Sal, you are the absolute man, I mean it. You came up with this idea for a free online school for anyone, and look what you've done with it! Amazing. I am very impressed sir, and I appreciate it! One question: When will I actually be able to get a post-grad degree in Math on KA? Peace man.
I am so grateful for this video. I have a test tomorrow and i finally understand what i am having to do for finding these equations. Thank you again!! Big help
Khan Acadamy: "I hope you enjoyed that." Why yes I did. I was pretty psyched when I was following along and finally getting the concept. Thank you very much, good sir!
Perhaps a more efficient way of determining the equation of a line given two points is by using a method from Vedic Mathematics. Using this method, we can determine the equation of a line from two points immediately without the need to write any down besides the answer. The method is as follows: given two points (a , b) and (c , d), determine the equation of the line going through these two points. The solution is as follows: (a - c)*y = (b - d)*x + (ad - bc) The method is fast and efficient. What do you think?
That's a great explanation you made us all understand but the -8 is suppose to be a +8. It's finding the difference between the 2 points so it would be 9-1= 8
I have only just read this reply. He is not using the point-slope to describe y=mx+c; he is using it to describe another form of a linear equation which has the 'point' and 'slope' contained in it. It is a lot clearer using the point-slope term when referring to this form of the linear equation in virtue of having the point and slope in it. There are several different forms of the linear equation: point-slope formula, the slope-intercept formula, and the standard form of a linear equation. All these names inform what type of linear equation it is, so we can use the appropriate one with the information we are given.
I fail almost every test in math (I'm in advanced although I shouldn't) and these videos have really helped me with that. Still probably need to go into standard math but I'm glad that these videos exist for people who need it. Thank you Khan Academy, for teaching me better than school ❤️
you don't always have to do both points on the graph you can do either one and it would still be the same equation if you did it for (6,1). even if you did both problems you would get the same answer for both equations.
Just Some Guy With A Ultra Instinct Mustache same my other classmate's are passing. It I just hope I don't get kicked out or else 1 EXTRA HOUR OF SCHOOL FOR NOTHING.
I was absent for a few days and was lost for weeks on the subject, this guy just helped it click.
Forsaken Plays same
Same
Same
same
SAMEEEE
I need you to like, come to my house and teach me everything in algebra
Sal, you are the absolute man, I mean it. You came up with this idea for a free online school for anyone, and look what you've done with it! Amazing. I am very impressed sir, and I appreciate it! One question: When will I actually be able to get a post-grad degree in Math on KA? Peace man.
Oh my gosh I’m in 8th grade advance geometry and I couldn’t remember how to do this, thank you so much
I am so grateful for this video. I have a test tomorrow and i finally understand what i am having to do for finding these equations. Thank you again!! Big help
Is anyone else here just because they have a test the next day?Because I am.
i hope you aced that test
Notorious Big T H I S M U S T BE T H E W O R K O F A N E N E M Y S T A N D
Yeah, just a year later. I have a test tomorrow :(
A Window yeh good luck man hope you pass it
Im here because I have a progress assesment in like 2 hours
Khan Acadamy: "I hope you enjoyed that."
Why yes I did. I was pretty psyched when I was following along and finally getting the concept. Thank you very much, good sir!
thanks. understand the concept much better now.
In ninth grade and I still need help on this 😭
Thanks for the help
Samee bro same.
4th year university and I still need help in this
thanks that help a lot 😊😊😊👍🏻👍🏻
Thanks I have a algbera test on friday algbera super hard. I hope I pass it I have to have 80% or higher cause I failed the last two. :/
I mean I didn't enjoy it but I understood so thank you!!
Perhaps a more efficient way of determining the equation of a line given two points is by using a method from Vedic Mathematics. Using this method, we can determine the equation of a line from two points immediately without the need to write any down besides the answer. The method is as follows: given two points (a , b) and (c , d), determine the equation of the line going through these two points. The solution is as follows: (a - c)*y = (b - d)*x + (ad - bc) The method is fast and efficient. What do you think?
That's pretty cool. Thank you :D
Thank you so much was about to fail bringing my grade back up
Great Explanation !!!
