Why do Capacitors allow AC, but block DC?

It's well known that a capacitor blocks DC, but allows AC. This video explains the exact reason behind this phenomenon.
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[@codyramos3200]

Best explanation on TH-cam. Informative, short , simple . 10/10

[@Artist13172]

Formula: Xc=1/2 Pi fc....... as we know that DC signal has 0hz frequency if you substitute this value in reactance Xc formula we get ♾infinity so if the reactance is high then current doesnot pass through it. This is why dc is blocked by capacitor in which we can prove theoritically.

[@air_cooler]

Then what if i connect capacitor in parallel to rectifer output circuit still does this apply in that case we won't be able to use capcitor in full bridge rectifiers....

[@kshay-Jindal]

Then why does capacitor allow current to pass through it while charging ?

[@tedlahm5740]

Sir: You short video was EXTREMELY informative. Great things come in small packages. thank you.

[@haleembaig7887]

missing enough things in capacitor AC behaviour bro but still all videos all are the best keep on in this way

[@jeffbeck6501]

What Cody said. Best explanation on TH-cam. Informative, short , simple . 10/10

[@GamingKeenBeaner]

Each phase of AC is actually DC; so what capacitors really block is anything above a certain capacitance. Still, effectively it blocks DC more than AC like the video states.

[@smrithis8397]

tysmm sir searching for this since so many days

[@benlee3545]

Very underrated video. More thumbs up should give for this.

[@ahmadfuadi8632]

Great 👍 easy tp understand

[@joarhussain]

Great clear and straight to the point explanation!

[@shrikantsawarkar3929]

Great simple and crisp explanations 👍

[@eeeqwerty7127]

Keep doing
Keep growing

[@patrickjacobsen7805]

Very good explanation

[@ikkicarlos]

good explanation

[@Festus2022]

BUT, the capacitor doesn't block DC during the charging process. in fact, when the charging process begins, the capacitor acts like a short. Isn't this correct??

[@chenjim1247]

As you said, the current decreases but still exists in part 2. If the source voltage is V = |sin(t)|, it is a DC current and what does the current perform in this case?

[@ENGINEERINGANIMATION]

In a pulsating DC current, the capacitor filters out the ripples.

[@FallingESP]

eficient explanation.

[@sriramsriram9195]

Correct

[@murph_mustela]

Fantastic explanation, but you could do with a better mic.

[@lakshmikhatun7151]

Very Good

[@NullCyan]

Thank you so much, it makes sense for me now

[@bakumhaku6454]

Why does the capacitor discharge with decreasing voltage?

[@babytaiyewale8401]

Because when voltage start decreasing capacitor act as power supply by supplyng the the current to the circuit by discharging itself

[@subhz06]

Because after capacitor gets somehwat charged,it's V is greater than the decreasing induced V due to ac so charge flows from higher to lower V

[@SAJAN_ECE]

Nice work

[@ENGINEERINGANIMATION]

Thanks a lot!

[@turbo_facts57]

🥂📈

[@kaiserschnitselsr.9228]

may as well read wiki instead of indi crap

[@GetFamousORDIETRYING]

youre trying to learn? cause hes trying to teach