I don`t know about The United States, but if I were to walk up to someone in the street over here and ask them to tell me what the sine of pi/4 is, they`d probably look at me as if I were giving birth to a helicopter ! ( Forgive the English humour ).
+Steve MetalHammer I came from the Khan Academy website into the TH-cam page just to look if there's a comment like this on the top and LOL!!! So how many of you are like this?
After dozing off in class multiple times, to realizing I need glasses, and just having a bad focus in general, this makes perfect sense now. Going through it step by step all at once rather than little bits and pieces in class interrupted by people talking really helps. I'm pretty sure my teacher described everything the same way too, minus using the term arcsin
My lad! This. Right here. I have been working on these gosh darn equations for MONTHS failed MULTIPLE tests and FINALLY understand. I am a absolute noob and was truly thinking I was finding the inverse but your explanation just saved me. (Ok I’m a little dramatic but this is groundbreaking)
Ashley Abiva sin cos etc are periodic functions (i.e. they repeat there results after a specific interval of 2pie) . so, for convience, we restrict our domain from (-pie to pie) . and add 2pie in the result to genarlize the solution obtained. hope it was helpful.
I'm glad you got some better drawing software compared to your 2007 videos. That 240p resolution in MS paint was giving me a headache. My complaints about the technical quality aside... I'm using this as a study aid for a big Trigonometry test I have tomorrow, and I have to say that this is helping me memorize those trig identities and inverse functions I need because I fully understand it. I love it now. It's elegant. I needed this after 12 hours of cramming. Thank you Sal. You are a hero.
Hi! I just discovered your channel and your math videos are great! Question; do you have a video where you talk about how to convert trigonometric expressions to algebraic expressions? I'm having trouble with that. Thanks!
Just watched your intro to sine cosine tan vid and then this. I'm starting to understand this the way i wanted to understand trig. Huge respect to you man and good wishes :)
on the ti84 plus CE if you divide by pi on the last part of the video you get -.333333333 then do alpha y= 4: FD to make it -1/3 then since it's radians it's -pi/3 as it's supposed to be
I like Sal's videos within first minute of watching. Then as the video progresses I get more and more impressed with the information he gives and I wish I could like it more and more but unfortunately there is only one like option. Bring back the star rating on TH-cam.
In this particular series, Sal used a convoluted way of explaining the concept. PatrickJMT saved my day. If it weren't for Pat, I would not have understood inverse trig functions. He didn't use the unit circle, but instead employed the graphs of sin, cos and tan. The graphs effectively explained why the domain has to be constrained (due to HLT test), etc. I hope Sal or Khan Academy notices this comment, and revamps the video.
Draw a right angle triangle with a missing value for an angle. Fill in the lengths of the triangle using SohCahToa. (The hypotenuse of the triangle will be 4 and the length opposite to the unknown angle will be 1). Use the Pythagorean Theorem to find the length of the missing side. Use the law of cosines, C^2=A^2+B^2-2ABcos(c), to find the unknown angle, c. (Where side C is the side length opposite to the unknown angle and A and B are the other lengths. The arcsin of 1/4 is the unknown angle, c.
I love you, I love your videos, I love your voice, I love the help you give people like me :D My prof in my first year calculus course has such a thick accent I can't understand him so I have to basically teach myself this stuff but when I get stumped you are my saviour!
@qsierra1 Hypotenuse can be any positive number, the angles won't change. Sal simply said it was 1 because he is assuming the unit circle's radius is 1 for simplicity.
@Artyompyandex Actually, the question would be arcsin(x)= (sqrt2)/2. This is because you are trying to find the radians. And, no, every answer there besides (-pi/4) would be incorrect. This is ok, but you have to remember that you only deal with the 1st and 4th Quadrant with arcsin. the range for both arcsin and arc tan are between (-pi/2) and (pi/2). Your other answers are not within the range. I hope I could help you :)
Good question, arcsin(sqrt(2)/2) is defined in both the first and the second quadrant; it is also defined in multiple rotations around the circle. However Arcsin(sqrt(2)/2) [notice capitalization] is uniquely defined in quadrants 1 and 4. We restrict the Arcsin in these quadrants so that it remains a function.
I hate math class these days. I go into school feeling depressed and stupid and come home frustrated because of my grades and my inability to complete my homework with out profuse outside instruction. I've never been in a situation where a little hard work didn't help me improve.
