ความคิดเห็น •

  • @khaledb8618
    @khaledb8618 4 ปีที่แล้ว +346

    It's 4 am rn, and I have an exam at 10, wish me luck

    • @Jessedegans
      @Jessedegans 4 ปีที่แล้ว +10

      How did it go?

    • @navjotsingh2251
      @navjotsingh2251 4 ปีที่แล้ว +23

      Khaled B first of all, that type of sleeping pattern is damaging to you in the long run please fix this. Second of all, how did you do in the exam?

    • @rainbow6siege345
      @rainbow6siege345 4 ปีที่แล้ว +41

      @@navjotsingh2251
      He's dead

    • @gmenos6252
      @gmenos6252 4 ปีที่แล้ว +5

      Hope your exams went ok

    • @blizzaroxxx
      @blizzaroxxx 4 ปีที่แล้ว +9

      F

  • @Xiorth_YT
    @Xiorth_YT 8 ปีที่แล้ว +277

    Have my discrete math exam tomorrow morning. Just wanted to say thanks for the videos, they've been great!!

    • @atidyshirt
      @atidyshirt 3 ปีที่แล้ว +1

      Have mine this afternoon, this just saved my ass for antisymmetric relations

    • @bestyoueverhad.2408
      @bestyoueverhad.2408 3 ปีที่แล้ว

      @@atidyshirt have mine this friday

    • @atidyshirt
      @atidyshirt 3 ปีที่แล้ว

      @@bestyoueverhad.2408 gl

    • @goncalomatias26
      @goncalomatias26 2 ปีที่แล้ว

      Have mine tomorrow ahaha

    • @bassitirfan7446
      @bassitirfan7446 ปีที่แล้ว +1

      so howd u guys do?

  • @anonInDE
    @anonInDE 8 ปีที่แล้ว +31

    You have such a great channel man! I'm studying computer Science and our math prof. does nothing except read out definitions and write them on the board all lecture long... You're really helping me understand what we're actually learning! Cheers man!

  • @ShanaAngliang
    @ShanaAngliang 4 ปีที่แล้ว +6

    I like how you mentioned that Hasse Diagrams are used to make relation diagrams clearer, this video has cleared some of my doubts about PO, thank you so much!

  • @grigoryshepelev8149
    @grigoryshepelev8149 6 ปีที่แล้ว +9

    I've found this video after I had some struggle with understanding "How to prove it" book, which opened a world of beautifull set theory for me.
    Thank you for those.

  • @MrGreyScreen
    @MrGreyScreen 9 ปีที่แล้ว +18

    You're a better teacher than my lecturer.

  • @DanielDupriest
    @DanielDupriest ปีที่แล้ว +1

    This is one topic I think I never really figured out from my CS classes. Thank you for the clear and concise explanation!

  • @adrianalexisoscar1369
    @adrianalexisoscar1369 6 ปีที่แล้ว +21

    it's easier if you explain transitive inequalities this way
    2

  • @eduardorivera508
    @eduardorivera508 6 ปีที่แล้ว +2

    Thanks for this. Definitely will start binging on these lectures from now on! I love that you explain what each concept means as you introduce them. My professor just mentions them and sort of expects us to know what it means. If it wasn't for this video, I wouldn't have known to have NOT thought of antisymmetry as "not symmetric". No wonder I was confused the entire lecture. Granted, I could have asked out loud, but our class is very quiet. It seems this course is particularly a very intimidating one.

  • @tinysosig
    @tinysosig 4 ปีที่แล้ว +19

    12:46 Trevor you said "We know in a partial order, everything is going to be symmetric", but I think you meant antisymmetric? Correct me if I'm wrong, wanna make sure I'm understanding this correctly.

    • @tet5951
      @tet5951 3 ปีที่แล้ว

      same

    • @purpose_is_empty
      @purpose_is_empty 3 ปีที่แล้ว +4

      He probably actually meant reflexive, because the next step was removing the reflexive arrows.

  • @jayantabiswas5689
    @jayantabiswas5689 9 ปีที่แล้ว +16

    sir, if u give more video with example of how to find maximal and minimal number n also for greatest nd least elements ,it will b helpful
    thax for giving this video

    • @TheYagga
      @TheYagga 7 ปีที่แล้ว +1

      yes please.. great video

  • @GoreDough92
    @GoreDough92 4 ปีที่แล้ว +1

    my dawg Trev killin it on the teaching game, thx bruh

  • @BusaBarnabas
    @BusaBarnabas 8 ปีที่แล้ว +21

    At 12:48 you mentioned that, "we know that in a partial order, everything is going to be symmetric..." I am quite sure you meant to say, everything is going to be reflexive.

