My last week of school and finals I haven't understood this all year and now I realize it is like the easiest thing ever thank you!! I won't have to go to summer school!!
We're concerned about when the denominator could be zero. So let's set it equal to zero and solve. a^2 - 49 = 0 Factor the difference of squares (a + 7)(a - 7) = 0 Solve each to get a = -7 and a = 7 We can double-check by putting them into the expression and sure enough, they both get us into trouble with a zero on the bottom. I hope that helps! Keep working hard on your math! :-)
Marty Brandl Yes! Thankyou! In factions, if you have a numerator and denominator that are both all variables (like m over a-b) how would you subtract and add that to another fraction that was set up similarly (like p over a-b)?
Wow!! This was so easy to learn!! Thank you so much!! Everyone in my class is failing algebra and none of us really know what’s going on because our teacher gives us notes and makes us do hw but we end up failing since she doesn’t teach us. So this really helped me and my sister!! Thank you!
Be careful, notes and homework are a part of teaching too... 😁🤷♂️ I'm glad you are seeking out extra help like this. That shows you really want to be successful! 👍
@@MartyBrandl I try my best to learn from my notes, but In class our teacher yells at us and says we should of already known this if we get something wrong so I’m pretty scared to ask her anything. 😅 thank you for replying so quick!
the ending, when he said " you could do anything you put your mind to" gave me more motivation than I have ever gotten in my life, like I wanna do good at math just for him.
If the denominator is 15x^2 + 30x, we start by setting it equal to zero and then solving. In this case, we can factor out 15x, so we get the following... 15x^2 + 30x = 0 15x(x + 2) = 0 Then use the zero product property to solve the two pieces. 15x = 0 x = 0 x + 2 = 0 x = -2 So the excluded values would be 0 and -2. We can double-check them to be sure and it turns out that both would get us into trouble with a zero in the denominator! I hope that helps! :-)
Set the denominator equal to zero and solve. 6n - 2 = 0 6n = 2 n = 1/3 So n can't be 1/3 because the denominator would be zero and we can't have that, of course, because division by zero is undefined. I hope that helps! :-)
@@MartyBrandl I'm on online class, and I get very tired and sleep through class, I take notes, but I mainly rely on videos like this to understand the concept afterwards
I don’t know how but I came up with this in math class since I was bored (my math teacher sucks at teaching), so instead of doing this, the easiest way of explaining this is that you factor the denominator, and once your finished with that, you change the symbol of the second term. Ex: The denominator is (x*2+5x+6). When you factor that you will get (x+3)(x+2), change the symbol of the second term so the restricted values become [-3, -2]. If the denominator has only one term (ex: 7x), then x=0. I don’t know if this is correct, it’s probably wrong since I’m just at grade 8, but it works for me so 🤷♀️🤷♀️.
The dominator is key to finding the excluded values because we can't divide by zero. We figure out what values of x will make the dominator zero by setting the dominator equal to zero and solving. I hope that helps! Please let me know if you have further questions! 👍
I am actually crying right now. I don't know what I'm doing wrong. There are no videos anywhere that tell me what to do when there are two different variables or a completely different variable in the numerator. Am I making this more difficult than it needs to be by panicking? I haven't completed a single page in my book and I have to hand in grades soon (I'm homeschooled and my mom doesn't know how to do it so I'm relying on the internet) At this point, I'm contemplating giving up because obviously I'm too stupid to understand basic math.
Update: I've figured out what to do when there are two variables in the denominator but a new problem has popped up. What happens when there is an exponent? The teacher's guide says "k^2-9" will become "k+3" and "k-3." I have know idea how they even came to that conclusion.
@@marcelinehall1328 Hang in there! You can do this! 👍 The k^2 - 9 can be factored as a difference of squares (both terms are perfect squares and they are being subtracted). That's where the (k +3)(k - 3) comes from. Can you give me an example of a problem with the 2 variables?
