Proving (x+y)^p=x^p+y^p | Abstract Algebra

[@manishjha5410]

Sir can you please elaborate how p divisible by pCr means 0

[@ganeshkadu2229]

In pCr numerator is divisible by p but denominator does not have factor of p, thus pCr is divisible by p

[@manishjha5410]

@@ganeshkadu2229yeah sir i understood that but 6:40 how the whole term is 0 i am unable to understand

[@ganeshkadu2229]

@@manishjha5410 As pCr is divisibly by p, it can be written as pk, for some integer k, Thus each term in the sum will contain pz, where z is an element in ring R, and it is zero as char R=p.