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Q14. Maam didn't explain anything. so here I am. c will be the only one with no optical isomer cause there is always a point of symmetry bout the centre, It will have fac-mer geometrical isomerism tho. in a,b,d it is true that the trans forms will be optically inactive, but their cis forms will show perfect optical activity.Hence they DO have an Optical Isomer.
alag hi mazaa...aise hum log bhi neet ke time pe option kaat ke change kr sakte kya???? Clearly written in 2nd ques it is coordination no...aur apne oxidation no nikal diya ...
Q.14 me maam ne itna fumble kiya🤣🤣....It was the easiest Question on isomerism as Optical isomerism will be shown in the presence of bidentate ligand ( written in ncert ) option C didn't have any bidentate ligand...Thus option C is perfectly correct answer🙃
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Q2 coordination no. =6
+2 is the oxidation no.
6 hona chahiye na kyonki coordination no. To total no. Of lone pair accepted by central metal ke equal hota hai 🤔
Ma'am shydd confuse hogyi hongi
Toh issliye oxidation number likh diya coordination number ki jgha
Yes 6 hi aaega answer silly mistake ho gyi mam se koi na
@@mohammadzeeshan1471 exactly
Yes 6
Yep 👍
Questions 2 .... Coordination number 6
Crct bro
Q14. Maam didn't explain anything. so here I am.
c will be the only one with no optical isomer cause there is always a point of symmetry bout the centre, It will have fac-mer geometrical isomerism tho.
in a,b,d it is true that the trans forms will be optically inactive, but their cis forms will show perfect optical activity.Hence they DO have an Optical Isomer.
Question 2 me co ordination no. Mam 6 hoga
How ???
@@dr.dipayandebnath6505 en bidentate ligand hai aur cl monodentate to coordination no.6 hoga n
@@snehamoon6957 yes. Yes. Correct ✅
@@snehamoon6957 tumne same method se kya tha ?
Thank u so much for this video mam
alag hi mazaa...aise hum log bhi neet ke time pe option kaat ke change kr sakte kya????
Clearly written in 2nd ques it is coordination no...aur apne oxidation no nikal diya ...
🤣
Thank you ❤
Mam q2 me coordination number poocha h to 6 aayega na
11Q) Cr atomic number is 24
Q.14 me maam ne itna fumble kiya🤣🤣....It was the easiest Question on isomerism as Optical isomerism will be shown in the presence of bidentate ligand ( written in ncert ) option C didn't have any bidentate ligand...Thus option C is perfectly correct answer🙃
😂
Not always
Ma'am ques 4 mein all of these hona chaiye because tridentate ko polydentate likh skte hai and woh chelation bhi krega
another one of cognitive dissonance. yes it will be 4. She didn't read all options.
Lovely session
Mam 2nd ques me aapne keval oxidation num nikala hai use 2 se multiply kriye becoz en ek bidentate ligand hai so ans 4 hoga
Mere ko bhi lag rha h 4 hoga
En ka 0 charge hota h chahe 2 lo ya 4 sahe h mam ne jo bataya h
@@Elite_Guardian bhai jaa pehle concept clear kr
@@Elite_Guardian concept shi kro phle
@@neetlover6949 Mam ne oxidation number nikala h to mine wo kha h coordination number 6 he h
Ma'am 2nd part please complete kijeye
Q 2 me coordination no. Pusha hai
Thanks
2nd question ans is D
Ma'am 2nd part 🙂
Coordination part 2 kb hoga complete
At Qno.20 mam kitne khus hue ,mam ko pura question solve nhi krna pra 😂
Mam aap 2 nd part kb karwaoga?
q1 ka answer 6 hoga
Mam pls thoda ache se explain kariye
nicee ♥️
Maam ques 2 m coordination number 6 hona chahiye
Mam ap ke bar Q10 ko check karna
Done mam
Ma'am report : failed
2 question glt hai.. 6 is the correct answer.
Mam ko nii aata hai
Your teaching everything so wrong the 2q 4q they all are wrong teach properly or don't teach
Mam q2 me coordination number poocha h to 6 aayega na