We could probably give the glorious team that made this possible all the riches in the world and it wouldn't be as much as they deserved.
This is going to help me on my test today thanks a lot it’s very useful
very helpful
Thanks!!
That was helpful
That's a great explanation you made us all understand but the -8 is suppose to be a +8. It's finding the difference between the 2 points so it would be 9-1= 8
Ricky Williams It’s the second Y minus the first, so negative 8 is correct
Thank you!!!!!
hey bro you are the best u have no idea how much you helped me. please keep on
Bro I was so confused but thanks, I’m very great full
I wish u were my teacher tbh
me too ...
Can you do another example? bc I don’t get it
Clifton Morlan same
thank you math lord
"Oh shit I forgot to label the x axis " 😭😭
This comment should have more likes
heard that. xD
Lmao
Where???
this going to help a lot tomorrow thank you
Tank u
Some of the language used here is completely different to that used in British schools, confused me for a bit
Alex Jones What parts in particular?
For example we never use the "point-slope" phrase to describe the y=mx+c, we would just say it's the simple form for the equation of a linear graph
martyspandex also we would just say "gradient" when describing the slope, although that might be a simplification
that's just British vs US, like use using analyze vs analyse... hope you understand what I am trying to say :)
I have only just read this reply.
He is not using the point-slope to describe y=mx+c; he is using it to describe another form of a linear equation which has the 'point' and 'slope' contained in it. It is a lot clearer using the point-slope term when referring to this form of the linear equation in virtue of having the point and slope in it. There are several different forms of the linear equation: point-slope formula, the slope-intercept formula, and the standard form of a linear equation. All these names inform what type of linear equation it is, so we can use the appropriate one with the information we are given.
what if the slope = 0/number
That would be a slope of 0, a horizontal line. Not to be confused with a vertical line or undefined slope.
Thank you, the exam is tomorrow, and you saved my life!
Did anyone else see the smiling face made out of the equal sign and the delta sign?
57 Guy lol yes
57 Guy it's actually just supposed to be an arrow
sir can you pls share the video of various forms of straight line topic of analytical geometry
What is the third point in the system of linear equations? My Algebra book doesn't tell me, but I really need to know for the exam!!
did you pass it?
@@biffydonk2539shit idk if its of much importance 4 years later when you commented
I fail almost every test in math (I'm in advanced although I shouldn't) and these videos have really helped me with that. Still probably need to go into standard math but I'm glad that these videos exist for people who need it. Thank you Khan Academy, for teaching me better than school ❤️
My exam is just in 1 h and I'm here to review this chapter.
im confused still... do you only use one of the points that was given? what does the formula to this look like? how do i know when to use it?
Why didn't he use the second point on the axis (x=6, y=1) ?
It works out to the same: y=-4x=25
you don't always have to do both points on the graph you can do either one and it would still be the same equation if you did it for (6,1). even if you did both problems you would get the same answer for both equations.
What app do you use
i would suscribe but i dont want spam
I don't understand anyting
what software are you using?
whos here becasue they are doing a test and didn't pay attention
But how do you do it with 1 point and 1 slope
Algebra I... I feel so dumb.
Just Some Guy With A Ultra Instinct Mustache same my other classmate's are passing. It I just hope I don't get kicked out or else 1 EXTRA HOUR OF SCHOOL FOR NOTHING.
Oof... thx
Anyone else from mrs. d in 8th grade algebra? If so, pog
i have no clue who mrs d is but u said pog so u must be a cool person
i’m also in 8th and i have no clue what’s happening rn hdjcrjg
i am readdy to pay anything for your personal teaching
What?
Is anyone here because the guy on edgenuity was trash at explaining? No? Just me? ok..
that's exactly why i'm here 😭😭
my brain hurts
Not helpful at all this one, You didn't explain the Equation form
HiddenPotential Aj it's easy to figure out standard form from these forms (if you meant standard form). Also, all of the forms are equations
my brain is bleeding.
Why does it have to look complicated
you literally. don’t make any sense at all. you just ramble and it gets so confusing