I m sorry to say but In this lecture there is a mistake in it In type 3 question,during writting the equation of voltage for supermesh- there should be the equation as follows -i1-i1-2i1-3(i2-i3)+1+2=0 But your equation is -i1-i1-2i1-3 (i2-i3)-1+2=0
At 21:36 second you said +1 but write -1 and it should be +1 over there as the current moves from negative to positive side of potential ..... All concepts learn from you. 😁 Thank you sir
Hello sir!!! Aap to cha gye sir dilo jaan m Ye Jo aapki style h n baar baar main concept ko repeat krne ki mujhe bhut accha lga Because if any one listening one and more period basic concept then there are no necessary to read again Like type 1 me current source ka n hona Type 2 current source ka hona bt outerside Type 3 current source lies between innerside Maza aa gya sir Respected sir humlog aapke totally lecture dekhte h O alg baat ho gai ki saro m comments n kre ho Thanks sir
@@axysahil2897 sir if question asks current then we had to put negative sign over there plzz tell me i m confused .....I think the current is I=-1.3amp.
Sir there is one mistake video timing (3 in question) 21:50 you should written voltage rise cases according -1+2 according me +1+2 I hope that's write me
Sir I was in Fear before watching your lectures.. I could fail in electrical . But after watching your lectures, now I can say proudly that I will be pass in electrical and will get good marks. Your teaching way is so amazing for freshers. Everybody can score good marks easily after watching your video..... Tq so much sir
क्या गजब का पढ़ाते हो सर आप। जो पढ़ाते हो सारा समझ में आ जाता है, सारा कॉन्सेप्ट समझ में आता है। ऐसे ही हम लोगो पर कृपा बनाए रखना सर🙏🙏 सर का कृपा बना रहे तो लोगों का जोव पक्का 🙏🙏
Solution of the type 3 question is V=3.81 Volts.... Plz do a small correction which sir probably missed that is after applying the super mesh principle the equation will be : -i1 -i1 - 2i1 - 2i2 - 3(i2 - i3) "+" 1 + 2 = 0 Solving this you'll get -4i1 -5i2 +3i3 =-3
Salute sir... U are empowering इंडिया....but must complete all module.. At our time no study material available except book.. But it is a pure class lecture
@21.25...-1i1-1i1-2i1-2i2-3(i2-i3)+1+2=0 i.e. -4i1--5i2+3i3=-3 this is right And Final Ans.i1=-1.8A i2=3.2A i3=1.93A....... Voltage(3ohms)=(3.2-1.93)×3=3.81V
Thanks a lot mr.Ranjan rai sir. you did that which my faculty was not able to do. The way you explain😍 Last two semesters I was skipping part of, KVL, Superposition and Thevenins, but i saw your videos last day, and today was mine exam. And did the things perfectly . thanks a lot for such wonderful work.
I always confused in these questions .................. but after surfing here my all confusion has gone😊 very good way of teaching ... headsoff to you sir🥰
Sir i dntt know how I saw this video actually I have got backlog in bee and now I saw ur video and today I am getting everything about bee. Thank u so so muchhhh for all these videos.. I have no wordssss😊😊😇😇😇😇. Love from kashmir
I used to think BEE is a tough subject until I saw this sir explaining it..Tomorrow is my BEE exam and iam sure I can score good marks in it..only because of this sir........ Thank you Sir.. You are doing a great job !!
In super mesh equation, we have to take +1 instead of -1, Because current flows from lower potential to higher potential so its like that. Anyone looking at the comments at 22:20 . If yes your right dude 😎
THANKS ALOT SIR THIS VIDEOS R VERY HELPFUL FOR US TO UNDERSTAND THE BASIC CONCEPT. SIR MY HUMBLE REQUEST TO PLEAST MAKE VIDEO SUCH TYPE OF CKT. WHICH INCLUDE RESISTANCE, INDUCTOR ,AND CAPACITORS AND DEPENDENT SOURCE AND WE HAVE TO FIND * I* IN CKT PLEASE SIr
In type 3 question,during writing the equation of voltage for supermesh- there should be the equation as follows -i1-i1-2i1-2i2-3(i2-i3)+1+2=0 But your equation is -i1-i1-2i1-3(i2-i3)+1+2=0
Doubt: In mesh 3 if there is a resistance in series with current source can we use source transformation and convert it into voltage source in mesh analysis?
