Just notice derivative of sqrt(x+1) is 1/2sqrt(x+1) and you want to cancel the 2 in the denominator so you multiply sqrt(x+1) by 2 and get [2sqrt(x+1) + c]
Your method works but it also embeds the case of the chain rule where the inner function differential is 1dx. This general approach isn’t necessarily quicker or easier to break down
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Did you find another fast way to solve this? 🤔
Just notice derivative of sqrt(x+1) is 1/2sqrt(x+1) and you want to cancel the 2 in the denominator so you multiply sqrt(x+1) by 2 and get [2sqrt(x+1) + c]
@@erezsolomon3838 good job!
Yeah but you could just say u=sqrt(x +1) and solve it instantly
That approach works too although the method I proposed is easier to break down conceptually for some
Your method works but it also embeds the case of the chain rule where the inner function differential is 1dx. This general approach isn’t necessarily quicker or easier to break down
U call this fast method 😂😂😂😂😂
Yup! Do you have a faster method to share