How to Determine the Distance Between Geographic Coordinates?
ฝัง
- เผยแพร่เมื่อ 27 มิ.ย. 2024
- this video explains how to determine the distance between two points defined by geographic coordinates, either by calculating the difference in latitude or longitude, or by means of a haversine formula.
Do you want to support this channel? Become a member and receive exclusive benefits:
/ aviationtheory
Facebook Fanpage: / aviation-theory-102745...
::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
If you found this information useful, subscribe, share and like! Soon more content related to the aviation world.
Very clearly explained! Before I didn't know, why and how to use the Haversine formula. You provided the background for all of it.
10/10 helped me pass my coding assignment
High informative and well presented, please keep them coming.
One of the best videos on internet
excellent explanation, thank you
Very good information for measuring distance through coordinates
Watching this video is like playing in kindergarden and then at 11:38 the UFC figther entering and smacking the shit out of you with Half Versed Sinus formula :D
Awesome information.
Great content, thank you
Good job! Thank you
Amazing!
informative, clear and well-organized!
Thank you!!
Thanks man 👍
Thank you!
This was beautiful ❤😊
Thank you
very very good
Well explained
I bit dissapointed, because my main interest was to learn about haversine formula.
The whole video is cool, but the amount of attention paid to the formula is a wasted potential.
If you have a video about it specifically, could be cool to add the link in the description!
Superexcellent ❤
Pls can you do a video on how to calculate distance in kilometers or meters between geographic coordinates.
Bruh. Just convert the answer in miles to Kilometers lol
Change 3440.1 to 6371. That's nautical miles converted to kilometers.
Finally, somebody explained why.
davd
Does haversine formula works on spheroid or ellipsoid. for which one ?
Spheroid, but the ellipticity of the Earth is small, just 0.37% so can be ignored for most navigational purposes.
What if, latitude is on equatorial and source longitude degree is lesser than destination longitude degree and in same hemisphere
Before this video, I have calculated distances between points like a flat earther. (Using the Pythagorean theorem)
😂
We’ll fun fact, the shape of the earth looks like an ellipsoid potato and it’s not a perfect sphere. So we instead use a very complicated formula that works out real distances based on Einsteins theory of relativity. It takes in to account the gravitational force which can be used to model the shape of the earth.😅
@@raveen-a5941 Nothing to do with relativity, it is just the formula for an ellipsoid.
@@karhukivi I thought there was a certain formula to calculate distance on earth using many using like 6 constants, think it was called something like length of arc using hermit transformation🤔 but I’m not sure I might be wrong here, I have not studied this for long time, learned this in my degree of Surveying
@@raveen-a5941 Yes, between points at different elevations on a spheroid, as for primary triangulation surveys, but I don't remember that formula, sorry!
Great video but I am currently faced with another way of calculating the shortest distance that I can't find any info on. Have you covered it in the past? It goes as follows. Given A=60°N 10°E B=50°N 170° W. The shortest route doesn' t follow the 60 parallel but a great circle 10°E 170°W. So from the 60°parallel to the pole is 30° (How do I get this difference?) From the pole to the 170°W meridian is 40° (again how do I get this?) So 30 + 40 = 70 × 60 = 4200 minutes = 4200nm. What is this method called and do you cover it? I don't know how to get the difference from the pole using basic measurement tools allowed on exams.
Update: I just realized the pole is 90° not 0, silly me... that solves the degree difference.
Hey bro i am from India, i am interested to learn this formula please help me
Does this other method use the Spherical Law of Cosines?
7:30 should be
1NM=1.852KM
for 5:29, i keep getting 49.83 when minusing the two points on my calculator. Why wouldnt you just convert both? and why do i keep getting a slightly different answer from you??
how are you calculating btw? degree and minute in the same time?
because 80-30= 50 and 67-18= 49, is right as per video.
Second in 11:15,why the 🌎 radius mention as a constant in the formula, while the earth’s radius changes between the poles to the equator(from 6,378km to 6,357km)- earth isn’t a perfect sphere.
Why not convert do decimal degrees?
28+07/60 etc.
It's much more practical.
Yes. Writing the angles that way. Is valid.
@2:43 lost me here. Why is it difficult to subtract 15 from 30? Why and how did you go from 19,15 to 18,45?
It's 18,75 not 18,45. You can do this because there are 60 minutes in a degree. If you subtract the numbers the way they are, it can be hard to remember what you need to subtract while doing the math. So instead we represent the number in a different way that's easier to understand.
How can I find the angle between two coordinates?
You can find the distance between the two points through de Haversine formula (let's call this distance "d"), and then, given that a great circle measures 40,000 km, the angle between the two points will be: angle = (d/40,000) * 360º
didnt understood las part
I don't know where I am making a mistake. From the calculations in the last task, I get 2842.01NM. Could someone help me?
same here
I get 2826.95 lol
State the radian angles to 5 decimal places.
Find the change in longitude first, then convert that (-14°) angle to radian measure.
1 nautical mile is equal to 1852 meters, not kilometers.
I did the math of the formula and I didn't get the same results
Hi Wael, what data did you use?
Using the mobile devices calculator, I ended up with 4,394 nm, way off somewhere
Äquator is 60.000 kilometers and not 40.000 km, because the Earth is........
The Earth is a globe with a mean radius of 3440.1 nautical miles and thus a circumference of 21614,8 nautical miles. Multiplied by 1,852 = 40030 km.
@@marcg1686 , ...........ha,ha,ha.........
No need for an Equator on Flatardia, numpty. You can’t divide a disc in half when you don’t know how big it is 🙄
@@EmersumBiggins .24 Hours on a Disk............Stupid Nasa Guy..............lol
@@peterhoebarth4234 Hilarious how you think you are normal
"Minoot"
Not really helpful. Your explanation doesn't help to find the difference in longitude. Take this example: E179° 20' 12'', W032° 30' 22''. I can't find the correct difference using your method.
211 50' 34"
What answer did you get
@@cpt.mojtaba148° 09' 26''
You can make your own system, though. I would stick to the decimal numbers included in the GPS info with +/- for N/S and E/W. Google maps use both. Minutes and seconds are just fractions of a degree. A latitude becomes +/-58.97754453 as an example. Quite easy to convert with 0.97754453*60 where the whole number is the result for minutes and the remainder is an extra 60 times (60*60).
ok, with the haversine formula at the end, how are you getting 2827.7? because I've put it in my calculator multiple times with different bracket arrangements to try and get that, but I just keep getting 2842? So I don't know if I'm doing it wrong or if you have the wrong answer? And If I am doing it wrong WHAT am I doing wrong? If I understand correctly, arccos is cos-1 on the calculator? So in my calculator I'm putting: 3440.1*acos((sin(0.488)*sin(-0.244))+cos(0.488)*cos(-0.244)*cos(-0.122-0.261)) and the answer comes up as 2842.0105435058
To get .1 NM precision will require 5 decimal places--not just 3.
.28° is not 488 radian. It is nearer .489 radian. In this task it is to be written as .48870 radian.
-14° = about -.24435 radian.
The change in longitude is properly found by subtracting the exact longitudes, then converting to radians. -21° is about -.36652 radian. (Using -.383 radian would cause 21 NM of error.)
[For exactitude, when calculating you could key in: (28° × pi ÷ 180°),
(-14° × pi ÷ 180°), and
(-21° × pi ÷ 180°). Your calculator knows pi to more than 5 places].
The distance from formula is about 2801.9 NM.