How To balance Redox Equations In Acidic Solution

This chemistry video tutorial shows you how to balance redox reactions under acidic conditions. It also shows you how to identify which half reaction is oxidation and reduction.
Stoichiometry Practice Test: • How To Solve Stoichiom...
Solute, Solvent, & Solution:
• Solute, Solvent, & Sol...
Strong & Weak Electrolytes:
• Identifying Strong Ele...
Molarity Practice Problems:
• Molarity Practice Prob...
Ion Concentration In Solutions:
• Ion Concentration in S...
Dilution Problems:
• Dilution Problems, Che...
___________________________________
Types of Chemical Reactions:
• Types of Chemical Reac...
Solubility Rules:
• Solubility Rules
Predicting The Products of Reactions:
• Predicting The Product...
Activity Series of Metals:
• Activity Series of Met...
Will This Reaction Occur?
• Chemistry - Will The R...
Predicting Products of SR Reactions:
• Predicting Products of...
___________________________________
Double Replacement Reactions:
• Introduction to Double...
Net Ionic Equations:
• Precipitation Reaction...
Writing Chemical Equations From Words:
• How To Write Chemical ...
Solution Stoichiometry:
• Solution Stoichiometry...
Molarity & Dilution Problems:
• Molarity Dilution Prob...
Acid Base Neutralization Reactions:
• Acid Base Neutralizati...
____________________________________
Acid Base Titration Problems:
• Acid Base Titration Pr...
Mixture Problems:
• Mixture Problems
Calculating Oxidation Numbers:
• How To Calculate Oxida...
Oxidation and Reduction Reactions:
• Oxidation and Reductio...
Balancing Redox Reactions:
• Half Reaction Method, ...
Ideal Gas Law Problems:
• Ideal Gas Law Practice...
___________________________________
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[@meowmeow-dw3bi]

when you said the difference between 5-1 did you mean 4? or did you mean 5-(-1)? 3:42

[@RekiaAnnaman]

Please some of the compounds in redox reaction already have OH in them how do we balance such under basic medium

[@victoriafuentes7284]

for the problem at 4:39 sec why is it 6e- and not 5e- on the left side?

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4:39 Is 6e- because 6e- is reducing so it will be 5-6 so it's balance ⚖️

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Does this means under acidic conditions the question will always have an oxygen atom

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KBiO3 + FeS + H2SO4 = Fe2(SO4)3 + K2SO4 + Bi2(SO4)3 + H2O Could help me? thx

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[@reyna5443]

i dont understand h20 and oh both gives O. how are we gonna decide which one to add? and why didnt we add oh to the both sides to make water this time?? it doesnt make sense

[@cross1368]

You add OH- to both H2O’s and you don’t add OH because that’s only for a basic redox reaction

[@nemrickreb7853]

how to know if it is an acidic solution?

[@izzatiafrina8159]

The H+ here is the property of the acidic solution. If for a basic solution, there is OH-. The only different step for a basic and acidic solution is that, after doing all of those steps (you get an acidic solution), you can turn it into basic by adding OH- to both sides of the equation to neutralise the H+ you got after you did the acidic solution. Hope this helps

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51

[@etherealfoe1599]

1:39

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[@sabirl9232]

3:48 5-1 is 4 not 6.

[@detectivefatman1938]

5- (-1) from an earlier comment i read

[@sabirl9232]

@@detectivefatman1938 I’m not talking about a specific charge, I’m talking about the number of electrons needed to balance both sides

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Wait, +5-1= 6?
WHAT?

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Peache nicol Ravelo 5- (-1)

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