@@MartyBrandl So after an entire day spent on this one problem, I get it. My brain hurts but I'm sure I'll be able to answer the rest of the problems. The only thing I was having trouble understanding was why or how 9 could possibly be divided into -3 and 3 but now I get that -3 multiplied by 3 is obviously 9. Stupid brain. As for an example, one of the earlier problems I had trouble with was "x+3 over y(z+5)" but according to the teacher's guide, all I have to do is solve for each variable in the denominator. I think the thing that was confusing me the most though was that I used multiple sources that had different ways of going about the problems. One even said that I should use the numerator to cancel out the denominator. But after hours of trial and error, I not only got the problem right but I also understand why I solved it the way I did. Thanks.
@@MartyBrandl The question i have states' Find the maximal domain of the function y=2-1/x-1' It's multiple choice. Then the tipe is 'denominator ≠ 0, so find what x valu/s make it = 0 and it is everything but that/those values'
@@Scholz23 I'm assuming that the problem looks like this: y = (2 - 1) / (x - 1)? Or is it: y = 2 - (1/x) - 1? Hmmm...I'm not 100% sure, in the first option x = 1 would make the denominator 0, which is a problem. The maximal domain would be {x | real numbers, except x = 1}. I hope there's something helpful there! Keep working hard! :-)
i literally hear gibberish, im so stupid, im gonna end up failing 11th because idk wtf is going on, i get completely lost whenever people start putting numbers and letters underneath eachother and do whatever while talking about denominators equaling to 0 or not im so fucking stupid
I have a question... If a problem asks you: (Which of the following equations have at least two excluded values? Select all that apply.), do I have to look for the equations that have only two excluded values or one or none? Also, if the equation has only 1 excluded value, does it count as an answer?
Joham Alfonso I would say to be a correct answer to your question of "at least 2" any equation with 2, 3, 4, or more would be a correct answer. I hope that helps! :-)
@@phoebeshae Remember, we have to make sure the denominator can't be zero. So we setup an equation with the denominator equal to zero. 6m^2 = 0 Solve that and we have the value(s) that we must exclude to be sure the denominator is not zero. I hope that helps! Keep working hard!
Then the only thing that will get us in trouble is if x = 0, because we can't divide by 0. I hope that helps! Keep working hard and asking questions! 👍
my professor is horrible at teaching this stuff, so i have to go to a youtube video to learn this. Might as well of just not went to school at this point with a professor this bad.
Having the denominator be zero is when we would be in trouble. So, let's see what value(s) of x would make that happen... Solve 2x - 4 = 0 2x - 4 + 4 = 0 + 4 2x = 4 2x/2 = 4/2 x = 2 That means any value of x is fine, except for x = 2 because that would make the denominator be undefined as we can't divide by 0. I hope that helps! Keep on keeping on! 👍
Swear to god, this explained it better in 5 minutes than four months of algebra 2/trig. Thanks you!
My last week of school and finals I haven't understood this all year and now I realize it is like the easiest thing ever thank you!! I won't have to go to summer school!!
Really quick... make sure that you use the EQUAL SIGN WITH A SLASH GOING DOWN THE MIDDLE if you don't use that you will for sure get it wrong...
thanks that was helpful i was wondering about that
Thank you! I had a multiple choice on my hw and it said t=(with the slash)3 and I was confused but this explains it so thanks!
Right now there is Corona virus and I have online classes. This video was helpful, thanks. 👍
We're concerned about when the denominator could be zero. So let's set it equal to zero and solve.
a^2 - 49 = 0
Factor the difference of squares
(a + 7)(a - 7) = 0
Solve each to get a = -7 and a = 7
We can double-check by putting them into the expression and sure enough, they both get us into trouble with a zero on the bottom.
I hope that helps! Keep working hard on your math! :-)
I don't understand abt those with three terms(trinomial)
@@hinatakahashi4638 Can you give me an example of a problem that's giving you trouble and I'll see if I can explain it?
I learned this with my teacher at school for the whole year i dont understand anything.Thanks for your help I understand now
OH MY GOD I am giving up on ever being successful in life. This is impossible.
I don't believe that! You're watching math videos on TH-cam rather than just giving up!
Is there something specific in the math that I can help with?
Marty Brandl Yes! Thankyou! In factions, if you have a numerator and denominator that are both all variables (like m over a-b) how would you subtract and add that to another fraction that was set up similarly (like p over a-b)?
+Jade Perry that would just be m+p over a-b....
