In the first numbers round, I had an alternative solution for 2 away: 75 + 50 = 125 125 / 25 = 5 100 + 5 = 105 8 - 1 = 7 105 x 7 = 735 In the second numbers round, I had an alternative to the contestants' solution: 100 + 10 = 110 110 x 7 = 770 770 + 75 = 845 845 + 6 = 851 In the third numbers round, I saw Tom's solution, but I also had an alternative based on factoring the number and on an unusual fact that not even a lot of regular players of four-large games know. The number factors down to 67 x 7 x 2 = 938, and the odd coincidence is that 67 is one of the few largish numbers that isn't a multiple of 25 that you can make using just the four large numbers: 100 x 50 = 5000 5000 + 25 = 5025 5025 / 75 = 67 10 + 4 = 14 67 x 14 = 938 In the final numbers round, it seemed to me that Tom made the solution needlessly complex when he could have done this: 75 + 7 = 82 82 x 10 = 820 3 - 2 = 1 820 + 1 = 821
In the first numbers round, I had an alternative solution for 2 away:
75 + 50 = 125
125 / 25 = 5
100 + 5 = 105
8 - 1 = 7
105 x 7 = 735
In the second numbers round, I had an alternative to the contestants' solution:
100 + 10 = 110
110 x 7 = 770
770 + 75 = 845
845 + 6 = 851
In the third numbers round, I saw Tom's solution, but I also had an alternative based on factoring the number and on an unusual fact that not even a lot of regular players of four-large games know. The number factors down to 67 x 7 x 2 = 938, and the odd coincidence is that 67 is one of the few largish numbers that isn't a multiple of 25 that you can make using just the four large numbers:
100 x 50 = 5000
5000 + 25 = 5025
5025 / 75 = 67
10 + 4 = 14
67 x 14 = 938
In the final numbers round, it seemed to me that Tom made the solution needlessly complex when he could have done this:
75 + 7 = 82
82 x 10 = 820
3 - 2 = 1
820 + 1 = 821