How to design a steel column using an easy approach.

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  • เผยแพร่เมื่อ 25 ก.ค. 2024
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    In this easy to follow tutorial, we will use a trail & error approach and show you how you can design a Universal Steel Column subjected to Axial force.
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ความคิดเห็น • 46

  • @andreipopovcean9494
    @andreipopovcean9494 9 หลายเดือนก่อน

    Thanks! This is one of the most understable and practical engineering channel on TH-cam.

  • @emmadavies7434
    @emmadavies7434 3 ปีที่แล้ว +1

    Great topic guys well done!.one of the most easiest ways I've ever come across cheers!.

  • @gulfadventurevlogs8054
    @gulfadventurevlogs8054 6 หลายเดือนก่อน

    Thanks. Great Explanation. easy to understand. great job.

  • @user-ov4dw3yr5d
    @user-ov4dw3yr5d ปีที่แล้ว

    Thank you for all you very informative videos. 👍

  • @jacksonphillips6276
    @jacksonphillips6276 2 ปีที่แล้ว +2

    Great Channel.

  • @dengineerslifevlog5534
    @dengineerslifevlog5534 3 ปีที่แล้ว +2

    Thanks for this topic...

  • @vesaltorabi9
    @vesaltorabi9 2 ปีที่แล้ว

    You are amazing!!

  • @nirshunarayanyadav5297
    @nirshunarayanyadav5297 2 ปีที่แล้ว

    Very nice explanation

  • @zakwanabo9265
    @zakwanabo9265 ปีที่แล้ว

    Thank you very much

  • @nadinbu257
    @nadinbu257 หลายเดือนก่อน

    thank you

  • @shahedsiddiki1165
    @shahedsiddiki1165 2 ปีที่แล้ว +4

    It's a good video but we want more about column design

  • @igirithankgod5395
    @igirithankgod5395 หลายเดือนก่อน

    Thank you Sir for this easy approach.
    I have my actual stress as 157N/mm^2, is the column suitable?

  • @goodmind6446
    @goodmind6446 ปีที่แล้ว +1

    Thanks Sir ! want to see video on stability analysis and design of steel structure.

    • @cnjrq
      @cnjrq ปีที่แล้ว

      I have lecture number 23 to 26 planned for stability analysis of steel buildings. I'm on lecture 10 at the moment and you'll see three vidoes per week uploaded. Please feel free to follow this playlist th-cam.com/play/PLOQ_D0oq27oCKwuVHk-mgE0SRIGpOpSVu.html

  • @ashutoshsuthar3753
    @ashutoshsuthar3753 ปีที่แล้ว

    So core topics, please make video regarding design of crane grider on which the crab travels

  • @dopareel
    @dopareel 9 หลายเดือนก่อน

    nice

  • @Beginner2Creator
    @Beginner2Creator 6 หลายเดือนก่อน

    Great topic : let me ask you, what about slenderness more than 3 ?

  • @harigovind2968
    @harigovind2968 ปีที่แล้ว

    can u make a video on design of inclined cantilever columns

  • @boy-br2tr
    @boy-br2tr 2 ปีที่แล้ว +7

    Can you sample a building design from roof down to foundation structual analysis?..

    • @cnjrq
      @cnjrq ปีที่แล้ว

      I have a complete tutorial on how loads are distributed from roof to foundation via columns. You can watch example 2 in my recent tutorial on steel columns th-cam.com/video/XQipsi8Je2Q/w-d-xo.html

  • @user-ov4dw3yr5d
    @user-ov4dw3yr5d ปีที่แล้ว

    If I may request a vlog for alum. Curtain wall and steel brackets structural calcs.? Thanks in advance.

  • @ashleyrandall6582
    @ashleyrandall6582 11 หลายเดือนก่อน

    The 203 x 203 x 46 works. However can anyone tell me which codes this example is going according to ?

  • @sakally6392
    @sakally6392 4 หลายเดือนก่อน

    cool

  • @IvanIvanov-lo6lv
    @IvanIvanov-lo6lv 2 ปีที่แล้ว +2

    Please explain for 1.35 and 1.5 in design load. What do they mean, when to use them.

