You are a great teacher! You are so meticulous and so patient. I answer all the questions you ask your students. Please keep these videos available for students like me. I am so so so grateful for your time, energy and your generosity to make these videos. God bless you with you making it number one and your children with good education ❤️🙌🏼
@@ChadsPrep I am an Indian and i should be honest with you. We have an entrance exams ( JEE Advanced ) which allows us into the IIT's and i am sure you know about it. Most of the teachers here in India are incomponent of teaching its level. And i am sure professor, you can teach upto that level. If you raised level till JEE advanced, believe me you will recieve huge crowd from India and you will be helping alot of students. Also this level will be automatically covered. Its my suggestion 🥰😍🤩
@Chad's Prep i am so happy and grateful to you, i found this topic little difficult and you made it very easy I am in grade 11th but still understood everything. THANK YOU.
I'm confused on one aspect, I thought that increasing heat also increases movement of particles/disorder (S). So I don't really understand how heat can be increased without disorder also increasing
Think about the combustion of glucose: C6H12O6(s) + 6O2(g) --> 6CO2(g) + 6H2O(g) The delta H is negative and delta S is positive which means it is spontaneous at all temperatures. Now consider the reverse reaction: 6CO2(g) + 6H2O(g) --> C6H12O6(s) + 6O2(g) This has a postive delta H and negative delta S and is not spontaneous at any temperature. But this doesn't mean it won't ever happen it just means it won't happen on its own. It will have to be accompanied by a huge input of energy from an external source. This is the reaction plants do during photosynthesis, and that big energy requirement is met by photons from the sun! Hope this helps!
Isn't weird if every reaction reaches the equilibrium, so why we count gibbs energy when in the equilibrium gibbs energy it's 0, it doesn't make sense, so reactions becomes neither spontaneous neither non spontaneous. I don't get it
You're right in saying that when every reaction reaches equilibrium that delta G will be zero. But the conclusion you come to seems to be then why do we care? And the idea is that if you have a system which is not at equilibrium but is spontaneous (negative delta G), then the absolute value of delta G under those conditions will tell you the maximum amount of work that can be performed by the reaction as it goes to equilibrium. This is very valuable information for say getting an idea of the maximum amount of work that could be performed by a combustion reaction (like in a combustion engine) as it goes to equilibrium. Ultimately, the more negative a delta G value the more energy that will be released as that reaction goes to equilibrium. Hope this helps!
@@ChadsPrep So how we can count total gibbs E of some reaction if every reaction achieve equilibrium at the end, that means we can count for some reaction more gibbs E depends at which point our rection is, but when our reaction achieves equilibrium we can't count the gibbs E because it becomes 0
So the further a reaction is from equilibrium the greater the magnitude of delta G and the more work that can be done in getting to equilibrium. But once equilibrium is reached the reaction has reached its minimum free energy and no more work can be done by the reaction.
Thanks Ari and that is definitely true! I'm working or refilming the entire playlist this school year. I just finished the 1st semester topics (up through chapter 13) and will be working on the 2nd semester topics in the Spring! Happy Studying!
I got damn tears of happiness when I find a video of you explaining a subject we are learning in class!
One day, you will be competing with khan academy!, amazing explanation, you are helping us a lot!
Actually Khan Academy is sorta overated imo
I’ve never paid for khan academy thanks to teachers like him 😊
You are a great teacher! You are so meticulous and so patient. I answer all the questions you ask your students. Please keep these videos available for students like me. I am so so so grateful for your time, energy and your generosity to make these videos. God bless you with you making it number one and your children with good education ❤️🙌🏼
Glad you found this helpful Krishna and I'm more than happy to have them available here! Happy Studying!
@@ChadsPrep Plz dont stop uploading. You are growing very fast believe me.
@@microcomputers5609 Slow and steady!
@@ChadsPrep I am an Indian and i should be honest with you. We have an entrance exams ( JEE Advanced ) which allows us into the IIT's and i am sure you know about it. Most of the teachers here in India are incomponent of teaching its level. And i am sure professor, you can teach upto that level. If you raised level till JEE advanced, believe me you will recieve huge crowd from India and you will be helping alot of students. Also this level will be automatically covered. Its my suggestion 🥰😍🤩
You just saved me hours of studying. Thank you!
Why couldn't I find this last year. This is best video I' ve watched so far for understanding Gibbs energy. Thank you so much ♥️🙏🙏🙏🙏
Better late than never!
Great explanations. The best on the topic I can find in the internet so far.
Wow, thanks! Glad you found it helpful!
Wow, I wish you were my professor!
Best video I've found explaining the relationship! Helped me on my final exam thank you
Man, thank youuuuuuuuuuuuuuuuuuuu. Damn the way you explained with extra information you just completed the mission with RESPECT ++.
You're welcome - Glad you found it helpful.
Very good explanation of signs in the formula! I like the "what the universe wants" way of looking at it.
Glad that connected with you Christian. Some people connect with the plain math of the equation, but this is my preferred way of looking at to also! 🙂
This is the only video that explains what happens at phase change. Thanks so much. :D
Glad it was helpful, Jamyson!
I've seen multiple of videos before but was only wasting my time.. here I got my concepts clear in just 17 minutes 😍
Glad you found us!
Get higher test scores! Hope this helps for me get high test scores for my chem test tomorrow :)
4 years later and yet you explain better than my teacher lmao tysm!
You're welcome, eunoia, glad it helped!
Thank you for being yourself and teaching. Great videos!
