Preparation of alkynes | Alkenes and Alkynes | Organic chemistry | Khan Academy

Note that if a terminal alkyne is produced, the strong base will deprotonate the alkyne to form an alkynide anion. A proton source (like H2O) must be added to regenerate the terminal alkyne. Created by Jay.
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Organic Chemistry on Khan Academy: Carbon can form covalent bonds with itself and other elements to create a mind-boggling array of structures. In organic chemistry, we will learn about the reactions chemists use to synthesize crazy carbon based structures, as well as the analytical methods to characterize them. We will also think about how those reactions are occurring on a molecular level with reaction mechanisms. Simply put, organic chemistry is like building with molecular Legos. Let's make some beautiful organic molecules!
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[@umbrellatree6632]

How many moles of NaNH2 were used in the first reaction

[@mohamadhanan5706]

so these are the only ways to prepare alkynes ??!!

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Why do we need three equivalents?

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ooooppsssyyy i see the vincinal compound formed sooorrryy.

[@mena_fire]

I don’t seem to understand one thing: once N takes the H proton, C has one electron that needs to bond, therefore to form a double bond the adjacent C needs to lose the bond with H or with X and in fact it loses the bond with X but how? I mean, it goes on its own like that?

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[@tridiascarlett9385]

the benzene formed is a geminal compound formed not vincinal o k