Good video, as always. One question... my professor was doing a problem similar to yours and we were trying to find arcsin(-sqrt(2)/2). While all of us in the class said that it's -pi/4, he went on to say that it would be the same as his answer, which is 7pi/4. Now... that didn't strike me as right and after watching your video, it seems that was a correct feeling to have. arcsin(x) is the angle between -pi/2 and pi/2 (non-inclusive) whose sin is x, right? So, it's not the set of all angles whose sin is x. I wonder if he was confusing it with Arcsin(x)... which is a thing (it's the set version of arcsin(x)).
bkboggy 7pi/4 would be the same answer because the unit circle goes counter clockwise so if u sub tract or move pi/4 clockwise were the unit circle starts would would end up in 7pi/4
There's a lot of confusion about this...The inverse sine function is a FUNCTION which means there cannot be more than one answer. By definition, the inverse sine function must give answers ONLY between -pi/2 and pi/2, inclusive. That's why answers such as 7pi/4 or 5pi/3 are never correct, for the inverse sine function. However, having an answer from the inverse sine function, sometimes we use that unique answer to go looking for other angles whose sine would give the same result. For example, the inverse sine of 1/2 is pi/6, meaning that's the angle between -pi/2 and pi/2 whose sine is equal to 1/2. There are an infinite number of other angles whose sine is 1/2, such as 13pi/6 and 5pi/6, and these are relatively easy to find, after we get the inverse sine answer, pi/6.
Its a pity how unfortunate and confusing the notations used for inverse trig functions are. First the term arcsin or arctan should be replaced by the term "angle" or "theta" which happens to be the "OUTPUT". The "INPUT" (or the term within brackets) should then be simply called by the appropriate input RATIO i.e. SIN or COS or TAN etc. So Arcsin notation simply becomes theta(sin), Arctan becomes theta(tan) etc. After all, all we are being asked is that if the INPUT provided is a ratio of sides of a right triangle then find the angle or theta which is the OUTPUT. In ordinary Trig functions the INPUT provided is the angle or theta and we are asked to OUTPUT the RATIOS called SIN, COS, TAN etc. So the function is simply termed SIN theta or COS theta etc. So why not just REVERSE the function terms for inverse functions? Sin theta becomes Theta sin, Cos theta becomes Theta cos and so on. Worse than Arcsin is the SIN^-1 which gets confused with Sin theta^-1 or 1/sin theta. Why do all the teachers stick to these archaic and confusing notations?
qualquan I would modify my comment by removing the brackets around sin, cos and tan since the brackets should be used for the actual numerical values of the ratio.
Hmm... I'm still a little confused about how to handle arcsin with a value outside the *-1 to 1* domain. Do I just subtract increments of 2pi? Ex: arcsin(3pi/2) becomes arcsin(pi/2)??
I dont understand how sin(theta) = y , but then he uses arcsin(x) = theta , meaning x = sin (theta), then restricts the x axis but refers to x now as the y axis.. can someone explain how you can just mix and match?
Been doing all of algebra and trig on Khan, and to this point I don't recall ever seeing negative radians. Wouldn't we have to restate that as 2pi - 1/3pi = 5/3pi radians?
but the hypotenuse fro the 45 degree triangle is the square root of 2 and x and y are both 1 so why did you choose one as the hypotenuse? i find that confusing right from the start
Hey, thank you for this video... however i have a misunderstanding: When (i.e) sin(x)=-(sqrt2)/2, couldn't x be (5pi/4), (7pi/4), and (-pi/4)? Thank you for help :)
Yes! I think you are right, but that’s where restrictions usually come in play. Or you write something like (1/4pi*n) n being the number of times it repeats
At 8:14 How do we immediately recognize that this is a 60 degree triangle and why should that be so obvious? Which is the video dealing with that skill?
+PacesetterAbbey Because arcsin can take values only from -1 to 1. That is, the domain is (-1,1). Since pi is not there in the domain, the function is undefined.
Yeah, funny thing that it is as far as I know. Maybe it's not practical to work with multiple periods; if you know 1 you can work out the rest. But that does not mean the other periods don't or cannot exist, and certainly it's just wrong to say f(x) cannot return multiple values! Of course it can: f(x) = x² + 6x + 8 = 0 just to give an example :P
Now I am prepared for you walking up the street.
lhh
Exactly
Let me do it in this blue colour.
*Draws in yellow*
حبيبي والله
I thought I was confused before this video. I now know I had no idea what confused really was, until now.
wow, i talked to my teacher for about 4 hours about this, and you explain all what i need in 5mins... i love you.
You explain it better than my teacher did! (Or maybe it's the fact I can't focus because my class is full of class clowns lol)
Honestly same.
Same.