    • @sajadhussain6897
      @sajadhussain6897 2 ปีที่แล้ว

      they are used to increase the load to induce factor of safety

    • @AS-tq2mn
      @AS-tq2mn ปีที่แล้ว

      They're safety factors used to increase the load. You use 1.35 for permanent loads (which is the weight of the structure and anything else that's part of the build up) and 1.5 for variable loads (which is the load you consider from people using the structure, or any other load that comes and goes/isn't constant like snow).

  • @Kom-pks
    @Kom-pks 2 ปีที่แล้ว +1

    Hi,
    Anyone know the formula for calculating 'non-dimensional slenderness' for SS400 ?
    i seem to couldnt find it anywhere, or any keyword to search would be great too
    Thank you!

    • @cnjrq
      @cnjrq ปีที่แล้ว

      Slenderness (Lambda) = (Lcr/iz)x(1/(93.9e), where e = SQRT(235/fy). Fy is yeild stress, Lcr is buckling lenggth, iz is radius of gyration in minor axix. You can follow the proceodure in my recent video, if it helps you th-cam.com/video/udCnAM3RenQ/w-d-xo.html

  • @youubik
    @youubik ปีที่แล้ว

    Just throw in that wacking great safety factor at the end and its doesn't matter what you calculate it to

  • @maggysantana3878
    @maggysantana3878 2 ปีที่แล้ว +3

    Just looking it few time and I don’t understand where you get the 350knm and the 300 Knm... from where you get the 4000mm ? Can you please do the example step by step... and show how you find those actor I mentioned to understand the math clear please.? Thanks.

    • @telestruct
      @telestruct ปีที่แล้ว

      the design DL=350KN & LL=300KN are obtained from structural analysis. the selected column height of 4m is just an example.

  • @vinothkumar-qq1gf
    @vinothkumar-qq1gf 2 ปีที่แล้ว

    As per 203 x 203 x 46Kg channel I got an actual stress value is 55.90 N/mm2. Is it correct?

  • @suhaibkhan7356
    @suhaibkhan7356 2 ปีที่แล้ว +3

    How 100 n/mmsq compressive stress assume

  • @saddammb5633
    @saddammb5633 2 ปีที่แล้ว +5

    How did you consider 100 N/MM2 as compressive stress?

    • @000khalil000
      @000khalil000 2 ปีที่แล้ว

      That was initial trial stress

    • @burhanalibaig2533
      @burhanalibaig2533 2 ปีที่แล้ว

      @@000khalil000 which book can i refer to for this calculations?

  • @victorgetsbetter
    @victorgetsbetter ปีที่แล้ว

    here right on time 😂

  • @unitvector-dq1gb
    @unitvector-dq1gb ปีที่แล้ว

    Trying 203×203×46 as you ask :
    This had properties,
    A = 58.8 cm
    i ( radius of gyration) = 5.11 cm
    The yield stress (fy) for this type of steel = 275 Mpa or N/mm² , it's the same.
    And the effective length is 4 m or *4000mm
    • Non-dimensional slenderness of the section is L/86i
    So 4000mm/86×5.11×10mm = 0.91
    • The reduction factor X from the curve is approximately 0.68
    • The buckling stress is : X × fy
    0.68×275= 187Mpa
    • Actual strees is :
    Design load/ Area of section
    922.5×10³ N / 58.8×10² mm
    = 156.9 Mpa < 187 Mpa ✓ok
    Susceptive to correct .

    • @charlesa1000
      @charlesa1000 ปีที่แล้ว

      hi can you suggest a column for 8m length

    • @civilking5437
      @civilking5437 ปีที่แล้ว

      Wrong. The reduction factor should be 0.58 not 0.68

    • @sandeepguleria8214
      @sandeepguleria8214 4 หลายเดือนก่อน

      So it failed actually

  • @bkingtz1
    @bkingtz1 ปีที่แล้ว

    Who will help me calculate what type of columns and beams etc I need to make 7.5m L x 6m w and 4.5m H, cover/garage for my car lift?
    I live in country where there is snow, also no other weight on the roof except snow. I am just going to cover it with thermo panels.
    And what is necessary for column foundation (concrete and rebar etc type and spec)

    • @hudumasaud8295
      @hudumasaud8295 ปีที่แล้ว

      As an engineer, do it first. Then submit for vetting

  • @bkingtz1
    @bkingtz1 ปีที่แล้ว

    My 🧠 hurts 😵‍💫