Al=n=2.7/27 =0.1moles N2=n=2.8/28 =0.1 moles Al=0.1/2=0.05 N2=0.1/1=0.1 Al is limiting reagent Molecular weight of AIN =41 2moles of al gives 2 mole of ain 0.1 mole of al gives 0.1 mole of AIN AIN formed =0.1×41 =4.1 grams
Mam aap bahat achhe se explain karte hein jo doubt school me clear nahi ho pata wo aap kar dete hein. I am in class 10th icse course Thankyou mam.....🙏☺️
4.1 gm AlN and limiting reagent is Al , you can take a feel using unitary method in reaction 2mol Al → 1mol N2 1mol Al → 0.5 mol N2 0.1 mol Al → 0.05 mol N2 But we have 0.1 mol N 2 so half of N2 will react and Al will end so limiting reagent is Al , now 2 mol Al → 2 mol AlN 1mol Al → 1mol AlN 0.1 mol Al → 0.1 mol AlN 0.1 × mass of AlN = 0.1 × 41= 4.1g . Thank you mam ❤
From my initial days of this phase I didn't have crystal clear idea of Limiting reagent and now by your wonderful way I understood completely 😊. The shortcut was also easy to remember
The ans of the home work is.. 4 . 1 Th L.R. is Al in this question. ... & thank u so much madam... wonderful explanation. .. nw I've no doubt in this part...
18:11 for the hw i am getting 5.5 as the 2 in 2AlN applies to both Al and N. does the 2 only apply to Al cuz all the comments say it is 4.1. Can anyone clarifyy…
Kahi se bhi prr lo.. jo dhyan se padta hai usko sab jagah samjh aa jaata hai.. Dhyan se padne se hi sab kuch samjh aata hai... Thank u mam for best explanation...
Ma'am lm science and fun ashuu sir student and I love you sooooooooooooooooooooooooooo muchhhhhhhhhh ma'am ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉 really mam ....anushka mam ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤ Exam are near Nothing is clear Students is fear I have not fear Because...our chemistry queen is here ❤❤❤❤❤❤❤ANUSHKA MAM ❤❤❤❤❤❤❤❤❤❤❤❤❤
The best explaination video of limiting reagent...i had not understand from any of the teacher the limiting reagents concept...but here i understood all the things ..thankyou so much MAM 👑THE CHEMISTRY QUEEN👑
Al=n=2.7/27 =0.1moles
N2=n=2.8/28 =0.1 moles
Al=0.1/2=0.05
N2=0.1/1=0.1
Al is limiting reagent
Molecular weight of AIN =41
2moles of al gives 2 mole of ain
0.1 mole of al gives 0.1 mole of AIN
AIN formed =0.1×41
=4.1 grams
Bro why not we take 0.05 *41 ??
because limiting reagent is Al
@@devanshtyagi5868
@@devanshtyagi5868same ques?
Thank you very much brother
@@devanshtyagi5868it is done just to find the limiting reagent
I loved the starting example that mam gave to crystal clear the topic of L.R...❤Thanks a lot maam😊😊
Mam aap bahat achhe se explain karte hein jo doubt school me clear nahi ho pata wo aap kar dete hein. I am in class 10th icse course
Thankyou mam.....🙏☺️
Answer of last home work question is 4.1g and the limiting reagent is Al ❤️❤️
B.t.w great explanation mam
Can you send a pic / solution for he question
Answer 2×2.05 gram hoga
@@thestraightboy4549 nahi 4*1.025 hoga
Kya difference hai @@ShortEditZ69
Aluminium is Limiting reagent and 4.1 g of AlN is formed
4.1 gm AlN and limiting reagent is Al , you can take a feel using unitary method in reaction
2mol Al → 1mol N2
1mol Al → 0.5 mol N2
0.1 mol Al → 0.05 mol N2
But we have 0.1 mol N 2 so half of N2 will react and Al will end so limiting reagent is Al , now
2 mol Al → 2 mol AlN
1mol Al → 1mol AlN
0.1 mol Al → 0.1 mol AlN
0.1 × mass of AlN =
0.1 × 41= 4.1g .
Thank you mam ❤
Thnx 😢
One of the best chemistry teacher on TH-cam thanku so much mam
Mam answer is 2.05gm ir 4.1 gm
Same
Anushka Mam respect button for her concept and theory.❤
Thanks maam all the concepts are crystal clear 💕💕💕🥰
Kya samjhati hai mam. Kisi ko bhi ekdam samjh aa jaega. So proud of you mam. We want all teachers in India like you.