    • @AirTimeEh
      @AirTimeEh 7 ปีที่แล้ว +6

      ya i thought a partial order was if R is reflexive, antisymmetric and transitive.
      staff.scem.uws.edu.au/cgi-bin/cgiwrap/zhuhan/dmath/dm_readall.cgi?page=20

    • @evancornish656
      @evancornish656 6 ปีที่แล้ว +3

      you're right, he made a lot of mistakes in this video.

    • @xiaoyulyu
      @xiaoyulyu 3 ปีที่แล้ว

      I was confused at this part, thx

  • @D.2023
    @D.2023 7 ปีที่แล้ว +1

    Clean, perfect explantation. You helped a lot! Thanks!

  • @MohammedAlAli
    @MohammedAlAli 7 ปีที่แล้ว +1

    Thanks Trevor. This is helpful for my Advanced Graph Theory class. We are talking about Comparability Graphs as well as partial order and transitive orientation.

  • @user-sf5bt8eb4y
    @user-sf5bt8eb4y 6 ปีที่แล้ว

    hey @TheTrevTutor , you are a god send for your discrete math lessons! you are really doing a good thing here, really helpful for students with crappy lecturers

  • @tallalomar3531
    @tallalomar3531 6 ปีที่แล้ว

    dude you are the best I have seen so far keep up the good work..

  • @bkevinF
    @bkevinF 9 ปีที่แล้ว +2

    Hi @TheTrevTutor, thank you for this one. It makes more sense to answer my modules. And also, do you have something that discuss Operations on Relations? Like Complement of a relations, inverse of a relation, composite product, R restricted to X and Image of x under R.

  • @adiletdaniyarov5737
    @adiletdaniyarov5737 5 ปีที่แล้ว

    THe only good discrete math teacher for the whole of the planet

  • @davidjohnson-my6sr
    @davidjohnson-my6sr 7 ปีที่แล้ว +1

    3:31: the equivalence class of a is {a,b} by reflexivity.

  • @JamesBrodski
    @JamesBrodski 2 ปีที่แล้ว

    Amazing video. Thank you so much. I will pass my exam because of you.

  • @nadeemjq
    @nadeemjq 5 ปีที่แล้ว +1

    Was the conclusion from 11:10 that the set is antisymmetric or not? Not sure what to make of "Yeah, we're looking good here."

  • @mimslilas15
    @mimslilas15 8 ปีที่แล้ว +2

    Thank you for your videos! it makes everything look simple :)

    • @Trevtutor
      @Trevtutor 8 ปีที่แล้ว +2

      +Marielle Huot Glad I can help :)

  • @ahmedal-tayy7332
    @ahmedal-tayy7332 4 ปีที่แล้ว

    Online Uni is a scam. Im paying 9k this year and all i get is mumbling and a squeaky chair in the recorded lectures. You my man have saved me from failing the maths module in my computer science course.

  • @jandomingo7162
    @jandomingo7162 7 ปีที่แล้ว +6

    I couldn't find Partial Orders in the Book of Proof. Does anyone know if it is actually covered in the book?

  • @stelpveri4679
    @stelpveri4679 7 ปีที่แล้ว

    Thanks for explaining why the diagram looks the way it does

  • @marioksoresalhillick299
    @marioksoresalhillick299 4 ปีที่แล้ว +1

    2:15, that looks absolutely beautiful!

  • @escape2064
    @escape2064 5 ปีที่แล้ว +11

    You keep saying "we know partial orders are symmetric" but before that you said they are antisymmetric ..... soo which is it?

    • @mcsgone4683
      @mcsgone4683 5 ปีที่แล้ว +1

      Partial orders are antisymmetric (example: if a

    • @snickerdoodle538
      @snickerdoodle538 4 ปีที่แล้ว +3

      He meant to say reflexive, as he is talking about removing the reflexive edges in the transfer from a graph representation to a Hasse diagram

  • @LuaneCarolineAquinoCavalcanti
    @LuaneCarolineAquinoCavalcanti 9 ปีที่แล้ว

    best tutorial about hasse diagrams, thanks !

  • @arkadiuszzdanowski3843
    @arkadiuszzdanowski3843 7 ปีที่แล้ว +36

    you're confusing equivalence class and equivalence relation

  • @martinhawrylkiewicz2025
    @martinhawrylkiewicz2025 2 หลายเดือนก่อน

    Great vid! Just wondering here if you have two partial orders on a set A, will their union be also a partial order on set A?