Sir, we are here to know the unknown chapters, your explanations are really good but please calculate correctly, there are many wrong calculation in this and as well as previous lectures, but as we all human, we all are not so perfect, but please mention the wrong part while editing, sometimes it's get so difficult and had many wastage of time to find whether I am wrong or you. So please atleast mention it while editing. Thank you
Sir ap hazar saal jiyo ist time I got these topics...love u sir and big thanks to gate academy u truly r great persons sitting in there.....but sir in this video u made a mistake plz look upon it otherwise confuse ho jte hai
sir there is a mistake i n solution of type three question we have to add the voltage that is (+1+2)=+3 but unfortunately you can write (-1+2) please correct it 🙏🙏🙏🙏🙏🙏🙏🙏
Sir is absolutely correct here! YOU GUYS HAVE PROBLEM IN BASICS! Suppose you don't remove that current source; let it be there . Now, write the individual equations mesh 1 gives: -4i1 + 2=0 mesh 2 gives: -5i2 + 1+ 3i3 =0 mesh 3 gives: -6i3 + 2 + 3i2=0 And also i2 - i1 =5 Now we want i1,i2 and i3 such that all 4 above equations hold true. So, we are adding mesh 1 and mesh 2 equations to reduce the number of equations. Now ,THIS LEADS TO CONCEPT OF SUPERMESH! so from super mesh (mesh 1+mesh 2) we get, -4i1 -5i2 + 3i3 +1 +2=0 if you liked it then then consider donating money not likes!🤣
I m sorry to say but
In this lecture there is a mistake in it
In type 3 question,during writting the equation of voltage for supermesh- there should be the equation as follows
-i1-i1-2i1-3(i2-i3)+1+2=0
But your equation is
-i1-i1-2i1-3 (i2-i3)-1+2=0
Yes
Yess
Of course
Amar Kumar yes yes yes
Yes
At 21:36 second you said +1 but write -1 and it should be +1 over there as the current moves from negative to positive side of potential .....
All concepts learn from you. 😁
Thank you sir
Bro sir padhate bht acha hai but har vdo me koi na koi silly mistake kardete hai lekin cmnt me bacche sahi kardete ...just like u 😅
Bhai bola galat hai par likha correct hai
@@abhishekdm5548 how reason ??
Yes I am also notice that 😁
@@abhishekdm5548no no
God bless you gate academy, for helping those who can't afford good classes in bad clges and due to lack of Mone...but have hunger for knowledge
if u r in bad clg that itself means u r not up to the mark
@@smarthguy_1719 yes exactly
@@smarthguy_1719 seriously??
@@smarthguy_1719 seriously🤔🤔🤔🤔,???
RIGHT BRO
Last year, I was surfing Physics Wallah's videos for my boards and now here I am.
lol... same same XD
Same here
Same bhai aap kis clg se ho 😂
So are you in the first year by the way which college I have also studied from physics wallah
@@shailandrakumarsharma9593 from rec sonbhadra 👍 and u
Currently in 1st yr CSE of NIT Durgapur and still i rely upon these excellent lectures in yt.
feeling PROUD to have him as my Class incharge!
You are from which clg
Bada hi taqdeerwala hai bhai
Bro which college you are from
FEKNE KA PAISA THORI LGTA HAI😂
Hello sir!!!
Aap to cha gye sir dilo jaan m
Ye Jo aapki style h n baar baar main concept ko repeat krne ki mujhe bhut accha lga
Because if any one listening one and more period basic concept then there are no necessary to read again
Like type 1 me current source ka n hona
Type 2 current source ka hona bt outerside
Type 3 current source lies between innerside
Maza aa gya sir
Respected sir humlog aapke totally lecture dekhte h
O alg baat ho gai ki saro m comments n kre ho
Thanks sir
i1= -1.8 amp, i2 = 3.2 amp, i3 =1.93 amp, Voltage(3 ohm resistance) = 3.81 volt
Voltage is in 3 ohm resistance is 3.9 volt
Resultent current I =3.2-1.9=1.3
Then v =ir
@@axysahil2897 you are right sir
@@axysahil2897 sir if question asks current then we had to put negative sign over there plzz tell me i m confused .....I think the current is I=-1.3amp.
