]

Excellent 👌

[@OptometryAcademy]

Thank you

[@aiswaryas8627]

Well explained👍👍

[@OptometryAcademy]

Thank you 😊

[@humerah5459]

Very very helpful to me 😊

[@Vlogwithjay-c6z]

If distance 1 m or homotropine use +1.00 DS

[@fairytales8993]

i did not get the point of how to get cyl power..that A n B value

[@aparnavarshney5321]

+1.50 D S /+1.00 D C × 90°

[@sheetalshrestha6835]

-0.50ds/+1.0dc×90°

[@MukeshYadav-lj4mo]

-0.50/+1.00x90

[@arthurkorir7846]

Good animations and well explained. One thing though. You're mixing and interchanging meridians and axes. They are different

[@sisters7458]

Accha laga

[@gowrielumalai5623]

+1.50DSph/+1.00 DCyl90

[@tausheefraza6983]

-0.50 +1.00 at 90

[@aishakhatun6497]

Thank you very much for this explanation video sir.

[@OptometryAcademy]

Thank you 😊

[@surekhasutar2196]

Got it, thank you sir.

[@OptometryAcademy]

Welcome ☺️

[@rockstarlara26]

What is your occupation

[@surekhasutar2196]

@@rockstarlara26 I'm a student of Bsc.optometry, learning in 3 rd year

[@surekhasutar2196]

@@OptometryAcademy please,can you make video on fitting assessment for all types of contact lenses?

[@rockstarlara26]

Hello dear how are you

[@santosheelokhande9982]

Working distance=-1.50ds
Tonus allowance=-0.50
Ans : +3.50/+1.00@90°
After the transposition=+4.50/-1.00@180°

[@santosheelokhande9982]

Pls reply my ans I want to know if my answer is correct or not

[@EmpressAhsedek]

Plano-1.00@90

[@ridosihaloho9067]

Why you substract +1.50 ? You did not put working lens from the start. Please explain

[@OptometryAcademy]

Here, I am doing retinoscopy from a distance of 66cm. For 66cm we need to subtract+1.50 DS from the retinoscopic value.

[@EmpressAhsedek]

You can also do retinoscopy with your working distance in the back of the frame to avoid calculations at the end

[@roshanchaudhary744]

What if axis is in 45 degree

[@roshni_Gautam221]

-0.50sph/-2.00dc×90° same case.....WD =1.50 and eye drop use homatropine = +0.50

[@keertirathoredopt237]

+1. 50 sph/+1.00cyl@90

[@sajid-khan77]

Sir please do a retinoscopy lecture on oblique meridian neutralization, I mean meridian other than 90 and 180..please

[@OptometryAcademy]

Ok sir 😊

[@sajid-khan77]

@@OptometryAcademy thank you sir😊