The explanation is actually pretty simple. After the piles are combined into two sets of eight cards, each pile contains two face-up Aces and six face-down cards. Flipping one pile reverses this, and dealing the cards into alternate piles doesn't change their order, it just makes the 16 cards consist of two intermingled series whose order hasn't changed (as if you performed a perfect riffle shuffle). Then dealing the cards into four piles sorts the cards into alternating series- piles 1 and 3 match, and piles 2 and 4 match. Thus when combining the piles, they need to be reversed, and this is the reason for "rolling" the four piles together. So for example if pile 1 has face-up Ace(s) and the rest face-down, pile 2 automatically has face-down Ace(s) and the rest face-up, and thus the two piles must be reversed, and so on. At the end, all of the Aces are in the original configuration along with the indifferent cards.
I believe the simple reason that the trick works is that it is only ever the four aces at the start that are face up. The piles of 3 cards added are face down. The packets are selected in pairs so this does not change the original orientation. The cards can go through as many steps as you like but the basic orientation does not change. It’s not a maths thing it’s simply the orientation of the four aces never changes, shuffling only changes the order not the base orientation as these are swapped in pairs of packets with each packet containing a single ace. David S
1) The Aces face the opposite direction from the rest of the cards. 2) You flip half of the deck (let's call one half on the left the A cards, and the half on the right the B cards). 3) By alternately dealing, effectively performing a Faro shuffle, the cards get merged into one pile ABABABAB etc. etc. Let's assume the B side gets flipped. 4) You then deal this deck into four piles. The piles will be four A cards, four B cards, four A cards, and lastly four B cards. 5) By alternately flipping the four piles back into one, you effectively undo the flip from step 2). Try it only with the four Aces, or use two visibly different / distinct decks (one for A, the other for B) to see what I mean.
Hey there, Uncle Steve, lol. This is really slick. I thought this trick was something like the cheek to cheek trick. Lol. But i was wrong. I read 2 or 3 comments who i believe have the right answer as to how / why this trick works like it does. The 4 aces are the only cards in the beginning that are face up. I also think things change when dealing 4 piles, one card at a time. Well, maybe that doesn't matter, 😊. There is no math involved. I just did the trick back wards, and it worked. I put the 4 aces face- down, and I put 3 cards face-up on each ace. I did the trick the same way, and the 4 aces were the only 4 cards face down. Lol. Thanks, man. Blessings to you and your family.
I think impossible self-working tricks have become my new favourite type of card tricks. Being that there is very little trickery [or even sleight of hand skill] used, it for some reason impresses me more that they are more ingenious.
Excellent, Hi Steve, I can explain it up until you do every other card , that’s when I cannot , I will be doing this until I can understand it , but excellent.
Consider the cards in each original pile named as follows: (a1 a2 a3 a4) (a5 a6 a7 a8) (b1 b2 b3 b4) (b5 b6 b7 b8) Grab two piles and shuffle them, and the other two piles and shuffle them. It doesn't matter which piles you grab due to symmetry. It also doesn't matter what order you shuffle them into as only the orientation of the cards matters. You can think of this symmetry as assigning the Ace to one of the random numbers in each pile. flip one of the shuffled piles. It doesn't matter which one you flip. (call the flipped cards A instead of a) now you have two piles: (A1 A2 A3 A4 A5 A6 A7 A8) (b1 b2 b3 b4 b5 b6 b7 b8) Deal them alternating between the two piles. (A1 b1 A2 b2 A3 b3 A4 b4 A5 b5 A6 b6 A7 b7 A8 b8) Now deal them in 4 piles: (A1 A3 A5 A7) (b1 b3 b5 b7) (A2 A4 A6 A8) (b2 b4 b6 b8) Flip the first pile 3 times, the second pile 2 times, and the third pile 1 time. (a1 a3 a5 a7) (b1 b3 b5 b7) (a2 a4 a6 a8) (b2 b4 b6 b8) Now all the piles have the same orientation as they did in the original piles. The order of cards in each pile may have changed, but the orientation is the same. If you want to make it easy to empirically show this, grab A-4 in each suit and look at the arrangement of the cards after each step.
