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Using the rejected solution, would there be any imaginary roots?
Infinite of them, in fact, every solution multiplied by exp(i*2*pi*n), n being integer is also a solution.
(1+5½)÷2 i nicely equal to phi
What?
Using the rejected solution, would there be any imaginary roots?
Infinite of them, in fact, every solution multiplied by exp(i*2*pi*n), n being integer is also a solution.
(1+5½)÷2 i nicely equal to phi
What?