Coupling coefficient || energy stored in the coupled inductors at t=1.5s

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[@Simbhatheking-rl1ve]

Sir in second loop why we start with -j2I1 sir .

[@easystudyplus]

Not necessary to start with -j2I1 ,You can start KVL with any one element in any direction ,this does not impact answer.

[@Simbhatheking-rl1ve]

@@easystudyplus sir I mean negative sign

[@surendrakverma555]

Very good. Thanks 🙏🙏🙏🙏🙏

[@easystudyplus]

Most welcome 🙏

[@SaiKumar-pl2fw]

Bro the calculation part of loop 2 equation gives jI1=(1+j)I2

[@easystudyplus]

You forgot divide by j so divide (1+j) by j also

[@diegolima7174]

Very good

[@easystudyplus]

Thank you so much bro

[@OdongpinyPatrick-vz4fi]

when I1=(1-j)2.773=/ cannot give 3.92 what method/algebra

[@easystudyplus]

So if you calculated I2=2.77

[@aryankumar3857]

Bro I1=(1-j)I2 kaise ayega ? Aur calculation part scientific calculator mei bhathe ke karo

[@easystudyplus]

Apply kvl in right side loop

[@easystudyplus]

Then divide by 2 on both sides and simplify

[@ramkrishna2315]

Use paper to calculate all not just by saying even though they are easy calculations

[@easystudyplus]

Yes ,your complex number topic should be strong

[@Ubaidkhan-qc8gr]

bhai itne jalde jalde step karte ho.. samaj he nahe ra raha hai.. apne koch step bohot jalde kya hai.. samaj nahe a raha hai 🙄😢

[@easystudyplus]

Bhai , konsa step samaj nhi aaya aaoko?

[@arixstatus4318]

Irritation hota hai

[@easystudyplus]

This will not happen from next time

[@arixstatus4318]

Bhai yah bich bich me si _si _si ki awaj na nikala karo

[@easystudyplus]

Okay ,i will remember it from next time