ไม่สามารถเล่นวิดีโอนี้
ขออภัยในความไม่สะดวก

7: Wronskian Determinant - Dissecting Differential Equations

แชร์
ฝัง
  • เผยแพร่เมื่อ 4 ก.ย. 2024

ความคิดเห็น • 25

  • @MuPrimeMath
    @MuPrimeMath  4 ปีที่แล้ว +4

    If you aren't familiar with how the determinant relates to linear independence, check out my video on determinants: th-cam.com/video/A9eJdQt5quw/w-d-xo.html

  • @bijoythewimp2854
    @bijoythewimp2854 2 ปีที่แล้ว +2

    This guy's video's always wipe my math tears and leaves youtube happily.

  • @omegapolar1355
    @omegapolar1355 3 ปีที่แล้ว +3

    An amazing explanation of the concept.Thank You!

  • @MrMyutubechannel
    @MrMyutubechannel 4 ปีที่แล้ว +1

    Was looking for the intuition about how this works. Thank you for the awesome explanation! Good video

  • @shandyverdyo7688
    @shandyverdyo7688 4 ปีที่แล้ว +7

    Hey, sometimes please to make a video about green's function and its application
    For ODE and PDE.
    It's a very rare topic on TH-cam.

    • @soccerbels7947
      @soccerbels7947 2 ปีที่แล้ว +1

      Ye unfortunately, the higher you go in math the hardest is to find resources

  • @agnespalfi6162
    @agnespalfi6162 8 หลายเดือนก่อน

    Incredibly helpful, thanks a lot!

  • @souvikroy9599
    @souvikroy9599 3 ปีที่แล้ว +1

    How to use Wronskian to check linear dependence of functions with more than 1 variable?
    Should we use partial derivatives in the matrix for different variables??

  • @schweinmachtbree1013
    @schweinmachtbree1013 2 ปีที่แล้ว +1

    0:56 homogeneous linear*

  • @rodrigo454
    @rodrigo454 4 ปีที่แล้ว +1

    Awesome explanation! Tks

  • @tiaanjansevanrensburg2762
    @tiaanjansevanrensburg2762 3 ปีที่แล้ว +1

    Damnnn you are awesome, Thank you.

  • @tgeofrey
    @tgeofrey 2 ปีที่แล้ว +1

    Thank you

  • @user-nr5tp2jo3u
    @user-nr5tp2jo3u ปีที่แล้ว

    Wronskian Determinant is only working for differentiable functions. It doesn't for continous functions, therefore wee must know other ways to define linear dependence.

  • @adialex1000
    @adialex1000 4 ปีที่แล้ว +2

    the absolute function is not differentiable everywhere, So how can we differentiate it?

    • @MuPrimeMath
      @MuPrimeMath  4 ปีที่แล้ว +7

      We can differentiate it everywhere except for at 0 and only consider those values!

    • @adialex1000
      @adialex1000 4 ปีที่แล้ว +1

      @@MuPrimeMath thanks for the video and the quick reply you have been very helpful!

    • @schweinmachtbree1013
      @schweinmachtbree1013 2 ปีที่แล้ว +1

      the example doesn't work. but if you multiply both functions by x, giving x|x| and x^2, then you get a correct example (because x|x| = sgn(x) * x^2 is differentiable, unlike |x| = sgn(x) * x)

    • @MuPrimeMath
      @MuPrimeMath  2 ปีที่แล้ว +3

      @@schweinmachtbree1013 that's a great example!

  • @MathPhysicsFunwithGus
    @MathPhysicsFunwithGus 4 ปีที่แล้ว +1

    GREAT VERY HELPFUL

  • @Invalid571
    @Invalid571 4 ปีที่แล้ว +1

    What if one of our equations, lets say g(x), is equal to e^x?

    • @MuPrimeMath
      @MuPrimeMath  4 ปีที่แล้ว +2

      It's still possible for the Wronskian to be nonzero in that case!

  • @mnasm007
    @mnasm007 3 ปีที่แล้ว +1

    Awesome

  • @jrbros2371
    @jrbros2371 ปีที่แล้ว

    More vids pls 🥺

  • @AmeerHamza-cy6km
    @AmeerHamza-cy6km 3 ปีที่แล้ว +1

    how u solve for x, x-1, x+3

    • @redwanburkan4790
      @redwanburkan4790 ปีที่แล้ว

      Well, u can first start with computing the wronskian. You will get 0 as a result and that's bcuz u have the third row to be zeros
      However, we cannot yet conclude whether they're dependent or independent unless we check if their constant multiple can be zero.
      And fortunately, they can be!
      Because if you try to multiply the first function by 4, the second function by -3 and the third one by -1, then you'll end up having zero ✨