I did other way around. Making b=100/a, going to c=2a and then solving 2a^2=300, resulting in a=5sqrt(6). Substituting it back in the previous equalities result in c=10sqrt(6) and b=20/sqrt(6), which can be added (a+b+c) resulting in 110/sqrt(6), which can be transformed into her result (multiplying twice by sqrt(2) in numerator and denominator.
Maam it's very much appreciated for this tutorial
Very effective maam
Values are correct and effective solution
Too easy for math olympiad
Simplified correctly and Chinese methods used
@harshpathak2359 • What Chinese methods was used ? 🙄
Maam, solution are very good and I liked these steps
very nice explaination💯💯
Teaching methods are good
lovely❤❤
Very nice mam 👌 👍
Good 👍👍
good explaination💯
I did other way around. Making b=100/a, going to c=2a and then solving 2a^2=300, resulting in a=5sqrt(6). Substituting it back in the previous equalities result in c=10sqrt(6) and b=20/sqrt(6), which can be added (a+b+c) resulting in 110/sqrt(6), which can be transformed into her result (multiplying twice by sqrt(2) in numerator and denominator.
What a wonderful day here
10^10 2^52^5 1^12^1 2^1 (b ➖ 2a+1) 10^20 10^5^4 2^5^5^4 2^1^12^2 1^1^2 1^2 (c ➖ 2b+1) 10^30.10^5^6 2^55^6 2^1^1^3^2 2^1^3^2 1^13^2 3^2 (c ➖ a+2).