  • @alialaa8824
    @alialaa8824 7 ปีที่แล้ว +1

    Thank you so much these wonderful videos!
    I'm having a trouble with reading mathematics notations related to set theory. How can I improve my awareness of reading these notations? I have a course in college that deals with theories of sets and graphs, and I can't understand all the notations especially when it comes to functions and relations that are a bit complex. What do you recommend?

  • @ahmedhussein660
    @ahmedhussein660 5 ปีที่แล้ว

    Very clearly explained! Thanks a lot.

  • @sperera5916
    @sperera5916 8 ปีที่แล้ว +3

    12:41 Hasse Diagram, you said it is Symmetric, please explain how. Thanks

  • @tiku.1414
    @tiku.1414 7 ปีที่แล้ว +1

    +TheTrevTutor So is the "=" relation,an antisymmetric relation,because a=b and b = a implies that a = b.

  • @-a5624
    @-a5624 5 ปีที่แล้ว

    my prof has a link to your channel posted on the online website lol. Your channel is definitely more helpful than his lectures...so thank you :)

  • @JasonJason210
    @JasonJason210 5 ปีที่แล้ว +1

    Thanks. I find 2:45 onwards confusing. Which is set Y?

  • @Kri38
    @Kri38 8 ปีที่แล้ว +1

    thanks for the video man, really appreciate it!

  • @Manikandan-nn2bw
    @Manikandan-nn2bw 2 ปีที่แล้ว

    Perfecto... And thanks for book suggestion.

  • @nangalucia7lucia667
    @nangalucia7lucia667 3 ปีที่แล้ว

    Thank u Sir. Ur video is helpful. Pls make me understand the difference between equivalence class and equivalence relation and also proofs

  • @leocomerford
    @leocomerford 6 ปีที่แล้ว

    0:31 For symmetry, if A has a *particular* relation to B, then we expect B to have *that same* relation to A. If A is related to B then B is *always* related to A in *some* way. If A is the father of B, a very non-symmetric relation, then B is the son of A.

  • @brianc5617
    @brianc5617 2 ปีที่แล้ว

    Love the videos, thanks for doing them! Minor correction: Hasse diagram's are named after Helmut Hasse with Hasse pronounced as hAss-uh

  • @Omer-es7wo
    @Omer-es7wo 6 ปีที่แล้ว

    thank you soo much, all the best for future videos!!!

  • @satyamsinghs786
    @satyamsinghs786 7 ปีที่แล้ว

    I want to know that we delete reflexcivity and transitivity in hasse diagram to make it more clear can i say that 3R1 and 1R2 -->3R2 from hasse diagram since we remove transitivity so i have that doubt plz clear it as soon as possible
    your lecture are really nice it helped me alot in learning dicrete mathematics thanks for helping us.
    regards
    satyam singh
    IIT BHUBANESWAR
    INDIA

  • @PizzaPunt99
    @PizzaPunt99 ปีที่แล้ว

    Very helpful, thanks

  • @gazamisehawoh
    @gazamisehawoh 4 ปีที่แล้ว

    thank you this really helped me

  • @danielmelville1729
    @danielmelville1729 2 ปีที่แล้ว

    Very helpful, I appreciate it.

  • @quocbaoha8373
    @quocbaoha8373 2 ปีที่แล้ว

    thank you Sir, as Vajazle had said, they had been great

  • @MRKS8
    @MRKS8 5 ปีที่แล้ว

    thumbs up. Clear and concise.

  • @SuegroLM
    @SuegroLM 3 ปีที่แล้ว

    I was following up quite well until reached around 11:09 where you explained antisymmetry so vaguely in comparison with the previously explained Reflective and Transitive conditions, from my point of view, I would have liked a better elaboration there, to be honest, 😂 was trying to figure out what was all this about but anyway... before that, I may say it had been a great video.

  • @adarsh350
    @adarsh350 4 ปีที่แล้ว

    perfect explanation

  • @nadeemjq
    @nadeemjq 5 ปีที่แล้ว +2

    This video was exceptionally difficult to follow... Several places it's difficult to see how you're thinking. For example, from 10:40, it's not clear how you are checking for reflexivity. You are merely pointing out the pairs, and not making it clear how that is a check for reflexivity. Anyways, been watching your videos from scratch, and they are lifesavers! :)

  • @smoothbrain
    @smoothbrain 2 ปีที่แล้ว

    Great vid my guy

  • @orionwolf-hubbard6895
    @orionwolf-hubbard6895 6 ปีที่แล้ว

    Thank you! This was very helpful.

