It didn't affect your subsequent calculations, but the cross product at 3:59 should be < 3cosu, 3sinu, 0 >. The cross product of two vectors is a vector of the same dimension.
It looks fine to me. However, for the z component, you need to factor out 4sin(u)cos(u) which leaves a factor of (cos v)^2 + (sin v)^2, which equals 1.
It didn't affect your subsequent calculations, but the cross product at 3:59 should be < 3cosu, 3sinu, 0 >. The cross product of two vectors is a vector of the same dimension.
is that why he left out the zero?
It looks fine to me. However, for the z component, you need to factor out 4sin(u)cos(u) which leaves a factor of (cos v)^2 + (sin v)^2, which equals 1.
I like how the subtitles say "pie" for pi
Awesome!!! Even my doggy could do it now!!!
LOL - I realize this was just for demonstrating the idea, but I couldn't help but think it would be so much faster to just use pi X diameter X height.
Really great stuff.
can you check your cross product again 6:53 i think its wrong
Thank you sir
THANKS!
oh i see it now thanks