NEVER GIVE UP
Jade Perry did you make it through? I’m in precal rn
Final tomorrow..trying to learn everything tonight 😭😰
How did it go
@@erikagovea2581 I can’t remember, I probably failed but I still graduated so 🥳🥳🥳
@@girlynathalie good for you sis, I'm trying to do a final too 😭
My teacher spent over 5 hours trying to teach my class the basics of this and no one got it, but now because of this video I understood in 3 minutes
Thank you so much! This is way easier than I thought. The internet is an amazing thing.
Thank you my teacher sucks
Yanitza Rodriguez agree
Oh my gosh same my prof literally gets paid to sit there. No lecture.
Ohhhh its 8 years ago then i found this amazing and he still giving a heart to the comment what a legend i salute to you
Thank you!!! After watching so many different videos and reading my book I finally figured it out after watching your video!!!!
I was getting confused on what excluded values were and this helped me a lot thanks!
Wow!! This was so easy to learn!! Thank you so much!! Everyone in my class is failing algebra and none of us really know what’s going on because our teacher gives us notes and makes us do hw but we end up failing since she doesn’t teach us. So this really helped me and my sister!! Thank you!
Be careful, notes and homework are a part of teaching too... 😁🤷♂️ I'm glad you are seeking out extra help like this. That shows you really want to be successful! 👍
@@MartyBrandl I try my best to learn from my notes, but In class our teacher yells at us and says we should of already known this if we get something wrong so I’m pretty scared to ask her anything. 😅 thank you for replying so quick!
@@lillyk3680 Eek! I'm sorry to hear that... 😢 Keep working hard! You can do it! 😊
@@MartyBrandl thank you for the positive encouragement!! I’ll try my best! 😁
This is literally the exact same for my grade
Thanks for the quick tip my teacher doesnt know how to teach, he just gives us worksheets and expects us to know what to do
I'm sorry to hear that. It's great that you seek out information like this to help you to understand! Keep after it! You can do it! 👍
It's so annoying when teachers do that
the ending, when he said " you could do anything you put your mind to" gave me more motivation than I have ever gotten in my life, like I wanna do good at math just for him.
You explained this better than my teacher!
If the denominator is 15x^2 + 30x, we start by setting it equal to zero and then solving.
In this case, we can factor out 15x, so we get the following...
15x^2 + 30x = 0
15x(x + 2) = 0
Then use the zero product property to solve the two pieces.
15x = 0
x = 0
x + 2 = 0
x = -2
So the excluded values would be 0 and -2. We can double-check them to be sure and it turns out that both would get us into trouble with a zero in the denominator!
I hope that helps! :-)
so question how did you get 2? hope you answer this
@@chanelm.9984 It comes from the x + 2, which we can't let be zero or the denominator will be zero.
I hope that helps! 👍
Set the denominator equal to zero and solve.
6n - 2 = 0
6n = 2
n = 1/3
So n can't be 1/3 because the denominator would be zero and we can't have that, of course, because division by zero is undefined.
I hope that helps! :-)
Crunching work literally a day before it's due. Curse procrastination. Also curse my math teacher for sucking at teaching
Thanks for this video
thanks dude, i dont pay attention to my teacher in class at all so this was very helpful
I'm glad you found the video helpful, but I'm curious why you don't pay attention in class...??
@@MartyBrandl I'm on online class, and I get very tired and sleep through class, I take notes, but I mainly rely on videos like this to understand the concept afterwards
@@pablovaldes2810 Online classes can be very challenging to stay engaged. I'm glad you are figuring out a way to learn that works well for you! 👍
I appreciate this brethren.. i really do... thank you 😊
Mans also gives hearts 7 years later, what a legend!!!
I don’t know how but I came up with this in math class since I was bored (my math teacher sucks at teaching), so instead of doing this, the easiest way of explaining this is that you factor the denominator, and once your finished with that, you change the symbol of the second term. Ex: The denominator is (x*2+5x+6). When you factor that you will get (x+3)(x+2), change the symbol of the second term so the restricted values become [-3, -2]. If the denominator has only one term (ex: 7x), then x=0. I don’t know if this is correct, it’s probably wrong since I’m just at grade 8, but it works for me so 🤷♀️🤷♀️.
