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Let b=a^{5/2} so (b+1/b)^2-2=724. Thus, b+1/b=√726(b+1/b)(b^2+1/b^2)=b^3+1/b^3+(b+1/b)=b^3+1/b^3+√726=724*√726This yields b^3+1/b^3=a^7√a+1/(a^7√a)=√726*723=7953√6
E=7953(6)^(1/2)
E=7953√6👍
Let {(a^2)√a+1/(a^2)√a)}=x & y=a^5+1/a^5; => x^2=y+2=724 +2=726;, x=√726=11√6; also {(a^7)√a+1/a^7√a}= (x)(y)-x =724(11√6)-11√6= (724-1)11√6=723(11√6)
?= (√726)^3-3√726= √726× 723= 11√6×723= 7953√6 soln.
Let b=a^{5/2} so (b+1/b)^2-2=724. Thus, b+1/b=√726
(b+1/b)(b^2+1/b^2)=b^3+1/b^3+(b+1/b)=b^3+1/b^3+√726=724*√726
This yields b^3+1/b^3=a^7√a+1/(a^7√a)=√726*723=7953√6
E=7953(6)^(1/2)
E=7953√6👍
Let {(a^2)√a+1/(a^2)√a)}=x & y=a^5+1/a^5; => x^2=y+2=724 +2=726;, x=√726=11√6; also {(a^7)√a+1/a^7√a}= (x)(y)-x =724(11√6)-11√6=
(724-1)11√6=723(11√6)
?= (√726)^3-3√726= √726× 723= 11√6×723= 7953√6 soln.