No shit
no shit #2
no shit #3
No shit#4
No shit #5
From my initial days of this phase I didn't have crystal clear idea of Limiting reagent and now by your wonderful way I understood completely 😊.
The shortcut was also easy to remember
The ans of the home work is.. 4 . 1
Th L.R. is Al in this question. ... & thank u so much madam... wonderful explanation. .. nw I've no doubt in this part...
Her, "Rrrrrrightt" is so goood. Awesome lecture!
The answer to H.W's question is 4.1 grams... BTW, amazing explanation ma'am. All my doubts are cleared. Thanks..
How?? Mine was 4g
Mine also 4g!!!
How my answer is 0.82
Same.. 4.1 grams
My answer. 2 grams
18:11 for the hw i am getting 5.5 as the 2 in 2AlN applies to both Al and N. does the 2 only apply to Al cuz all the comments say it is 4.1. Can anyone clarifyy…
Yes I also think so
I am fully confused why
In homework limiting reagent is Al and AlN is formed 4.1 gm.
mam 4.1 is the answer of homework question
u r teaching very nice
keep it up
2.05
Thnkuu mam😄 I was finding this topic. Very difficult but it is very simple
mam..I searched many vedios but...now my obstacles are clear about limiting reagent..thank u taught nicely with good example at first
You are welcome 😊
"Vedio"? "Obstacles"?
@@aadityavilassharma1802 🤣🤣
@@aadityavilassharma1802 The spelling of obstacles is correct tho lol
@@omgggwowow276 spelling of tha is incorrect....lol😂
Anushka mam is truly 🐐 🔥she is amazing teacher ❤️
This mam is my favourite mam and I like her teaching so much .
Mine ans is 2.05 gm
Unitary method se 4.1 gm
Bro not 2.o5 g its 20.5 g 😂
Thnku so much ma'am now I get it very well☺️😍
Kahi se bhi prr lo.. jo dhyan se padta hai usko sab jagah samjh aa jaata hai..
Dhyan se padne se hi sab kuch samjh aata hai... Thank u mam for best explanation...
Keep watching
Ma'am yrr tussi great ho.🥲khushi ke aasu. Apne Mera doubt clear kardiya
Mujhe limiting reasent concept hi weak tha...vo bhi aapne pdaya to....strong bn gya..😍😍😍😘😘😘
I read in aakash kota mam waha se padha but aap unse kafi accha padhate ho.
Superb superb superb explanation ma'am👏👏🤘🤘😃😃💗💗you explained this topic in a very interesting way😊😊😊😊😊😊
Ans-4.1g AlN is formed
Jiska bhi yeh answer Aya hai like kro
Aur mai pray krti joh bhi like krega uske chemistry mein hamesha full no. Mile
The Answer is 4.1 gram of ALN....😊
Very good session mam.... CRYSTAL CLEAR 👍😘
4.1 aayega ya phir 8.2
@@adarsh_0724 8.2
8.2@@adarsh_0724
AL is the limitting reagent......
And mass of ALN formed .....4.1 g💕
Thank you for making it easy 😇
Kesa aaya answer
Exactly and moles of AlN is 0.1 as. 0.1 moles of Al and then to find the mass of Aln we'll multiply 0.1 with 41=4.1g
Hello
@@farwakhan9155 can u pls tell me full on insta? Pls?
noh answer is 4.1g but limiting reagent is nitrogen
2024 25 batch attendance 😂😊
Present 👋🏻
4.1 answer of AIN and also thanku mam
Home work question ka ans 4g AlN formed and Al is the limiting reagent
Thanks a lot Mam .... 😊😊
Ans of homework: limiting reagent is Al and mass of AlN formed is 4.1gm
Very Conceptual Example Great.
15:47 (half) use earphones
[18:11] is it *4.1g* ? 🙂
too helpful ty Anushka Ma’am!
The way you taught this topic really awesome.
