Either some mafia-type threatened your life for saying "or not 2B" or you have a sore throat. So you should either call the cops or a doctor. Get well!
Another, more elegant way to list all the solutions is x = (3k±1) * pi/6, or perhaps k*pi/2 ± pi/6, for integer values of k. (I used k rather than n since the idea of these integer values differs from the idea used in your video.)
Hey, are you alright? Your voice seems down these videos. Hope everything is okay for you. I can't completely understand what you are going through, I pray it becomes wonderful for you. P.S. Interesting problem indeed. Have a great day ahead.
I set a=16^(sin^2 x) and b=16^(cos^2 x). Our given equation gives us that a+b=10, and we can f out that ab=16^(sin^2 x+cos^2 x)=16. That means we can use the binomial formula to give us that a and b are the roots of the equation u^2-10u+16, which is pretty much the formula you solved.
@@seroujghazarian6343 That's true, too, but one of the beautiful things about math is that you can solve problems in many different ways, each of which can be a "correct" way. This still got to the solution and wasn't exactly a "no pain, no gain" approach.
Either some mafia-type threatened your life for saying "or not 2B" or you have a sore throat. So you should either call the cops or a doctor. Get well!
Well said 😂
It's the viruses that attacked my vocal chords. They are too powerful and impossible to fight!
Wish you speedy recovery.
Thank you! 💖
Another, more elegant way to list all the solutions is x = (3k±1) * pi/6, or perhaps k*pi/2 ± pi/6, for integer values of k. (I used k rather than n since the idea of these integer values differs from the idea used in your video.)
shush
Beautiful exercise!!
Glad to hear that
Substitute 16^sin^2x=t & solving We get the value of x
Hey, are you alright? Your voice seems down these videos. Hope everything is okay for you. I can't completely understand what you are going through, I pray it becomes wonderful for you.
P.S. Interesting problem indeed.
Have a great day ahead.
Thank you! I had sore throat and had lost my voice! Have you seen it?
Feeling better now. 🧡
I set a=16^(sin^2 x) and b=16^(cos^2 x). Our given equation gives us that a+b=10, and we can f out that ab=16^(sin^2 x+cos^2 x)=16. That means we can use the binomial formula to give us that a and b are the roots of the equation u^2-10u+16, which is pretty much the formula you solved.
I meant the quadratic formula. Not quite sure why I had binomial on the brain.
You only need a, because b=16/a
@@seroujghazarian6343 That's true, and that's one way to do it. This is just another.
@@felaxwindwalker206 they're almost equivalent anyway.
@@seroujghazarian6343 That's true, too, but one of the beautiful things about math is that you can solve problems in many different ways, each of which can be a "correct" way. This still got to the solution and wasn't exactly a "no pain, no gain" approach.
Here's an idea for a video : simplify a trigonometric equation like sinx/cosx + secx/tanx
multiply by 16^sin^2 x or 16^cos^2 x solve the quadratic and u r done
I like trigonometric equations!!!!I am glad to be able to solve it !!!
You seem sick.. May Allah give u a prompt good health soon. Amen
This is jee main pyq
±π/6, ±π/3 and their alignment angles
±π/12 and their alignment angles, fundamenral period: pi/2.
x = 0.5736 or 1.1472
Good exercise for secondary school. ☺☺☺☺☺☺
Yes it is!
Yay
Throat problem again? Get well soon!
Yes! Thank you 🥰
Lost me at pi