A Locus Problem | Problem 322

[@JefiKnight]

1 will work! (I couldn't help guessing and checking.)

[@bobbyheffley4955]

This is a circle centered at (1/3,0) with a radius of 2/3.

[@trojanleo123]

Agreed. Got the same answer.

[@scottleung9587]

Nice - I'm not very good at locus problems, but they're sure fun to do! (BTW z=1 would work if you plug it into the original equation.)

[@aplusbi]

Thanks for the tip!

[@JamesDuemmel]

The answer can restated as |z-1/3|=2/3.

[@phill3986]

🔥👍✌️😎😎✌️👍🔥

[@damiennortier8942]

±z ±1 = ± 2z
± z ± 2z = ± 1
± 3z = ± 1
or ± z = ± 1
z = {-⅓, -1, ⅓, 1}

[@oenrn]

Not how absolute values work with complex numbers.