Find input impedance and current from source of coupled circuit board

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  • เผยแพร่เมื่อ 11 ก.ย. 2024
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ความคิดเห็น • 10

  • @surendrakverma555
    @surendrakverma555 2 ปีที่แล้ว +1

    Very good. Thanks 🙏🙏🙏🙏🙏

    • @easystudyplus
      @easystudyplus  2 ปีที่แล้ว

      🙏🙏🙏❤️😀 welcome

  • @yashasvikumar9244
    @yashasvikumar9244 ปีที่แล้ว +1

    In 3:40 How you convert that complex rectangular form into simple 28-j22
    Please recommend me a video

    • @easystudyplus
      @easystudyplus  ปีที่แล้ว

      Its rectangle to polar conversion
      If we have a+ib then it can be change to polar by
      magnitude=sqrt(a^2+b^2) and angle =tan^-1(b/a)
      Use this for 28-22j which is magnitude= sqrt(28^2+(-22)^2))=35.16
      angle=tan^-1(-22/28) =-38.16 degree

    • @yashasvikumar9244
      @yashasvikumar9244 ปีที่แล้ว +1

      Sorry to bother you again sir but I know How 28-j22 is converted into 35.61 angle - 38.16 degree
      But I donot understand How -j1I1+(j4+30+j40+80+J 60) I2 converted into I1=I2(28-j22)

  • @muhammadmubashir9716
    @muhammadmubashir9716 2 หลายเดือนก่อน +1

    Sr calculator se alag arhi hy reading

    • @easystudyplus
      @easystudyplus  2 หลายเดือนก่อน

      Calculator take range from -π/2 to π/2 ,calculate using quadrant rule.

    • @easystudyplus
      @easystudyplus  2 หลายเดือนก่อน

      Here is the video for calculating angles
      th-cam.com/video/yE-DG0ndV9w/w-d-xo.htmlsi=Szn1Tw_KYMio7Ry1

  • @nesamlw
    @nesamlw ปีที่แล้ว +1

    where did you get the I2, please explain

    • @easystudyplus
      @easystudyplus  ปีที่แล้ว

      Solve the last step
      (60-j80)(28-j22) I2 -j5 I2=50