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Coupling coefficient || energy stored in the coupled inductors at t=1.5s
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- เผยแพร่เมื่อ 20 ก.ค. 2020
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Sir in second loop why we start with -j2I1 sir .
Not necessary to start with -j2I1 ,You can start KVL with any one element in any direction ,this does not impact answer.
@@easystudyplus sir I mean negative sign
Very good. Thanks 🙏🙏🙏🙏🙏
Most welcome 🙏
Bro the calculation part of loop 2 equation gives jI1=(1+j)I2
You forgot divide by j so divide (1+j) by j also
Very good
Thank you so much bro
when I1=(1-j)2.773=/ cannot give 3.92 what method/algebra
So if you calculated I2=2.77
Bro I1=(1-j)I2 kaise ayega ? Aur calculation part scientific calculator mei bhathe ke karo
Apply kvl in right side loop
Then divide by 2 on both sides and simplify
Use paper to calculate all not just by saying even though they are easy calculations
Yes ,your complex number topic should be strong
bhai itne jalde jalde step karte ho.. samaj he nahe ra raha hai.. apne koch step bohot jalde kya hai.. samaj nahe a raha hai 🙄😢
Bhai , konsa step samaj nhi aaya aaoko?
Irritation hota hai
This will not happen from next time
Bhai yah bich bich me si _si _si ki awaj na nikala karo
Okay ,i will remember it from next time