ROC and its Properties
ฝัง
- เผยแพร่เมื่อ 7 ก.ย. 2024
- Signal & System: ROC and its Properties
Topics discussed:
1. Definition of Region of Convergence (ROC).
2. Properties of Region of Convergence (ROC).
3. ROC of right-sided signals.
4. ROC of left-sided signals.
5. ROC of both-sided signals.
6. ROC of finite duration signals.
Follow Neso Academy on Instagram: @nesoacademy(bit.ly/2XP63OE)
Follow me on Instagram: @sujeetsingh20(bit.ly/2JLcQz5)
Contribute: www.nesoacademy...
Memberships: bit.ly/2U7YSPI
Books: www.nesoacademy...
Website ► www.nesoacademy...
Forum ► forum.nesoacad...
Facebook ► goo.gl/Nt0PmB
Twitter ► / nesoacademy
Music:
Axol x Alex Skrindo - You [NCS Release]
#SignalAndSystemByNeso #Signal&System #LaplaceTransform #ROC
![Warhammer 40k: Space Marine 2 | เพื่อจักรพรรดิ ! [ตอนเดียวจบ]](http://i.ytimg.com/vi/4M0ckYMA4-U/mqdefault.jpg)
00:09 Laplace Transform and Fourier Transform are unique properties of a time domain signal
01:24 Region of convergence (ROC) is the range of complex variable where a Laplace transform is finite or convergent.
02:46 ROC is the range of complex variable s in which the Laplace transform is finite or convergent.
04:11 Poles are not included in the ROC of a Laplace transform.
05:32 The region of convergence is on the right side of the rightmost pole.
06:51 The region of convergence for left-sided signals exist on the left side of the leftmost pole.
08:12 ROC for both sided signals is a strip in the s-plane
09:35 ROC for finite duration signals is the entire s plane excluding s=0, s=+∞, and s=-∞
01:24 Region of convergence (ROC) is the range of complex variable where a Laplace transform is finite or convergent.
02:46 ROC is the range of complex variable s in which the Laplace transform is finite or convergent.
04:11 Poles are not included in the ROC of a Laplace transform.
05:32 The region of convergence is on the right side of the rightmost pole.
06:51 The region of convergence for left-sided signals exist on the left side of the leftmost pole.
08:12 ROC for both sided signals is a strip in the s-plane
09:35 ROC for finite duration signals is the entire s plane excluding s=0, s=+∞, and s=-∞
hi sir, please increase the voice quality, I can't hear ur voice clearly without earphones. and I always watch all your videos on 1.5x speed as it feels a little slow for me , but the content is really great and to the point.
Lol;-)
I watch them on 2x
Correct
@@vikramrajput76 same😉🙌
sir, you are explaining nicely in theory. But it is signals and system so I would like to request you to explain it in practically also
Physically realizable systems are causal and so a right handed signal can described their impulse response. So here ROC is the right side to the right most pole as he states in 2. That is probably the most important point.
hi, i like your intonation and the way how you explain the properties . Thx !
Hopefully sir you will be able to finish Discrete Time Signals by September because that's when I will take this course!
Sir,please explain for stability,why jw axis should be included?
because it implies sigma=0, then f(t)*exp(-sigma t) is absolutely integrible can be said as f(t) is absolutely integrible, that is the criterion for stablity
I thought for the ROC to be BIBO stable, it cannot include the jw axis?
Thank you sir.....it is more help full for me...
In 3rd property also roc doesn't include imaginary axis. Then,how Laplace transform exists??
Very informative sir 🙌🙌
Why should we exclude zero in the last property of roc?
Is the above ROC. Concept same for Laplace and fourier transform!
Fourier Transform is a special case of Bilateral LT. FT exists only for stable signals and is always unique therefore the concept of ROC is not required in FT.
Thanks Sir🙏🙏
So helpful
Thank you sir
Laplace Transform converges (gives finite value) in ROC. How is this information (the finite value of LT) help us anyhow?
Thanks
Nesoacdemy which book should we follow for signal and systems??
Swarup Das
signal and sys. by
ramesh babu or sanjay sharma ......
Why for finite length signal, roc doesn't include s=0?
This is because we factorize denominator to get poles. If s=o means the Laplace transform of the function will be1/s . In that case if we substitute s=0 in 1/s we get 1/0=infinity . according to the definition of roc , it lies only when lt is finite . So roc doesn't exist for s=0
Sir when will you upload the videos for z transform of signal and system
Periodic signals are integrated from 0 to T (time period) to derive LT. What is the ROC of such signals? The entire s-plane?
yes...entire s plane
4th and sixth property are the same... or is there any difference in it? For me it resembles the same
But the discrete impulse has the ROC as the entire s plane....It doesn't satisfy ur last property...Reason plz sir...
Why w(omega) is not included to find roc?
sir aap kya op amp loic familes microprocessors k vdo ni doge
Sir,what is the role of jw in signal of y(t)
What is the ROC of an impulse signal ?? Which is a finite duration signal
Entire S plane, because LT of Impulse is 1 and there is no point on s-plane where the LT can become infinite.
what if 3 roots or poles which strip to choose
Sir when will be sampling completed
❤❤❤❤❤❤
does anyone know how to solve this with steps thank you:
The system function of a system is H(z)=(1-7z^(-1)+5z^(-2))/(1+0.5z^(-1) )(1-5z^(-1)+6z^(-2) ) .
(a) Find all possible ROCs for this system.
(b) For each ROC from 2.(a), find the impulse response h[n] of the system.
(c) For each ROC from 2.(a), find if the system is (i) causal, and (ii) stable.
this video is about laplace transform, not z transform
In property 2 u included the poles
How can u include
In roc no poles should be there
Please reply
Last two properties are not able to understand
Low volume
boriggggggggggggggg