Thanks for such kind of short video for single concept this helps a lot students like me.❤
Mam bahut acche se samjh àaya😊
Its limiting will be Aluminium and the mass of ALN is 4.1gm
Perfect lecture for limiting reagent I understand this concept ❤️
Now I am getting why Anushka ma'am is famous 🎉
H.W: 2.05 g of AIN will be formed
4.1g
Wrong
Bro I got same as 2.05g😊😊
this is the correct answer in all comment option my answer is also same
Same answer 2.05g
Ur smile makes more interesting to watch ur video 😊😅❤❤
The ans for the hw question is 4.1g
Nice explanation maam ❤😊😊
HW ans-4.1g AlN
I am preparing for NEET in Aakash institute.But I can't understand this concept.This video is really very helpful for me.Thank you so much ❣️
Aapka AIATS hoga isliye aap ise dekh rhe ho
Same
Same
I am also preparing for NEET in Aakash Institute
In which branch are you studying in Aakash institute
Thanku so much mam
Aapney jo car se start kiya vo bhaut hi accha tha thanku so much mam
H.W ans = 4.1 gm
Thanks a lot ma'am for making our concept clear. Now I will struggle with the questions of limiting reagent
AlN :- 41×0.1 = 4.1g ans
Mam I searched many videos but now my obstacles are clear about limiting raegent thanks a taughty nice alay
Abey kya kya bole ja rha hai😅
This mam is crystal clear thank you for explaining us
For me , you are best chemistry ⚗️⚗️ teacher ♾️ forever'
Limiting reagent is (Al) and mass of AlN is 4g
18:11 The answer is 5.5g AlN ?
4.1 g may be
4.1 absolutely right
4.1 g is the correct one
Hw ans( 4.1 g )
There’s no other way that can be simple than this one......
You are the right teacher for chemistry ❤❤❤thank you
8.2 g ans is right
Mam can we use this trick in half yearly exam for class 11
yes Hema
A very good session of physics, I wasn't distracted even for a second
it was chemistry friend.
@@sastikanandi1063 😂
It's chemistry.....😒
Keep Loving Btw it was chemistry 😁
@@atpstarphysics Oh, was it? Sorry I was lost in your eyes
Thank u for such a great concept
Mam u r so cute and you explanation is excellent ☺️☺️
Mam can u send ur no...
Ma'am lm science and fun ashuu sir student and I love you sooooooooooooooooooooooooooo muchhhhhhhhhh ma'am ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉 really mam ....anushka mam ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Exam are near
Nothing is clear
Students is fear
I have not fear
Because...our chemistry queen is here ❤❤❤❤❤❤❤ANUSHKA MAM ❤❤❤❤❤❤❤❤❤❤❤❤❤
Shut up man
Nice teach mam I love u mam and love ur teaching tq so much mam for clarification all the subject clearly ❤️❤️❤️
It's my pleasure
Your explanation is so good
The best explaination video of limiting reagent...i had not understand from any of the teacher the limiting reagents concept...but here i understood all the things
..thankyou so much MAM
👑THE CHEMISTRY QUEEN👑
Answer is 4.1 as lr is al and mass of aln is 0.05×82👍🏻💯
Best teacher 👏❤️
Thank you! 😃
Answer of homework question is 4.1g 😊😊
Tq so much ma'am our school teacher doesn't teach us well but after watching this video all my concepts are crystal clear
mam i love your teaching method
🥰😍
Ma'am avogadro no of thanks to you for this nicee explanation 🚶♂️
🙂
Mam you are a good teacher and also very beautiful
Thank you so much ma'am ❤️
Most welcome 😊
miss anushka you are the great one in the world for me watching from afghanistan 🇦🇫🇦🇫🇦🇫🇦🇫🇦🇫
Thanku mam
Beauty+brain 🧠 Mam's
😊
4.1 gm mass of ALN and AL is the limiting reagent
Good session mam♥️
True 🐦
Yes it's right
Homework question answer
4.1g
Thanks ma'am 🥰🤩 aapne Mera concept clear kar diya
Now..... new class,new josh , new teacher,new masti but old we 😅😅
Best of luck for every jee/neet aspirants 🌚
😊 very best explanation nice mam😅❤
Mine answer is 2.05g and think it's correct 👍
Yeah..
But most of the people in the comment section are saying that 4.1 is the correct answer
@VIRAT ERA CLUB ooh niceee..😇
I'm so confused...I can't find the solution 😕
Concept crystal clear
Thank you for making my study easy ❤❤❤❤❤❤❤
Thankyou so much maam for explanation ...
Most welcome 😊
Very fast and efficient with quality content
Mass of AIN is 4.1 gm
Same
Crystal clear💖
Plz mcqs bhi upload krein?
Crystal clear ma'am
4.1g AlN is formed
Yaha Mam ki Good Explanation ke Regarding Comment Kr K hum ATP STAR Physics ke jale pr namak chidak rahe hai😂😂😂😂😅😅
Mam ap kitna accha padati hoo....🤭🤭🤭😊😊
I am in 10th class and preparing for Olympiad....
Thanku mam
last Q. ans - mass of ALN is 4.1 g