Correct✅✅
Sir there is one mistake video timing (3 in question) 21:50 you should written voltage rise cases according -1+2 according me +1+2 I hope that's write me
yaaa i was here for the same
Correct brother
Sahi pakdre hai 21:47
corrct
Yess
Sir I was in Fear before watching your lectures..
I could fail in electrical . But after watching your lectures, now I can say proudly that I will be pass in electrical and will get good marks.
Your teaching way is so amazing for freshers. Everybody can score good marks easily after watching your video.....
Tq so much sir
So did you pass ?
Bhai paas hue ??
SIR IN EQUATION 2ND THE CONSTANT VALUE WILL B -3 INSTED OF -1.
Yes brother
Yes bro there is mistake
it will be positive 3 as voltage is going from positive to negative
@@liebermen2369 yes..
In rhs it is -3
@@hcoonamatata1079 exactly
क्या गजब का पढ़ाते हो सर आप। जो पढ़ाते हो सारा समझ में आ जाता है, सारा कॉन्सेप्ट समझ में आता है। ऐसे ही हम लोगो पर कृपा बनाए रखना सर🙏🙏
सर का कृपा बना रहे तो लोगों का जोव पक्का 🙏🙏
Solution of the type 3 question is V=3.81 Volts.... Plz do a small correction which sir probably missed that is after applying the super mesh principle the equation will be :
-i1 -i1 - 2i1 - 2i2 - 3(i2 - i3) "+" 1 + 2 = 0
Solving this you'll get -4i1 -5i2 +3i3 =-3
Correct
Ye sahi h
Thanks
Han mujhe bhi laga ASA hi
Thanks
Pichli video m bhi galti kar diya tha sir ne lol
U are literally doing grt work.... India needs teachers like you... Hats offf to you for your work...✌✌✌✌
Salute sir... U are empowering इंडिया....but must complete all module.. At our time no study material available except book.. But it is a pure class lecture
@21.25...-1i1-1i1-2i1-2i2-3(i2-i3)+1+2=0
i.e. -4i1--5i2+3i3=-3 this is right
And Final Ans.i1=-1.8A
i2=3.2A
i3=1.93A....... Voltage(3ohms)=(3.2-1.93)×3=3.81V
sir i think you have to write +1 instead of -1 because of potential rise in supermesh eqnation for 2nd loop
Absolutely
yes +1+2=+3 so it will be -3
Yes bro. even I was about to write this
blessed to have a teacher like you for exams in university
The best teacher for BEEE i came across🔥🔥.Thank you so much sir🙏
in last years, which teachers u found as best for every subject?
Kasam se bol raha hun, itna achha koi nhi padhata. Dil se sadar charan sparsh Gurudev ❤❤❤.
Thanks a lot mr.Ranjan rai sir.
you did that which my faculty was not able to do.
The way you explain😍
Last two semesters I was skipping part of, KVL, Superposition and Thevenins, but i saw your videos last day, and today was mine exam.
And did the things perfectly .
thanks a lot for such wonderful work.
I always confused in these questions ..................
but after surfing here my all confusion has gone😊
very good way of teaching ...
headsoff to you sir🥰
Sir in the forming of supermesh eqn the source voltage sign is +1V and +2V ..
Due to lower to higher potential
You are right
yes bro
preparing for my 1st sem exams
Sir i dntt know how I saw this video actually I have got backlog in bee and now I saw ur video and today I am getting everything about bee. Thank u so so muchhhh for all these videos.. I have no wordssss😊😊😇😇😇😇. Love from kashmir
I used to think BEE is a tough subject until I saw this sir explaining it..Tomorrow is my BEE exam and iam sure I can score good marks in it..only because of this sir........
Thank you Sir.. You are doing a great job !!
same bhai
Kitne marks aaye bro
got my BEEE first semester exam next week these videos seems to be so useful, thanks
You're doing a great job sir
Wishing everyone good luck !🖐
sir thnx ...
saare doubts chale gye....waaah waaahh...sir kya padate hai...liked his every video...
The way of teaching is easy to understand
Mr.Ranjan Rai sir❤️
Thank you sir
Increasing our abilities....👍
22:15 +1 will be there coz there's no voltage drop in that 1V source
Yess...
