Even though I am a Turkish guy who studies in Turkey. Your videos are much more understandable than the Turkish tutorials. Thanks for keeping the topics this simple and easy to understand by giving relatable examples.
@@BenBrawn shouldn't there be brackets for it to be considered an element of the original set? For instance the empty set is a subset of all sets, but {empty set} is not a subset of all sets. Isn't it the same case here?
Kiko Ribeiro brackets or no brackets, nether is an element of the set given. Yes what you say is correct, the empty set {} is a subset of every set but {{}} need not be a subset.
Hi pls help with this question (decide for each of the following relation whether or not it is an equivalence relation. Give full reasons. If it is an equivalence relation, give the equivalence classes. (a) let a. b be integers. Define aRb if and only if a 3 devises ( a-b) in other words R is the congruence modulo 3 relation....... Pls help
Even though I am a Turkish guy who studies in Turkey. Your videos are much more understandable than the Turkish tutorials. Thanks for keeping the topics this simple and easy to understand by giving relatable examples.
if I pass this course, I will thank god and you.
Maryam Ali Be sure to use the new playlist instead. The videos are updated and I fixed any mistakes.
@@SawFinMath I will, thank you from the bottom of my heart
@@maryamali1818 did u pass
Amazing video. Wish I found your channel sooner.
Thank you for delievering such great quality lectures
So nice of you
Bless your heart ! Your videos are so helpful
excellent explanation
than you very much
Perfect, thank you so much!
at 3:01 it should be (a-b)+(b-c) is in Z
Stephane Wamba I fixed the example in the updated video.
(Badiya) best classes 🇮🇳
For mod 4 [1] - how's 7 a congruent when if you divide 7 by 4 the remainder is 3 I thought we were to look for number who remainder was [1]
thanks you so much mam its helping course because these are book example that are more understanable.
Ma'am I have a doubt - is equivalence classes and partitions are exactly one and the same thing or they're different?
They are different. However some partitions are examples of equivalence classes, as shown in the video.
@@SawFinMath Thanks, Ma'am! You're such a blessing!
Awesome Class
Thanks bro
Thank you so much !
for the last problem, P1 should also be a "yes", right? because every set contains an implicit empty set
no. Every set has the empty set as a SUBSET, but not as an element.
@@BenBrawn shouldn't there be brackets for it to be considered an element of the original set? For instance the empty set is a subset of all sets, but {empty set} is not a subset of all sets. Isn't it the same case here?
Kiko Ribeiro brackets or no brackets, nether is an element of the set given. Yes what you say is correct, the empty set {} is a subset of every set but {{}} need not be a subset.
i love you kimberly
thank you maam, I wish you were my professor :((
GOAT
Hi pls help with this question (decide for each of the following relation whether or not it is an equivalence relation. Give full reasons. If it is an equivalence relation, give the equivalence classes.
(a) let a. b be integers. Define aRb if and only if a 3 devises ( a-b) in other words R is the congruence modulo 3 relation....... Pls help