My friend. You are need 4 cards in a 16 card game of 4 piles of 4. The order after you put one over the other one puts everything in order because they are even and 4x4 is 16. The best way to understand it is do it without mixing, because it really doesn’t matter and deal the cards one beside the other and you’ll understand it better than my explanation. Great trick though I didn’t see it at first. I’ve been dealing to my self for 11 hours after I got it jajaja. Abrazo!
if you look through the final 4 piles as you turn them over you can see you are putting the aces back the same way and all the other cards are going back the opposite way. Freaken clever trick
Thank you for that tutorial Mr Steve I really enjoyed that mind-blowing trick it really is strange how that works I have no clue myself LOL but I will definitely be performing this one again I really do appreciate the video until next time take care of yourself your friend Billy Simmons
Here is UNEXPLANABLE 2.0! It really has my head spinning 😅
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The explanation is actually pretty simple. After the piles are combined into two sets of eight cards, each pile contains two face-up Aces and six face-down cards. Flipping one pile reverses this, and dealing the cards into alternate piles doesn't change their order, it just makes the 16 cards consist of two intermingled series whose order hasn't changed (as if you performed a perfect riffle shuffle). Then dealing the cards into four piles sorts the cards into alternating series- piles 1 and 3 match, and piles 2 and 4 match. Thus when combining the piles, they need to be reversed, and this is the reason for "rolling" the four piles together. So for example if pile 1 has face-up Ace(s) and the rest face-down, pile 2 automatically has face-down Ace(s) and the rest face-up, and thus the two piles must be reversed, and so on. At the end, all of the Aces are in the original configuration along with the indifferent cards.
That's the correct and indeed very simple explanation, thanks for writing it down!
I also figured it out, but it works on almost everyone because it throws you off!
I believe the simple reason that the trick works is that it is only ever the four aces at the start that are face up. The piles of 3 cards added are face down. The packets are selected in pairs so this does not change the original orientation. The cards can go through as many steps as you like but the basic orientation does not change. It’s not a maths thing it’s simply the orientation of the four aces never changes, shuffling only changes the order not the base orientation as these are swapped in pairs of packets with each packet containing a single ace. David S
Well done!!!!
@herberar sorry, not so well done. The correct and very simple explanation is given by Severian in the comments.
It's very easy. It's like one long false shuffle with the 4 aces returning to their original position of face up and the other cards face down.
1) The Aces face the opposite direction from the rest of the cards.
2) You flip half of the deck (let's call one half on the left the A cards, and the half on the right the B cards).
3) By alternately dealing, effectively performing a Faro shuffle, the cards get merged into one pile ABABABAB etc. etc. Let's assume the B side gets flipped.
4) You then deal this deck into four piles. The piles will be four A cards, four B cards, four A cards, and lastly four B cards.
5) By alternately flipping the four piles back into one, you effectively undo the flip from step 2).
Try it only with the four Aces, or use two visibly different / distinct decks (one for A, the other for B) to see what I mean.
Mind-blowing
Hey there, Uncle Steve, lol. This is really slick.
I thought this trick was something like the cheek to cheek trick. Lol.
But i was wrong.
I read 2 or 3 comments who i believe have the right answer as to how / why this trick works like it does.
The 4 aces are the only cards in the beginning that are face up.
I also think things change when dealing 4 piles, one card at a time. Well, maybe that doesn't matter, 😊.
There is no math involved.
I just did the trick back wards, and it worked.
I put the 4 aces face- down, and I put 3 cards face-up on each ace. I did the trick the same way, and the 4 aces were the only 4 cards face down. Lol. Thanks, man. Blessings to you and your family.