What are you doing now in your life
@@slenderman4378how old r u now
I don`t know about The United States, but if I were to walk up to someone in the street over here and ask them to tell me what the sine of pi/4 is, they`d probably look at me as if I were giving birth to a helicopter !
( Forgive the English humour ).
+Steve MetalHammer I came from the Khan Academy website into the TH-cam page just to look if there's a comment like this on the top and LOL!!!
So how many of you are like this?
+pranav turlapati 😂
😁😁 Same in India😂😂😂
After dozing off in class multiple times, to realizing I need glasses, and just having a bad focus in general, this makes perfect sense now. Going through it step by step all at once rather than little bits and pieces in class interrupted by people talking really helps. I'm pretty sure my teacher described everything the same way too, minus using the term arcsin
This is way easier than reading it in a book.....THANKS!
*when someone walks up to you in the street and asks you about trig functions*
possibly
Just one up them and start asking questions about literature and grammar rules.
This is what real math is all about. Not something that we memorize a problem, and paste the exact solution in an examination.
8:20 how do you know that side is 1/2 and theta is 60 degrees without calculating it?
I'm using this to study for a calc placement test. :) I'm sure I'll do fine thanks to you!
My lad! This. Right here. I have been working on these gosh darn equations for MONTHS failed MULTIPLE tests and FINALLY understand. I am a absolute noob and was truly thinking I was finding the inverse but your explanation just saved me.
(Ok I’m a little dramatic but this is groundbreaking)
Just wanted to ask,
Are Inverse trigonometric Fns in any ways similar to logarithms?
so im in calculus 2 and this shit popped in the middle of my exam when the teacher hasnt mentionned this once, is this normal?
Yeah, we have to carry all the knowledge from trig/precalc to calc and calc 2...
Kallabotz Is the human mind capable of remembering all that, considering our schools teach us to take orders rather than make them.
man, by your videos you are doing a huge favor for humanity...
Ashley Abiva sin cos etc are periodic functions (i.e. they repeat there results after a specific interval of 2pie) . so, for convience, we restrict our domain from (-pie to pie) . and add 2pie in the result to genarlize the solution obtained. hope it was helpful.
@Divyadeep Singh Why can't the range of tan inverse be [0,π] still one-one and onto ??
I'm glad you got some better drawing software compared to your 2007 videos. That 240p resolution in MS paint was giving me a headache. My complaints about the technical quality aside... I'm using this as a study aid for a big Trigonometry test I have tomorrow, and I have to say that this is helping me memorize those trig identities and inverse functions I need because I fully understand it. I love it now. It's elegant. I needed this after 12 hours of cramming. Thank you Sal. You are a hero.
8:12 nope, im out.
It's a simple formula!
FullChicken44 shut up chicken
@@benjaminsibson8760 L
Hi! I just discovered your channel and your math videos are great!
Question; do you have a video where you talk about how to convert trigonometric expressions to algebraic expressions? I'm having trouble with that. Thanks!
11 years later your comment got a reply
@@ameershahul2968 hurray! lol
@@noblessus 🤣I thought you wont reply
@@noblessus I guess you would be having kids by now
you there bud
we meet again
Just watched your intro to sine cosine tan vid and then this. I'm starting to understand this the way i wanted to understand trig. Huge respect to you man and good wishes :)
Thanks man! I was searching for this information for hours. you're my hero
6:01 I dont understand why theta need to be restricted. Can someone please explain it for me?
on the ti84 plus CE
if you divide by pi on the last part of the video you get -.333333333
then do alpha y= 4: FD to make it -1/3 then since it's radians it's -pi/3 as it's supposed to be
I like Sal's videos within first minute of watching. Then as the video progresses I get more and more impressed with the information he gives and I wish I could like it more and more but unfortunately there is only one like option. Bring back the star rating on TH-cam.
OMG thank you so much sal, for responding to my request! And I understand it fully it now,
0:05-0:06 "I didn't want to write that thick" lol😁
Love your stuff! What software are you using?
In this particular series, Sal used a convoluted way of explaining the concept. PatrickJMT saved my day. If it weren't for Pat, I would not have understood inverse trig functions. He didn't use the unit circle, but instead employed the graphs of sin, cos and tan. The graphs effectively explained why the domain has to be constrained (due to HLT test), etc. I hope Sal or Khan Academy notices this comment, and revamps the video.
you are stupid sorry
Draw a right angle triangle with a missing value for an angle. Fill in the lengths of the triangle using SohCahToa. (The hypotenuse of the triangle will be 4 and the length opposite to the unknown angle will be 1). Use the Pythagorean Theorem to find the length of the missing side. Use the law of cosines, C^2=A^2+B^2-2ABcos(c), to find the unknown angle, c. (Where side C is the side length opposite to the unknown angle and A and B are the other lengths. The arcsin of 1/4 is the unknown angle, c.
