Hallo Mr H Tutoring, I am 80 years, and had the need to "brush off" some dust on past knowledge of your Topic. Well, after your video lessons, again ...I am on top of the subject. You have a marvellous way of making things look easy. Today is Christmas dec 26 in Holland, Merry Christmas to you, THANK YOU, and continue making things "look easy".
I took some differential calculus courses when I was a Business student at Saint Mary's University in Halifax, Canada during the mid 1990s. While I'm familiar with limits, derivatives, and integrals, I would like to see some optimization and Law of Diminishing returns type questions.
Hello sir, you're method of teaching is extremely helpful, concise and clear, I'm from Canada and I'm wondering, which grade I will be using logs? Since I've just reached grade 11 and I've started quadratics.
When the Bass meets the Treble i listen. When i Beat is about the nature of the Record i say "Turn it up!" I'd like to say something when i listen to a Record i am listening with an Ear to say i like it or i hate it. I don't minding thinking for you about this Lesson, but i am about the Record. I am the Owner of a Peer, but i am the CEO of Shore Entertainment Incorporated a California Corporation. ~ CEO this Record.
In skydiving you have to account for air resistance. So, assuming that the skydiver is falling in a vacuum the calculations are correct. And, the skydiver is dead.
Good video bro but I want to point out that exponential equations can have imaginary solutions if you consider x to be a complex number. For example e^x=-2 has a complex solution.
@@mrhtutoring the equation I gave does have a solution x=ln(-2) can be broken into ln(-1)+ln(2)=ln(e^(ipi))+ln(2)=ipi+ln(2) as the principal root, this equation has infinitely many complex solutions. In general the solution is (2n+1)ipi +ln(2) where n is any integer and i is the sqrt (-1) so in our base case when n=0 we get the solution I stated 2 sentences back.
We are sure we can use the law of exponents, for the number was elevated to an exponent, right? There are many numbers; that elevated to an exponent allow us to use the log law of exponents. What numbers do not allow us to do so? Would we have to invent such numbers? To begin with all the numbers minus times a positive integer . We cannot take the log of a negative number...Let us start by saying that the log of a negative number is undefined........Or assuming the log of a negative number is undefined........
When i say i am a Dr. with no Degree i am, but i'll never say it to you Reader. I am smart, so i listen. I don't like thinking for you Reader, but i do. I am not about talking to you Reader. I am about my Doctrine. When i think about it i see it Reader. I don't like being about my Name and not talking Reader. I listen. I talk. I think, so i am Reader. When i listen Reader. I listen. When i think Reader i listen. When i talk Reader i am thinking about me Reader. This Dr. Degree is a Science Reader. And i like it. Bye Reader. ! Holder of a Science Degree. 🙂
No. x^(-1) is the same as 1/x. Negative exponents imply reciprocals in general, where the negative exponent becomes a positive exponent, once you move the power term downstairs. However, if x is in the exponent, instead of the base, it must remain in an exponent in some form or another. B^(-x) is not the same thing as 1/x of B/x, or anything else that only has x in the denominator. It is 1/B^x.
From India but also watch your videos just because of your amazing teaching style🔥🔥
Awesome! Thank you!
Thank you for your videos! Very easy to understand!
Hallo Mr H Tutoring,
I am 80 years, and had the need to "brush off" some dust on past knowledge of your Topic.
Well, after your video lessons, again ...I am on top of the subject.
You have a marvellous way of making things look easy.
Today is Christmas dec 26 in Holland, Merry Christmas to you, THANK YOU, and continue
making things "look easy".
Thank you.
Merry Christmas!
Once more, you render math simple and exciting.
Again, thank you so much for sharing your knowledge, Mr H!
Greetings. Thanks always for sharing. Have a great day
Your videos and the time you take to make them are truly appreciated. Thank You very much!
we would like to see u solving calculus problems, huge support from hong kong😻😻
I took some differential calculus courses when I was a Business student at Saint Mary's University in Halifax, Canada during the mid 1990s.
While I'm familiar with limits, derivatives, and integrals, I would like to see some optimization and Law of Diminishing returns type questions.
Meanwhile, some student is paying an arrogant professor $10,000 a semester
😂😂😂😂😂😂
Real
Nicely done, professor.
i am soo happy about this lesson .becouse the lesson was very hard to me but now it very ezy to me .thnk you sir
Damn! I wish you were my teacher in math when I was in school. I would have been more attentive! Lol. You make math so easy! Thank you sir!
First, also again, love these videos
Thank you very much sir may God richly blessed you for the time you take to impact knowledge in our lives.
7:27 efficient to another level 💪💪
Gracias profesor, excelente, las matematicas el lenguaje universal.
Thank you for the great review.
Good work Sir
Wow it amazing teacher thank you i appreciate you a lot sir i enjoying everything about you sir you have taken time to explain each step yeah
You are very welcome
You're the best
Wow that's awesome
Superb!
😊 thank you sir very useful questions 👍
Dear professor, a big greeting from Italy. Thanks for your lessons.
I can recommend You an other channel for math Olympiad preparation
Thank you so much sir.