Shi
Amazing lecture sir . Lots of love and respect form odisha.
Thank you ranjan sir, you made electrical so easy for me. Wish i could get teacher like you.
Dear sir, you are great teacher, you explain all deep concepts thats why i love you.
GATE ACADEMY is really a great and quite fruitfull intiative
In super mesh equation,
we have to take +1 instead of -1,
Because current flows from lower potential to higher potential so its like that.
Anyone looking at the comments at
22:20 .
If yes your right dude 😎
Right please provide me the answer I1= -1.8A, I2= 6.8A, I3= 3.73A AND THE REQUIRED VOLTAGE= 9.21V PLEASE REPLY
The thing I felt difficult in college but after seeing this video if feel that it is very simple 😀
yes sir nice
Thanks gate plus
For providing us a wonder ful learning experience free of cost
Again thanks
Sir Pls not seen due to very small write
Current through 3 ohm resistance will be i2-i3= 3.2-1.93= 1.26
From pw hand gloves to Gate academy ❤❤❤ what a journey
Both videos are great on describing the basic. Sir, Thanks a lot!
❤ well i was very poor in electical basics ......now ig i understand it a lot ....THANK YOU SIR
A very great method of teaching very smooth and very easy to understand and apply thanks sir😁
what an explanation....🤔clear all network doubts with just two lectures..
At 21:50,,,sir u wrote -1 instead of +1
kamran qureshi yes.. u can correct that mistake.. unknowingly i did that..
Yes
@@ranjanrai9408 hello sir
21:37
Yes i also have the same question
Thank you sir helping not only student of India but also to the student of nepal❤❤
My college teacher Ranjan sir
My BEE teacher blessed to have you sir
Which college??
Sir apne dil khus kr diya itne achhe se smjha kr
Ranjan sir , you are great🙇 thank you a lot sir😇
Sabse achha apki dual languge (Hindi and English) me teach karana achha lagta h. Thanks sir
Keep Up the Brilliant Work......Thanks, Gate Academy
nice video for basis concept to all student Junior and Senior who prepare of competition.
At time 21:37 in this the sing taken is wrong of 1V you have taken negative instead of positive
Chulbul😂 listen sir's lecture carefully what he said and what he write..
i1= -1.8amp,I2= 3.2amp,I3= 1.933amp
Thanks for this lecture sir
Will you please tell me how to get ans for I1, I2 and I3
अकॉर्डिंग टू द लेक्चर एनालिसिस सरूर answer is correct
Understand
This video is very important for electrical engineering
Very nice video
THANKS ALOT SIR
THIS VIDEOS R VERY HELPFUL FOR US TO UNDERSTAND THE BASIC CONCEPT.
SIR MY HUMBLE REQUEST TO PLEAST MAKE VIDEO SUCH TYPE OF CKT. WHICH INCLUDE RESISTANCE, INDUCTOR ,AND CAPACITORS AND DEPENDENT SOURCE AND WE HAVE TO FIND * I* IN CKT
PLEASE SIr
For network theory u r even better than dhande sir... superb video
Who's watching in 2024😂
Me
😅
Not a single ad promotion ....salute sir
Stay blessed sir u are awesome ❤❤❤
best teacher of Electrical
I will surely try to get full marks in electrical 😼
Tq sir🙏. There are no one better than you. It's help me a lot to understand BEE.
amazing sir !! helped me out a lot in understanding the concept, make more of videos of Ac circuits and remaining chapters, please
Sir you are fab❤️
You made it so easy to understand 🙏🏻
Real ma sir aap bahut esi mathar se padate ho
Thank to this open platform, hope you continue like this !
Very good teaching style sir thank u so much
21:38 par +1 hoga sir ne bola bhi hai issa but likhne time galat ho gaya so aap log jitne bhi ye video dekhiyega to confuse nahi hoiyega 🙏
realy very very nice lecture sir
aapki jitni taarif ki jaye wo kam hi parega
tough ive spotted a minor mistake of type 3 Q in 2nd eqn. sir
yet i would like 2 say .u are gr8.❤
you goin clearin up in detail with concept.