You just saved my math grade!!!! Thankyouthankyouthankyou:)
Can't the answer be 5π/3 radians or 300 degrees?
Sin? Makes so much sense. Thanks bro
I love you, I love your videos, I love your voice, I love the help you give people like me :D My prof in my first year calculus course has such a thick accent I can't understand him so I have to basically teach myself this stuff but when I get stumped you are my saviour!
Check when you go to the ''mode'' screen if you have your calculator set on radians or degrees; it should be radians for this video at least.
You are welcomed.
this man saves lives
Thanks a lot sal. Never stop!
Hey Sal. Can you do a presentation on integration involving trig inverse functions?
@Swetlana0 I'd say it's just because he has a tablet now, so it's his actual hand writing, where as before he was using his mouse to write on paint.
God gave that voice for a very good reason. Tnk u.
thank you, im never awake enough in school to pay attention
Best video ever. Thank you so much for making It
this part is simple, its pure memorzaton...
can you give steps on solving identity?
Way better than my math teacher in turkey who cant solve 11th grade problems
Love the way you say "two"
The graphs of the arcsigns look interesting.
Excelent explaination. Thanks Sal.
Excuse me Mr.Sal, do you have presentation on converting trigonometry form to complex numbers? Urgently needed!!
wait a minute 3:24 sin to the negative 1 (sin^-1) isn't supposed to reverse the squared 2 over 2?
@qsierra1 Hypotenuse can be any positive number, the angles won't change.
Sal simply said it was 1 because he is assuming the unit circle's radius is 1 for simplicity.
@Artyompyandex Actually, the question would be arcsin(x)= (sqrt2)/2. This is because you are trying to find the radians. And, no, every answer there besides (-pi/4) would be incorrect. This is ok, but you have to remember that you only deal with the 1st and 4th Quadrant with arcsin. the range for both arcsin and arc tan are between (-pi/2) and (pi/2). Your other answers are not within the range. I hope I could help you :)
What software do you use? Me gusta
Great video!
I live for the day this guy learns grammar.
Ermahgerd! Thank you, Khan Academy!!!
@puzzlepeace19 because the function of Arcsin has a domain of pi/2 and -pi/2. If it was unrestricted then it would be a relation and not a function.
Hey sal, is it possible to have a graph of arcsin? And, if it is could you do a video on that?
Thank you ! That was really helpful
alg. II (adv) final tomorrow. THANKYOU!
This is absolutely amazing.
Good question, arcsin(sqrt(2)/2) is defined in both the first and the second quadrant; it is also defined in multiple rotations around the circle. However Arcsin(sqrt(2)/2) [notice capitalization] is uniquely defined in quadrants 1 and 4. We restrict the Arcsin in these quadrants so that it remains a function.
Why do you restrict it to the 1st and 4th quadrant?
This is very helpful
Thanks a lot man!
really really good explaination
I agree
bless this man
Thank you very much!
I LOVE this guy omfg
WHY? is always the question we need to ask ourselves!
We really need to keep this man off the streets.
Mashallah brother!
how is arcsin different from cosecant? likewise arccos to secant, and arctan to cotan?
Thanks
a very helpful video
I hate math class these days. I go into school feeling depressed and stupid and come home frustrated because of my grades and my inability to complete my homework with out profuse outside instruction. I've never been in a situation where a little hard work didn't help me improve.
Thank you!!!
Good video, as always. One question... my professor was doing a problem similar to yours and we were trying to find arcsin(-sqrt(2)/2). While all of us in the class said that it's -pi/4, he went on to say that it would be the same as his answer, which is 7pi/4. Now... that didn't strike me as right and after watching your video, it seems that was a correct feeling to have. arcsin(x) is the angle between -pi/2 and pi/2 (non-inclusive) whose sin is x, right? So, it's not the set of all angles whose sin is x. I wonder if he was confusing it with Arcsin(x)... which is a thing (it's the set version of arcsin(x)).
bkboggy 7pi/4 would be the same answer because the unit circle goes counter clockwise so if u sub tract or move pi/4 clockwise were the unit circle starts would would end up in 7pi/4
There's a lot of confusion about this...The inverse sine function is a FUNCTION which means there cannot be more than one answer. By definition, the inverse sine function must give answers ONLY between -pi/2 and pi/2, inclusive. That's why answers such as 7pi/4 or 5pi/3 are never correct, for the inverse sine function.
