Hi, thank you for the video. I’d like to ask you a question. How you modeled damage, because as I understood, you have different strain at break for each direction. Thank you.
Thanks for the instruction. They are very helpful. Can you recommend any reference or provide any explanation about the calculations in the Matlab script for R11, R22, .. R13? Thanks.
Hi thank for the post. Can I ask a question please? when you entered the plastic strain stress curve values, which direction you pick? and why? Many thanks!
I picked the machine direction or 0 degree orientation for stress-strain curve. It is optional though. Whichever direction you choose to divide by for calculating anisotropy ratio or yield stress ratio becomes your reference direction, and stress-strain response of reference direction can be used for hardening.
Thank you for your valuable information sir. I have a doubt. I am modelling a composite mateirals. While taking the stress-strain data as you suggested in another video I am not getting as expected. I am trying to apply displacement loading up to 60% strain. What type of input parameters I should give to get close to the experimental data.
Hi, you can define material orientation in Abaqus. If the orientation is along 45 degree of for example of a dogbone specimen, inducing tension will result in response in 45 deg
@@10Minuters so we change the material orientation definition from 'global' to 'coordinate system' and add additional rotation angle as '45' deg in that case?
Hi, thank you for the video. I’d like to ask you a question. How you modeled damage, because as I understood, you have different strain at break for each direction. Thank you.
Thanks for the instruction. They are very helpful. Can you recommend any reference or provide any explanation about the calculations in the Matlab script for R11, R22, .. R13? Thanks.
Hi thank for the post. Can I ask a question please? when you entered the plastic strain stress curve values, which direction you pick? and why? Many thanks!
I picked the machine direction or 0 degree orientation for stress-strain curve. It is optional though. Whichever direction you choose to divide by for calculating anisotropy ratio or yield stress ratio becomes your reference direction, and stress-strain response of reference direction can be used for hardening.
Thank you for your valuable information sir. I have a doubt. I am modelling a composite mateirals. While taking the stress-strain data as you suggested in another video I am not getting as expected. I am trying to apply displacement loading up to 60% strain. What type of input parameters I should give to get close to the experimental data.
Thanks for the wonderful explanation. I had a doubt about how we can do the simulations at 45 and 90 degrees. Can you please reply?
Hi, you can define material orientation in Abaqus. If the orientation is along 45 degree of for example of a dogbone specimen, inducing tension will result in response in 45 deg
@@10Minuters so we change the material orientation definition from 'global' to 'coordinate system' and add additional rotation angle as '45' deg in that case?