  • @georghieronymus9935
    @georghieronymus9935 6 ปีที่แล้ว

    Thank you for the informative video. Any prospects for making a video on equivlance classes and partitions?

  • @AnjaliChadha
    @AnjaliChadha 8 ปีที่แล้ว

    Lucid explanation. Thanks!

  • @jemand1685
    @jemand1685 2 ปีที่แล้ว

    Thanks for the video

  • @surajmu4169
    @surajmu4169 8 ปีที่แล้ว

    You have a video on extremal elements in a poset?? This video was good!

  • @tadiwanashemadongorere2374
    @tadiwanashemadongorere2374 2 ปีที่แล้ว

    Amazing work!!!

  • @sperera5916
    @sperera5916 8 ปีที่แล้ว

    I have 2 questions. time line 8:29
    1. if 2=2 is reflexive, then why x

    • @SoBoredTv12321
      @SoBoredTv12321 8 ปีที่แล้ว +1

      Hopefully I can help. x

    • @sperera5916
      @sperera5916 8 ปีที่แล้ว

      Thanks alot! I think I got it.

  • @andywei8963
    @andywei8963 6 ปีที่แล้ว

    perfect explanations, thanks

  • @edgardobaldovinojr.3565
    @edgardobaldovinojr.3565 8 ปีที่แล้ว

    Hi need some help here, 'cuz im really confused about the antisymmetric property, why is that the relation "greater than" considered as antisymmetric and for this T = {(a,c),(b,d),(d,c)} in relation to X ={a,b,c,d} is considered also antisymmetric . :( please i'm so confused

  • @hell4eg
    @hell4eg 8 ปีที่แล้ว

    Thank you for this lessons!

  • @majidalismaili575
    @majidalismaili575 4 ปีที่แล้ว

    Which text book are you using?

  • @thunderbeast9831
    @thunderbeast9831 3 ปีที่แล้ว

    I have a question, should we not write "x divides y" as y/x ?

  • @oumaimaalazhari8704
    @oumaimaalazhari8704 3 ปีที่แล้ว

    Please where can I find the 3rd part of relations, I really need it

  • @nethajis1384
    @nethajis1384 ปีที่แล้ว

    How many partial order relations are possible on set of n elements?

  • @purnimasaikia7776
    @purnimasaikia7776 7 ปีที่แล้ว

    Thank u so much , really very helpful !

  • @kofiafful7004
    @kofiafful7004 6 ปีที่แล้ว

    A = {1, 2} and B = {a, b, c}. Is (a, a) an element of A x B?

  • @deannac.7199
    @deannac.7199 8 ปีที่แล้ว +2

    I'm a bit confused because my professor introduces antisymmetry as aRb bRa when a does not equal b. So i dont quite u derstand why you say aRb bRa when a=b when that is the definition of symmetry

    • @Trevtutor
      @Trevtutor 8 ปีที่แล้ว +3

      +Deanna Camacho What we're saying is that if aRb and bRa, then a=b. The definition of symmetry states that if aRb then bRa, so we don't always have that a=b.

  • @neuralworknet
    @neuralworknet 9 หลายเดือนก่อน

    Omg so helpful!

  • @silentrobi2905
    @silentrobi2905 8 ปีที่แล้ว

    i think it would be like what I see from the book is: [x] ^ [y] != {} cz their are reflexive elements in those set. isn't it, if I am not wrong sir?

  • @Engineer_With_A_Life
    @Engineer_With_A_Life 9 ปีที่แล้ว

    ossum video, now i am cleared with poset but still i confused in symmetric and antisymetric relation both look same :(

  • @novanskaagintaganesha4376
    @novanskaagintaganesha4376 7 ปีที่แล้ว

    its very helpful ! thanks sir

  • @theone0201
    @theone0201 7 ปีที่แล้ว

    Thanks mate, you've helped alot :)

  • @amarindersingh8678
    @amarindersingh8678 7 ปีที่แล้ว

    Hey man i have a question. If partial order and total order both are asymmetric, reflexive and transitive then what is the difference between them?

    • @manuhortet
      @manuhortet 7 ปีที่แล้ว

      A binary relation is a partial order if it is reflexive, antisymmetric and transitive. But inside partial relations, there are other two types of relations: total order and well-order. What I am saying is that every total ordered set is partially ordered too.
      The conditions for a partial ordered set to be a totally ordered is that every pair is comparable (xRy is always true)

  • @evev6383
    @evev6383 3 ปีที่แล้ว

    can we draw the hasse diagram horizontally?