You're right. That's a good shortcut! Keep working hard on your math! You're off to a great start just being in 8th grade! :-)
how about if the denominator has two term for ex. ( 2x - 5) ?
I like this video it helps me understand excluded value. It is readly a good video.
Yo thanks for this my final is in two weeks but this will help me get started thx!
Thank you for this video. It helps me a lot!😄
This honestly helps so much👏🏾
Thanks for the video dude, this really helped.
This really helped me with my quiz tomorrow! Thanks!
This vid really helped me alot thanks
you are an absolute legend sir
You teach really good!I now get it!Thanks!
On the third one, how do you know which half of the expression to simplify and find the zeros?
The dominator is key to finding the excluded values because we can't divide by zero. We figure out what values of x will make the dominator zero by setting the dominator equal to zero and solving.
I hope that helps! Please let me know if you have further questions! 👍
@@MartyBrandl Thanks! Thant really helps!
I have a quiz tomorrow, and told myself I would study but it’s now 2 am 😭. I wanted to atleast learn something and this made it sooo simple
I just started an intermediate algebra class and I kind of remember this stuff but I need to start with regular algebra again.
thank you so much! :) now i can pass my finals :)
My teacher thought I was cheated in class then I sent her your channel lol now she shows you vids in class
That's classic! Keep working hard and definitely not cheating! 👍
I am actually crying right now. I don't know what I'm doing wrong. There are no videos anywhere that tell me what to do when there are two different variables or a completely different variable in the numerator. Am I making this more difficult than it needs to be by panicking? I haven't completed a single page in my book and I have to hand in grades soon (I'm homeschooled and my mom doesn't know how to do it so I'm relying on the internet) At this point, I'm contemplating giving up because obviously I'm too stupid to understand basic math.
Update: I've figured out what to do when there are two variables in the denominator but a new problem has popped up. What happens when there is an exponent? The teacher's guide says "k^2-9" will become "k+3" and "k-3." I have know idea how they even came to that conclusion.
@@marcelinehall1328 Hang in there! You can do this! 👍
The k^2 - 9 can be factored as a difference of squares (both terms are perfect squares and they are being subtracted). That's where the (k +3)(k - 3) comes from.
Can you give me an example of a problem with the 2 variables?
@@MartyBrandl So after an entire day spent on this one problem, I get it. My brain hurts but I'm sure I'll be able to answer the rest of the problems. The only thing I was having trouble understanding was why or how 9 could possibly be divided into -3 and 3 but now I get that -3 multiplied by 3 is obviously 9. Stupid brain. As for an example, one of the earlier problems I had trouble with was "x+3 over y(z+5)" but according to the teacher's guide, all I have to do is solve for each variable in the denominator. I think the thing that was confusing me the most though was that I used multiple sources that had different ways of going about the problems. One even said that I should use the numerator to cancel out the denominator. But after hours of trial and error, I not only got the problem right but I also understand why I solved it the way I did. Thanks.
Marty Brandl I need help again 😒
Marty Brandl This is seriously getting pathetic
this helped sm thank u
Would whatever you get for x be the excluded value??
You got it! 👍
What does it mean when the equation =Y tho?
Can you give me an example of the whole problem?
@@MartyBrandl The question i have states' Find the maximal domain of the function y=2-1/x-1'
It's multiple choice.
Then the tipe is 'denominator ≠ 0, so find what x valu/s make it = 0 and it is everything but that/those values'
Thank you for responding so prom[tly. I was not expecting a response
@@Scholz23 I'm assuming that the problem looks like this: y = (2 - 1) / (x - 1)? Or is it: y = 2 - (1/x) - 1?
Hmmm...I'm not 100% sure, in the first option x = 1 would make the denominator 0, which is a problem. The maximal domain would be {x | real numbers, except x = 1}.
I hope there's something helpful there! Keep working hard! :-)
@@MartyBrandl Thanks for the help
Thank you, I finally understood this topic :D!
yeah I needed this because my teachers on edgenuity don't understand how to teach.
thank you so much I am not allowed to fail and I might've without you
This legend is still liking comments after 7 years😮
Still useful to this day. TO THIS DAY
This helped me but you should also try to teach it also when it has more than 1 variable.
