Aromatic, Antiaromatic, or Nonaromatic Practice Session #1

This lesson examines multiple compounds to determine if they are aromatic, antiaromatic, or nonaromatic based on Huckel's Rule and other criteria.
How to Determine Aromaticity: • How to Determine Aroma...
Lone Pair sp2 Lecture: • Are Lone Pairs in Hybr...
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[@aarushpandit8221]

The AMOUNT OF CLARITY is insane!!!!! Thank you so much ❤

[@anushuajana1722]

at 12:23 it will be 3/2

[@josephine4854]

👍🏼

[@cami9295]

Your explanation of the pi bond in the lone pairs 1 C away from a pi orbital just saved my exam grade lol

[@mkhan8902]

Wow after watching a bunch of videos, your video made the most sense. Thank you!!

[@Emilia-we2dc]

wow thank you!! After the whole semester this finally makes sense before my final!!

[@umairshah5697]

Same situation

[@inventopotter8582]

I was not able to understand what's the hybridisation of the charged carbon atoms but now I do thanks a lot

[@lucastavoulareas963]

Best video on aromaticity. Made me understand it 100%.

[@jasmineramirez615]

highly recommend this video!!! I can do my homework problems now. Thank you

[@mariatariq5780]

Wonderfully explained! Cleared my concepts about aromaticity👌

[@mekdesbelete8766]

very very amazing and clear explanation

[@noreensyed4877]

You are amazing !!! Final is on monday and you made this 10000 times easier. Thank u

[@user-iu1jr5tl2d]

I can't explain how good your lectures are.❤❤

[@michaeljosechavez]

You are literally one of the best organic chem teachers I've known

[@ChemComplete]

Thank you for the high compliment!

[@5nsport426]

5th compound n = 3/2

[@Stohsh]

Yes it should be anti-aromatic as 4n = 8. = 2 which is a hückle #. So anti-aromatic

[@kevinbenitez7844]

From what I’ve understood, wouldn’t the second to last molecule be non-aromatic since a molecule would rather remain non-aromatic rather than switch to anti-aromatic ?

[@enoughnonymity]

that’s what i think too lol

[@leehailey3479]

Thank you! I was super confused until I watched your videos.

[@Alisha-pg9hu]

great explanation !!

[@shrutilipisetha8969]

Thank you so much for complete detailed information

[@Newsome6277]

goated channel

[@ChemComplete]

Organic is bussin

[@bichumonlotha3130]

I find that It's unnecessary to have it subtracted by 2 and find the n value. Simply check if the pi electron value is 4n or 4n+2. If it's the former then it's Antiaromatic, if it's latter then Aromatic. But very very helpful. Thanks!

[@adelinarodriguezzahrt8363]

Thank you for the help.

[@chandimchatterjee8444]

Very helpful.... But sir we can also consider that delocalised lone pair are sp2 and localised lone pair sp3 and stays in hybrid orbital... So whenever we see any lone pair participating in resonance we can say it is sp2..

[@PanPan-km5ip]

Big thanks for you, Sir.. Your videos help me a lot, especially for my lecture.. Once again thank you so much. :)

[@ChemComplete]

You are most welcome

[@suhaibaziz4597]

Thank you

[@pasindudeepajith1226]

Great video!! on point❤

[@kennethacheampong7]

Thanks 🎉

[@mizlolia]

Thank youuuuu ❤ I’m finally cleared

[@ek3378]

thank you very much it was really helpful and clear

[@pragyasingh7591]

thanks a lot for an easy explanation

[@rishiruns228]

Thanks for this 🙏

[@ChemComplete]

No problem 👍

[@lizbethjacome3787]

BEST VIDEO !

[@latanandb1]

it was really helpful .Keep up ur momentum bro.

[@mattt9868]

Thanks!

[@rassimsimou1594]

Good

[@Hackersuncovered]

thanks so much! Hope you guys are able to push out more Orgo 2 videos haha

[@linayasmine9975]

very helpful thank you !

[@mikaeladeniseresueno4666]

thank you for this!

[@Briankiptoon.metagulist]

Good am now getting something

[@josephlaguerre5359]

4n+2=8 4n=6 6/4=n n=1.5

[@keyannasafforld2341]

thank youuuu so much

[@ChemComplete]

You're welcome!

[@Czar_Char]

please how do i easily know that a ring structure is going to be conjugated?

[@ademmohammed644]

Thanks

[@andreavacaflor3680]

AMAZING

[@yt_mus1085]

i love u man

[@ThaPriusMen]

Great video, thanks a bunch. Quick question. My prof heavily emphasized planarity in his lecture on this topic. Any comments on planarity and it’s importance?

[@ChemComplete]

Hi Dominic, yes planarity is very important and required for aromaticity. The reason planar ring systems are so vital is that they allow for p-orbital overlap which leads to proper conjugation of pi electrons. When a ring fails to meet planar standards, it is classified as non-aromatic (not anti). An example of this is 1,3,5,7-Cyclooctatetraene. One would normally expect anti, but it is non-planar.

[@sanahilal6179]

Thank you!

[@user-dm3hz9od9h]

شكرآ

[@_krissy_lauren]

you're great

[@jadenkinnersley9342]

Makes Sense

[@bekky834]

BLESS

[@souravkumar2522]

Nice video

[@user-vk4wf7bc4n]

How know that aromatic is planar?

[@Stohsh]

If the ring is of 5 or less carbon. Then it’s planar. If you have a ring with more than 5, see if the molecule satisfies cyclic, conjugated and Hückles #. If all passes it’s planar. If not it’s non-aromatic.

[@saagarsingh7095]

good vid

[@Lola14826]

Good one

[@sienamarie8968]

awesome

[@PratikshaMurdeshwar-ik6ht]

4n=6 n=3/2

[@clementgyapong1700]

We need part two on the,same topic with different structures. You are a GOD

[@souravkumar2522]

In furan how to jutch oxygen is sp2 hybridised ????

[@user-rm4rp6lg4p]

Value of n in thio pyrane not correct

[@shelbygomez8023]

You are using the same 4n + 2 formula for both aromatic and anti aromatic

[@ChemComplete]

4n +2 = Pi electrons is the formula for determining aromaticity (aromatic or anti)

[@user-ed6uy3ln4y]

Why pyridine is marked not aromatic???

[@ChemComplete]

Pyridine is aromatic, it was also marked as such in the video!

[@indrajitnayak2643]

How the nitrogen atom is SP2 hybridized in last compound.

[@mattt9868]

The lone pair is in resonance with the pi bonds. In order to participate in the delocalization of electrons, the nitrogen must keep a p-orbital for overlap purposes and therefore can only be sp2.

[@AK-di4rv]

I find your videos very helpful, but your intro music is very loud and hard on the ears especially with headphones on. Can you please consider changing it for future videos? Thanks for all your effort man!

[@TogetherinParis]

algebra dude!

[@souravkumar2522]

In last question how nitrogen is sp2 hybridised here ??plz clear confusion

[@mattt9868]

The lone pair is in resonance with the pi bonds. In order to participate in the delocalization of electrons, the nitrogen must keep a p-orbital for overlap purposes and therefore can only be sp2.