Regards🙏
My teachers were hardening math. Made easy here, waiting for integration, differentiation and flow chart
this video is AMAZING!
I love this guy
❤❤ beyond
Hello sir, you're method of teaching is extremely helpful, concise and clear, I'm from Canada and I'm wondering, which grade I will be using logs? Since I've just reached grade 11 and I've started quadratics.
Usually in the 9th or 10th grade in the US
We learned logs in grade 12 pre-calculus classes in Canada. I hope it helps
When the Bass meets the Treble i listen. When i Beat is about the nature of the Record i say "Turn it up!" I'd like to say something when i listen to a Record i am listening with an Ear to say i like it or i hate it. I don't minding thinking for you about this Lesson, but i am about the Record. I am the Owner of a Peer, but i am the CEO of Shore Entertainment Incorporated a California Corporation. ~ CEO this Record.
Thank you ❤
Please can u apload graph of lagarithm...some thing like domain,simple trick
In skydiving you have to account for air resistance. So, assuming that the skydiver is falling in a vacuum the calculations are correct. And, the skydiver is dead.
Thank you ❤
You're welcome 😊
can you make a video about binomial theorem?? pleaseeee
Will do soon
@@mrhtutoring thank you sir
log_2(3)+log_2(x)=log_2(5)+log_2(x-2)
log_2(3x)=log_2[5(x-2)]
3x=5(x-2)
3x=5x-10
3x-5x=-10
-2x=-10
x=5 ❤
Good video bro but I want to point out that exponential equations can have imaginary solutions if you consider x to be a complex number. For example e^x=-2 has a complex solution.
x=ln(-2)?
The equation you gave has no solution.
@@mrhtutoring the equation I gave does have a solution x=ln(-2) can be broken into ln(-1)+ln(2)=ln(e^(ipi))+ln(2)=ipi+ln(2) as the principal root, this equation has infinitely many complex solutions. In general the solution is (2n+1)ipi +ln(2) where n is any integer and i is the sqrt (-1) so in our base case when n=0 we get the solution I stated 2 sentences back.
Nice
thank you
Sir can u do teach vector basic ( short video )
Sir please explain under the root when can we cancel the root and when we can can't please sir make a vedio 💖
3^(x+2)=7
x+2=log_3(7)
x=-2+log_3(7) ❤
If math were jazz, you’d be Miles Davis.
im from sri lanka
log(x+2)+log(x-1)=1
log[(x+2)(x-1)]=1
(x+2)(x-1)=10
x^2+x-2=10
x^2+x-12=0
(x+4)(x-3)=0
x+4=0
x=-4 (x[>=]-2; x[>=]1) extraneous solution
x-3=0
x=3 ❤
We are sure we can use the law of exponents, for the number was elevated to an exponent, right? There are many numbers; that elevated to an exponent allow us to use the log law of exponents. What numbers do not allow us to do so? Would we have to invent such numbers? To begin with all the numbers minus times a positive integer . We cannot take the log of a negative number...Let us start by saying that the log of a negative number is undefined........Or assuming the log of a negative number is undefined........
log_5(x+1)-log_5(x-1)=2
log_5[(x+1)/(x-1)]=2
(x+1)/(x-1)=25
x+1=25(x-1)
x+1=25x-25
x-25x=-1-25
-24x=-26
x=13/12 ❤
e^(2x+1)=200
2x+1=ln(200)
2x=ln(200)-1
x=[ln(200)-1]/2 ❤
4+3[log(2x)]=16
3[log(2x)]=12
log(2x)=4
10^[log(2x)]=10^4
2x=10000
x=5000 ❤
This is eassy
Good shit professor I love it!
Barbarian at the gate
When i say i am a Dr. with no Degree i am, but i'll never say it to you Reader. I am smart, so i listen. I don't like thinking for you Reader, but i do. I am not about talking to you Reader. I am about my Doctrine. When i think about it i see it Reader. I don't like being about my Name and not talking Reader. I listen. I talk. I think, so i am Reader. When i listen Reader. I listen. When i think Reader i listen. When i talk Reader i am thinking about me Reader. This Dr. Degree is a Science Reader. And i like it. Bye Reader. ! Holder of a Science Degree. 🙂
e^2x-e^x-6=0
(e^x)^2-e^x-6=0
(e^x+2)(e^x-3)=0
e^x+2=0
e^x=-2 (x>0)
e^x-3=0
e^x=3
x=ln(3) ❤
Lesson is nice sir but try to include some tough questions
Anybody for JEE 😊
Söylediklerinizi anlamıyorum ve buna gerek de yok çünkü yazdıklarınızı anlıyorum matematiğin dili evrensel
@10:52 Isn't something raised to the -x just the same as 1/x?
No. x^(-1) is the same as 1/x. Negative exponents imply reciprocals in general, where the negative exponent becomes a positive exponent, once you move the power term downstairs.
However, if x is in the exponent, instead of the base, it must remain in an exponent in some form or another. B^(-x) is not the same thing as 1/x of B/x, or anything else that only has x in the denominator. It is 1/B^x.