Omg thanks!! I'm in algebra 1 in 8th grade and she doesn't explain things very well but when I saw this everything made perfect since ^u^
God bless you for your skills :)
i literally hear gibberish, im so stupid, im gonna end up failing 11th because idk wtf is going on, i get completely lost whenever people start putting numbers and letters underneath eachother and do whatever while talking about denominators equaling to 0 or not im so fucking stupid
Looks simple but I'm sure I wont be able to do it.
Thanks! This was really helpful
what an absolute legend
In the last example, why is it -3 instead of +3??
thanks this explained everything i needed to know :)
Thank you , very helpful
Thank youuuu man i have a retake so i have to remember this
Thank you so much! That really helped!
Thanks!! Bro!! That really helps!!👍
thanks this was very helpful
It did really help
I have a question...
If a problem asks you: (Which of the following equations have at least two excluded values? Select all that apply.), do I have to look for the equations that have only two excluded values or one or none? Also, if the equation has only 1 excluded value, does it count as an answer?
Joham Alfonso I would say to be a correct answer to your question of "at least 2" any equation with 2, 3, 4, or more would be a correct answer.
I hope that helps! :-)
thanks!! it helped me so much
this was so helpful
This is now my math class because of coronavirus.
Same
Thank you this helped out a lot
Thank u very much it's readly a easy step
I need to find the value of x but it is in the numerator like: 15x/25y.
Is there more to the problem...like is that set equal to something? Let me know and we'll go from there!
Thanks for helping me
Can you give me an example of a problem you're having trouble with? Then I'll see what I can do! :-)
4/6m^2 please help !
@@phoebeshae What is on the top and bottom of the fraction? (4/6)m^2 or (4/6m^2) or 4/(6m^2)?
Marty Brandl whoops sorry i should’ve clarified. 4 is on the top and 6m^2 is on the bottom.
@@phoebeshae Remember, we have to make sure the denominator can't be zero. So we setup an equation with the denominator equal to zero.
6m^2 = 0
Solve that and we have the value(s) that we must exclude to be sure the denominator is not zero.
I hope that helps! Keep working hard!
Marty Brandl thank you!!
If there is no variable in the denominator. There will be no excluded value right?
Exactly! 👍
How many people are here from their teachers sending them here
Thank you so much i understand now
Super helpful, thanks
thank you for making this video
What if the denominator is 4x^2 - 2x
theoreically, x/0 is infinity
thanks this helped a lot
Forgot to write my notes
This helped so much
What if the denominator is equal to the variable x ONLY?
Then the only thing that will get us in trouble is if x = 0, because we can't divide by 0.
I hope that helps! Keep working hard and asking questions! 👍
Thanks! (I have an exam tomorrow 😭)
Very helpful!
Thanks now i understand it!
Thanks you so much bro
He is right. Don't divide by 0. I ended up breaking my calculator when I put it in xD
thank you so much!
my professor is horrible at teaching this stuff, so i have to go to a youtube video to learn this. Might as well of just not went to school at this point with a professor this bad.
I'm sorry to hear that, but it is a great skill to figure things out using alternative sources as needed! You've got this! 👍
This helped so much I might have failed were it not for you
You didn't fail because you worked at it. That's the key! 👍
🐐
Thank you!!!
What is your denominator? 21? If so, there are no excluded values because the d can be anything and we won't get into trouble.
I hope that helps! :-)
so helpfull thanks!
Thanks 😊😍☺️👍👍😍
if 3power x+y=81 &81 power x-y=3. so value of x/y=
Thanks it helped
Ok how do I go about solving this?
16 / 6n-2
How can I solve 6x/2x-4?
Having the denominator be zero is when we would be in trouble. So, let's see what value(s) of x would make that happen...
Solve
2x - 4 = 0
2x - 4 + 4 = 0 + 4
2x = 4
2x/2 = 4/2
x = 2
That means any value of x is fine, except for x = 2 because that would make the denominator be undefined as we can't divide by 0.
I hope that helps! Keep on keeping on! 👍
tysm teaching my self was hard lmao
dude is 100% Canadian
Close! Minnesotan! 😂
@@MartyBrandl You a GOAT still replying to comments after all these years. Have a good day man.
@@scottveregge2944 Thank you! Have a great day yourself!