Glad you're finding them helpful Cody! And I have no idea what I'd do if I wasn't teaching!
this man is a genius
watching from iraq
very helpful
ill watch u with interest
Thanks for watching, Abdulrahman.
@Chad's Prep i am so happy and grateful to you, i found this topic little difficult and you made it very easy I am in grade 11th but still understood everything. THANK YOU.
Glad you found us, Dashing Planet - you're welcome!
thank you so much this video cleared all my doubts
That's great to hear, Taran kaur!
beautiful explanation ! Talk and chalk will never die :)
Yes!
Thank you sir , Love from india ❤️:)
Thanks Vasu! Happy Studying :)
God bless this man!!!
Thanks - and you, too!
"Get higher test scores" That is a good mnemonic, I've never heard it before!
😀 😀 😀
This helped me a TON. Thank you!!!!!
This is copy of a video on youtube.
Not thankyou to the man who upload the video ,thankyou to the teacher who gives lecture.
Yeah I think so that's why the teacher is amazing but there are so less comments n subscribers
Yaaaaa...
@@romanreigns542 Hey there, Roman - I am the teacher/lecturer, but I also uploaded the video. Glad you find the video helpful.
U r great in teaching sir
Thanks M! Glad you're finding my videos helpful!
Goated teaching
Thanks, Micah!
YOU ARE AMA-HAZZINGGGGGGGG
And damned good. Superb. Perfect.
Great explanation
Thanks!
This indeed understanding the concept
Great!
My exam is tomorrow I have hope with this explanation I will save a Semester
Hope you do well, J.Z.
@@ChadsPrep I am back to testify this video was very helpful and guess what?
I got it all right!
Thanks very much.
Congrats Jonathan and you're welcome!
Thanks a lot it is easy to understand.
Glad to hear that, amine - thanks for your comment.
I'm confused on one aspect, I thought that increasing heat also increases movement of particles/disorder (S). So I don't really understand how heat can be increased without disorder also increasing
Your the best men thank you so much 💓
You're welcome.
Professor..... What if it is a mixed species system? How do i know which will react with which?
can you clarify what you mean by a mixed species system?
Chad, you have a great head.
I don't know what else to say besides THANK YOU Bon!
Damnnnn such a good video! Thank youuuu, I finally understand
Excellent - glad to hear it!
THANKYOU SO MUCH
You are welcome so much!
You are so good❤
Thank you.
@@ChadsPrep 😊
:)
whats an example of when we will gain heat and get more ordered? its non spontaneous so seems unlikely
Think about the combustion of glucose:
C6H12O6(s) + 6O2(g) --> 6CO2(g) + 6H2O(g)
The delta H is negative and delta S is positive which means it is spontaneous at all temperatures.
Now consider the reverse reaction:
6CO2(g) + 6H2O(g) --> C6H12O6(s) + 6O2(g)
This has a postive delta H and negative delta S and is not spontaneous at any temperature. But this doesn't mean it won't ever happen it just means it won't happen on its own. It will have to be accompanied by a huge input of energy from an external source. This is the reaction plants do during photosynthesis, and that big energy requirement is met by photons from the sun!
Hope this helps!
Isn't weird if every reaction reaches the equilibrium, so why we count gibbs energy when in the equilibrium gibbs energy it's 0, it doesn't make sense, so reactions becomes neither spontaneous neither non spontaneous. I don't get it
You're right in saying that when every reaction reaches equilibrium that delta G will be zero. But the conclusion you come to seems to be then why do we care? And the idea is that if you have a system which is not at equilibrium but is spontaneous (negative delta G), then the absolute value of delta G under those conditions will tell you the maximum amount of work that can be performed by the reaction as it goes to equilibrium. This is very valuable information for say getting an idea of the maximum amount of work that could be performed by a combustion reaction (like in a combustion engine) as it goes to equilibrium. Ultimately, the more negative a delta G value the more energy that will be released as that reaction goes to equilibrium. Hope this helps!
@@ChadsPrep
So how we can count total gibbs E of some reaction if every reaction achieve equilibrium at the end, that means we can count for some reaction more gibbs E depends at which point our rection is, but when our reaction achieves equilibrium we can't count the gibbs E because it becomes 0
So the further a reaction is from equilibrium the greater the magnitude of delta G and the more work that can be done in getting to equilibrium. But once equilibrium is reached the reaction has reached its minimum free energy and no more work can be done by the reaction.
@@ChadsPrep
Thanks
my chem professor could never
Glad the channel is helping you - Happy Studying!
great explanation, but you need a new camera guy, it was hard to focus with the screen moving constantly.
Thanks Ari and that is definitely true! I'm working or refilming the entire playlist this school year. I just finished the 1st semester topics (up through chapter 13) and will be working on the 2nd semester topics in the Spring! Happy Studying!
"The universe wants what every girl wants"
Me: To have fun?
Fun with CHEMISTRY. 😁 😁 😁
oh my god , thanks so lot
You're welcome Danny! Glad you found this lesson helpful!
I wish you were my prof
Great
Why they are not laughing
? ? ?
Organic chemistry.
magnificient.
Thanks!
Pharmaceutical chemistry.
Super
Thanks!
Vikas
Terrible. 'The universe wants what a girl wants', a 'stable' guy. 🤦♂️
You're welcome! 😁😁😁
You look like walter white but balder and older
Not to mention: less criminal activity and more teaching!
One day, you will be competing with khan academy!, amazing explanation, you are helping us a lot!
Thanks Dunya! Helping is all that matters!
This man is a genius
Wow - glad you think so - Happy Studying!