thanks! EXTREMELY very helpful. I'm currently reviewing for preparation of my calculus AP test. I will be binging your videos for the next couple of weeks haha! :)
For anyone trying to get help from this: the one with e^x from [0,2] is actually a WASHER question, not a disk one. This guy doesn't know what he's doing. If you picture it rotated about the line, then the shape will have a cylinder cut out of it, so therefore the cross sections will be washers. Then, it would be pi *(integral from 0,2) R^2 - r^2 dx. Which is e^2x - (-1)^2 dx.
Alex, I'm sorry if the video wasn't clear, but I did not say that an area bounded by the curve AND the x-axis was being rotated around the line y= -1. It was simply the curve being rotated--and is therefore a solid. I have clarified the video, and I appreciate the comment.
thanks Eric. I wasn't trying to come off as rude or anything. I was just used to doing regions bounded by axes and incorrectly assumed that it would be the same. I didn't want anyone else to run into the same problem. Appreciate it
thanks! EXTREMELY very helpful. I'm currently reviewing for preparation of my calculus AP test. I will be binging your videos for the next couple of weeks haha! :)
Great
At the 2:27 mark, with respect to the graph, wouldn't it have been clearer to denote the Area as pi*y^2 instead of pi*x^2?
Solid !
how did he get (4,4) ? at 8:56
How did you get square root of 5?
Newton Jay 2.254
how did you find root 5 10.05
6:16
Is the integration correct?
Hi, Ahmed, I hope you are well. Yes, the integration is correct. Good luck in your studies!
Y u didn't take -2 while fndg x
For anyone trying to get help from this: the one with e^x from [0,2] is actually a WASHER question, not a disk one. This guy doesn't know what he's doing. If you picture it rotated about the line, then the shape will have a cylinder cut out of it, so therefore the cross sections will be washers. Then, it would be pi *(integral from 0,2) R^2 - r^2 dx. Which is e^2x - (-1)^2 dx.
Alex, I'm sorry if the video wasn't clear, but I did not say that an area bounded by the curve AND the x-axis was being rotated around the line y= -1. It was simply the curve being rotated--and is therefore a solid. I have clarified the video, and I appreciate the comment.
thanks Eric. I wasn't trying to come off as rude or anything. I was just used to doing regions bounded by axes and incorrectly assumed that it would be the same. I didn't want anyone else to run into the same problem. Appreciate it