cosec a - sin a sec a - cos a=1/tana+cota

[@anveshpandita6714]

Sir I had a doubt , if I do the reciprocal of sinA.cosA and then apply identity and then at end reciprocate again, will that work?

[@Darabdarkid4]

Yes sir I also had the same doubt

[@DonkeySharma-uk4fv]

Yes same

[@anveshpandita6714]

Please reply sir

[@NumberX]

Can you send me an image of your work to my email ID [e-mail] so that I can help you out?

[@NumberX]

Can you send me an image of your work to my email ID [e-mail] so that I can help you out?

[@BROOKLYN.___.]

It is more easy when we use LHS and RHS seperately

[@AbhayJaiswal-tf9iu]

Sir... reciprocal kaise le liya?

[@Saad_thenics]

It will be more easier if we keep cosa x sina and then solve 1/tana + cota to bring it as LHS ❤❤..

[@cswathi8328]

Thank you sir

[@NumberX]

So nice of you.

[@VanshKumar-Trader]

🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉

[@Goodgirlshrutimaurya]

mujhe math nahi aata hai

[@FantasicoXD]

gaai hamara maata hai, hamey kuch nahi aata hai

[@SanjayKumar-nm6rj]

1/(sin)²+(cos)²/(sina+ cosa) kyu likha gaya hai

[@NumberX]

You can write (2/3) = 1/(3/2).

[@AryanYadav-hu1sl]

🎉

[@EAGLE_CRICKET_07]

Nice

[@imgmanga4124]

Op sir

[@manojitkumar2319]

Niman

[@manojitkumar2319]

Bsgd