However, having an answer from the inverse sine function, sometimes we use that unique answer to go looking for other angles whose sine would give the same result. For example, the inverse sine of 1/2 is pi/6, meaning that's the angle between -pi/2 and pi/2 whose sine is equal to 1/2. There are an infinite number of other angles whose sine is 1/2, such as 13pi/6 and 5pi/6, and these are relatively easy to find, after we get the inverse sine answer, pi/6.
Its a pity how unfortunate and confusing the notations used for inverse trig functions are. First the term arcsin or arctan should be replaced by the term "angle" or "theta" which happens to be the "OUTPUT". The "INPUT" (or the term within brackets) should then be simply called by the appropriate input RATIO i.e. SIN or COS or TAN etc.
So Arcsin notation simply becomes theta(sin), Arctan becomes theta(tan) etc.
After all, all we are being asked is that if the INPUT provided is a ratio of sides of a right triangle then find the angle or theta which is the OUTPUT.
In ordinary Trig functions the INPUT provided is the angle or theta and we are asked to OUTPUT the RATIOS called SIN, COS, TAN etc. So the function is simply termed SIN theta or COS theta etc. So why not just REVERSE the function terms for inverse functions? Sin theta becomes Theta sin, Cos theta becomes Theta cos and so on.
Worse than Arcsin is the SIN^-1 which gets confused with Sin theta^-1 or 1/sin theta.
Why do all the teachers stick to these archaic and confusing notations?
qualquan I would modify my comment by removing the brackets around sin, cos and tan since the brackets should be used for the actual numerical values of the ratio.
qualquan It doesn't work like that
qualquan how do you get confused between sin^-1 (theta) and sin(theta^-1)???
How do you know at 8:05 that this is 30-60-90 triangle? It doesn't seem to be obvious...
Hmm... I'm still a little confused about how to handle arcsin with a value outside the *-1 to 1* domain. Do I just subtract increments of 2pi? Ex: arcsin(3pi/2) becomes arcsin(pi/2)??
really good!!
Thankyou so much! This was a huge help! (:
how do you figure out-> cot(arcsin(radical x^2-9/x) ?
Yes - they are the same thing!
I dont understand how sin(theta) = y , but then he uses arcsin(x) = theta , meaning x = sin (theta), then restricts the x axis but refers to x now as the y axis.. can someone explain how you can just mix and match?
X is not always "x axis". F(x) is simply using x as an arbitrary placeholder for an input value to a function.
Thanks for the great videos
Been doing all of algebra and trig on Khan, and to this point I don't recall ever seeing negative radians. Wouldn't we have to restate that as 2pi - 1/3pi = 5/3pi radians?
I’m a junior at a Turkish high school but still watching this...
I am here to say that I am still watching this in 2024/11
wish i have you right now instead of my trig teacher
Can you basically just look at the square root over 2 in the y coordinate on a unit circle and find the angle pi/4?
but the hypotenuse fro the 45 degree triangle is the square root of 2 and x and y are both 1 so why did you choose one as the hypotenuse? i find that confusing right from the start
Sal: Says “ninety”
Me: hears “Nani”
What about when they ask for all possible vaules between 0 and 2π do you still use the range restrictions ?
Hey, thank you for this video... however i have a misunderstanding: When (i.e) sin(x)=-(sqrt2)/2, couldn't x be (5pi/4), (7pi/4), and (-pi/4)? Thank you for help :)
Yes! I think you are right, but that’s where restrictions usually come in play. Or you write something like (1/4pi*n) n being the number of times it repeats
At 8:14
How do we immediately recognize that this is a 60 degree triangle and why should that be so obvious? Which is the video dealing with that skill?
Are there more triangles we should be able to immediately recognize? how many..which ones ?
Yeah 30 60 90 and 45 45 90
I like how I know the answers already.
please tell me where you got that ti-85 program!!!!
9 years later your comme t got a reply
Nice explanation! Why is Sin^-1 (π) undefined ? For example, why is this question undefined ? >>>>> sin(sin^-1(π))
+PacesetterAbbey Because arcsin can take values only from -1 to 1. That is, the domain is (-1,1). Since pi is not there in the domain, the function is undefined.
+Akshay Singh Wrong, arcsin can only take values from pi/2 or -pi/2 anything beyond or below that is undefined.
Yeah, funny thing that it is as far as I know. Maybe it's not practical to work with multiple periods; if you know 1 you can work out the rest. But that does not mean the other periods don't or cannot exist, and certainly it's just wrong to say f(x) cannot return multiple values! Of course it can: f(x) = x² + 6x + 8 = 0 just to give an example :P