Sir type 2 question mere liye hard tha lekin ap batheye pura clear hogaya thankyou so much sir
Sir aap hamare IIT professor se bhi achha padhate ho🥰🥰🥰🥰🥰😜
Its soo helpful for me brillent lecture thanku gate academy😊
A lot of thank you ,god bless you
In type 3 question,during writing the equation of voltage for supermesh- there should be the equation as follows
-i1-i1-2i1-2i2-3(i2-i3)+1+2=0
But your equation is
-i1-i1-2i1-3(i2-i3)+1+2=0
Ha voltage ko -1 liya hai
Yes yes barobar
Sir, "gate academy plus" चैनल pe basic electrical engineering subject के video जल्दी बनाइए. तो Network subject easy हो जाएगा gate के लिये.
Mayur Shirude yes we r on it
@@ranjanrai9408 sir aap bhut acha padhate hai.. Kash ap jaise teacher har college me hote
@@Stoicbanda sahi yaar
wah ab bee ki koi tension nhi....❤️😌😌❤️
Sir At 21:47 there should be +1 V
Concept is clear 💯
amazing sir !! helped me out a lot in understanding the concept, make more of videos of DC circuits and remaining chapters, please
1
You are great man sir. Excellent video.
Doubt: In mesh 3 if there is a resistance in series with current source can we use source transformation and convert it into voltage source in mesh analysis?
Yess
at 21:35 in 2nd mesh it is the case of voltage rise so voltage will be +1V
Type 3:
I1 = -1.8A
I2 = 3.2A
I3 = 1.933A
Now,
I' = 1.267A
Sir are theses values correct
i2=3.199 A aa raha h baki to same h
I'=1.266A
@@anjaliverma9344 3.199~3.2 both are correct
@@sandeshrestha_ yo bro🤟
Sir apke...padhane...ka style bahut acha laga
Supermesh topic is not clear. Sir plz make a another video for this topic...plz..
Thank you 😊
Yes sir
Dhanyawad sir♥️
Sir 21:36 aap ne +1 bola aur -1 likha 🙄🙂
Same dout bro
efforts made by camera man 🔥🔥🔥🔥🔥🔥🔥🔥
Sir, we are here to know the unknown chapters, your explanations are really good but please calculate correctly, there are many wrong calculation in this and as well as previous lectures, but as we all human, we all are not so perfect, but please mention the wrong part while editing, sometimes it's get so difficult and had many wastage of time to find whether I am wrong or you. So please atleast mention it while editing. Thank you
Sir ap hazar saal jiyo ist time I got these topics...love u sir and big thanks to gate academy u truly r great persons sitting in there.....but sir in this video u made a mistake plz look upon it otherwise confuse ho jte hai
Sir, why -1v is taken instead of +1v ? please clarify.
same here bro, in Q3
Amazing explanation sir 🔥🔥
Sir age ka lectures v upload kijiye......plzz sir
really nice way of explanation 😀
sir there is a mistake i n solution of type three question we have to add the voltage that is (+1+2)=+3 but unfortunately you can write (-1+2) please correct it 🙏🙏🙏🙏🙏🙏🙏🙏
Yes I was also confused here. +3 is correct, right?
Sir is absolutely correct here!
YOU GUYS HAVE PROBLEM IN BASICS!
Suppose you don't remove that current source; let it be there .
Now, write the individual equations
mesh 1 gives:
-4i1 + 2=0
mesh 2 gives:
-5i2 + 1+ 3i3 =0
mesh 3 gives:
-6i3 + 2 + 3i2=0
And also i2 - i1 =5
Now we want i1,i2 and i3 such that all 4 above equations hold true. So, we are adding mesh 1 and mesh 2 equations to reduce the number of equations. Now ,THIS LEADS TO CONCEPT OF SUPERMESH!
so from super mesh (mesh 1+mesh 2)
we get, -4i1 -5i2 + 3i3 +1 +2=0
if you liked it then then consider donating money not likes!🤣
Tune bhi toh +1 hi likha hai
Thanks sir for this part ....
Thnku soo much Sir u r my last minute saver.... U lectures are excellent and it clears all my doubts...😊😊
Hii aap engineering krte ho kya
Sir 21:35 par -1 nhi hoga waha +1 hona chahiye
Yes same question please correct it. It's create lot of confusion......
Yes that's correct .it should be +1
you are write dear
There current is moving as drop in potential so -ve sign has to be applied that's right it would be -1 not +1 guys