  • @NoraAlfraidi
    @NoraAlfraidi 4 ปีที่แล้ว

    When we draw hoss diagram we have to Remove a reflexive sign?

  • @lobnaabdelhamed1234
    @lobnaabdelhamed1234 7 ปีที่แล้ว

    is there any video for closure of relations ?

  • @utkarshjauhari1443
    @utkarshjauhari1443 3 ปีที่แล้ว

    Useful topics....

  • @deathstalkr_
    @deathstalkr_ 7 ปีที่แล้ว

    For a given poset can we have more than one Hasse diagram?

  • @Aaztha
    @Aaztha 8 ปีที่แล้ว

    Thank You so much!

  • @Kalo953
    @Kalo953 8 ปีที่แล้ว

    I have a question: Why this set if reflexive, by definiton A relation in which all the elements follow the property A→A.
    All the elements are related to themselves is known as reflexive relation. So if there are ordered couples, which are not reflexive as in the example (1,1) (1,2) (1,3)... then it shouldnt be reflexive?

    • @Trevtutor
      @Trevtutor 8 ปีที่แล้ว +1

      +Kalo953 A relation is reflexive, not ordered pairs. If all the pairs of (x,x) are in the relation, then the relation is reflexive. If there are additional pairs, it doesn't change anything.

    • @Kalo953
      @Kalo953 8 ปีที่แล้ว

      okay, i understand now, also can i ask why the ordered pairs in the hasse diagram seem to be incomplete. R subset of AxA => AxA = {(1,1),(1,2),(1,3),(1,4)(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),(4,1)(4,2),(4,3),(4,4)} ?

    • @Trevtutor
      @Trevtutor 8 ปีที่แล้ว

      +Kalo953 I don't understand what you mean by "incomplete".

    • @Kalo953
      @Kalo953 8 ปีที่แล้ว

      ahh I think i understand it now. You only write the pairs that are related. I thought at first that you write the result of the cartesian product of A^2.

  • @ProphetPakoKadosh
    @ProphetPakoKadosh 8 ปีที่แล้ว

    thanks guys.

  • @saladprayer8239
    @saladprayer8239 8 ปีที่แล้ว

    Thank you so much, man.

  • @GoodBalak
    @GoodBalak 9 ปีที่แล้ว

    Great Vid! Cheers!

  • @SmokyBigSmoke
    @SmokyBigSmoke 5 ปีที่แล้ว

    Thank you

  • @dellokrd9916
    @dellokrd9916 2 ปีที่แล้ว

    Great Vid

  • @ngelemar
    @ngelemar 5 ปีที่แล้ว

    Life saver💯

  • @IndigoStat
    @IndigoStat 5 ปีที่แล้ว

    I owe you my life.

  • @hovhadovah
    @hovhadovah 7 ปีที่แล้ว +1

    Note: symmetry does not mean aRb implies bRa, but rather aRb iff bRa

    • @Trevtutor
      @Trevtutor 7 ปีที่แล้ว

      aRb -> bRa comes out to be that aRb iff bRa. Since 3R2 implies that 2R3 is in the set. But 2R3 in the set implies 3R2 in the set.
      The simple definition of symmetry is for all a,b, aRb -> bRa.

  • @baovoquoc6358
    @baovoquoc6358 8 ปีที่แล้ว +1

    Thanks, sir.

  • @pushkar9021
    @pushkar9021 7 ปีที่แล้ว

    thank you so much .grt work

  • @purpledorii
    @purpledorii 6 หลายเดือนก่อน

    Thank u 🙏

  • @george4746
    @george4746 3 ปีที่แล้ว

    Thanks

  • @123455866201Aaron
    @123455866201Aaron 5 ปีที่แล้ว

    trev wheres the video that explains upper/lower bounds?

  • @BharadwajRbwaj95
    @BharadwajRbwaj95 9 ปีที่แล้ว

    A={1,2,3,4}....is it symmetric or anti-symmetric .....??? Being a PO SET it is of course
    anti-symmetric .....but how...??

    • @Trevtutor
      @Trevtutor 9 ปีที่แล้ว

      +bharad waj (bwaj95) The relation is anti-symmetric, not the set. Only relations have these properties. So 2 divides 4 but 4 doesn't divide 2.

  • @kempisabel9945
    @kempisabel9945 5 ปีที่แล้ว

    you have saved my exam! TT

  • @unesyu3481
    @unesyu3481 4 ปีที่แล้ว

    Is there anyway to contact you?

  • @praneethaluru2601
    @praneethaluru2601 7 ปีที่แล้ว +1

    sir explain with more clarity..u are also confused while checking transitivity and some other parts