I've seen a different version of this trick but this one is better imo. Great work
fantastic trick, nice n easy with an amazing result 👍
Teach us some practical card controls please
wow ! def legit a awesome trick... Gonna start adding that one right away.
I think impossible self-working tricks have become my new favourite type of card tricks. Being that there is very little trickery [or even sleight of hand skill] used, it for some reason impresses me more that they are more ingenious.
I totally agree I get the best reactions 👍
Excellent, Hi Steve, I can explain it up until you do every other card , that’s when I cannot , I will be doing this until I can understand it , but excellent.
Consider the cards in each original pile named as follows:
(a1 a2 a3 a4) (a5 a6 a7 a8) (b1 b2 b3 b4) (b5 b6 b7 b8)
Grab two piles and shuffle them, and the other two piles and shuffle them. It doesn't matter which piles you grab due to symmetry. It also doesn't matter what order you shuffle them into as only the orientation of the cards matters. You can think of this symmetry as assigning the Ace to one of the random numbers in each pile.
flip one of the shuffled piles. It doesn't matter which one you flip. (call the flipped cards A instead of a)
now you have two piles: (A1 A2 A3 A4 A5 A6 A7 A8) (b1 b2 b3 b4 b5 b6 b7 b8)
Deal them alternating between the two piles. (A1 b1 A2 b2 A3 b3 A4 b4 A5 b5 A6 b6 A7 b7 A8 b8)
Now deal them in 4 piles: (A1 A3 A5 A7) (b1 b3 b5 b7) (A2 A4 A6 A8) (b2 b4 b6 b8)
Flip the first pile 3 times, the second pile 2 times, and the third pile 1 time.
(a1 a3 a5 a7) (b1 b3 b5 b7) (a2 a4 a6 a8) (b2 b4 b6 b8)
Now all the piles have the same orientation as they did in the original piles. The order of cards in each pile may have changed, but the orientation is the same.
If you want to make it easy to empirically show this, grab A-4 in each suit and look at the arrangement of the cards after each step.
❤ Thanks for sharing!
Another awesome trick for an amateur to add to their routine! Love your channel and thanks!
You’re very welcome!
That is insane 😳 Mindblown🎉 😮 Thanks for sharing 🎩 ✨️
My friend. You are need 4 cards in a 16 card game of 4 piles of 4. The order after you put one over the other one puts everything in order because they are even and 4x4 is 16. The best way to understand it is do it without mixing, because it really doesn’t matter and deal the cards one beside the other and you’ll understand it better than my explanation.
Great trick though I didn’t see it at first. I’ve been dealing to my self for 11 hours after I got it jajaja. Abrazo!
Wow you’ve done it again Uncle Steve 👍
if you look through the final 4 piles as you turn them over you can see you are putting the aces back the same way and all the other cards are going back the opposite way.
Freaken clever trick
Fantastic this Steve learning lots from your channel I'm looking forward to performing these tricks on the Family at Xmas thank you🙏
Amazing. Another winner.
Thank you for that tutorial Mr Steve I really enjoyed that mind-blowing trick it really is strange how that works I have no clue myself LOL but I will definitely be performing this one again I really do appreciate the video until next time take care of yourself your friend Billy Simmons
Nice!
Very nice, sir!
You have a special brain😮👍
Is that full deck of 52?
I love card tricks like these!! Thank you for sharing can't wait to show my family
Very cool!
Nice
Etonnant non!
Bravo.
Great
No he has a rabbit.
damn dude! someone owns a cat ha ha. Great video
My rabbit ripped my hands up.😅 cheers mate
Stop overloading my old head with reputation making routines It could explode all over my computer work station
Im definitely not that person either thanks for sharing
👍👍
No mathematics here. Two bundles with access are flipped once and then flipped back again!
It is math. But pretty cool trick
It’s not maths here it’s just the illusion created by flipping cards over twice and getting everything in the same order again
Nice trick though
It cannot be explained because it's math. 🙄
you have a cat?