General method for drawing any regular polygon given the measurement of one side

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  • เผยแพร่เมื่อ 27 พ.ย. 2024

ความคิดเห็น • 48

  • @alexbennie
    @alexbennie ปีที่แล้ว +3

    I've read through all these comment, yapping on about "It's wrong!", but no one seems to be fascinated by the fact that such extremely high accuracy is reached by such an extremely low effort method.
    For instance: How many division in "n" parts of lines and angles are suddenly possible after the "Origami Axioms" come into play?
    I've not yet seen Mr Galois or any of his students tackle the -morphisms from Geometry including Origami axioms to their rings and fields and their other headache-inducing, albeit fascinating, contraptions!
    Anyways, late to the party, but YT Algorithm should've known better and recommended this channel years ago... So, a belated, cheers on an awesome channel!
    And secondly, if anyone can tell me who the originator of this method is, I'd love to Delve into that Rabbit Hole!

  • @cbranalli
    @cbranalli 5 ปีที่แล้ว +9

    the hexagon drawn here is perfect
    because the construction establishes
    an equilateral triangle ABO
    and replicates it 5 more times around the circle.
    an equilateral hexagon is indeed comprised of
    6 identical equilateral triangles meeting at a common vertex.
    however - any construction purporting to draw equilateral polygons
    of successive numbers of sides - based on the notion that
    the respective circumscribing circles have centers equally spaced
    along the central vertical line is simply WRONG -
    as a trigonometric analysis will clearly show.
    at best -
    this method will yield good approximations of equilateral polygons
    whose number of sides is "quite close" to the original number of sides -
    in this case 6 - thus 7 8 and 9 as well as 5 4 and 3.

  • @apunctg
    @apunctg 3 ปีที่แล้ว +7

    It's an approximation method ... the accuracy is 1.9 degrees ... try to draw it in CAD ...

  • @josefwintzentlibot7852
    @josefwintzentlibot7852 ปีที่แล้ว +1

    Yes, the heptagon thing is just an approximation because for it to be perfect 7sin(180/7) must be exactly 3. But that is not the case as 7sin(180/7) = 3.037... or 1.24% more than 3.

  • @devildog4805
    @devildog4805 3 ปีที่แล้ว +2

    The sector is a vintage drawing instrument. It uses the same method to lay out any regular n-gon.

  • @supchurch8055
    @supchurch8055 6 ปีที่แล้ว +5

    Well done . Applied mathematics for machine trades ... Divideing head math . 👍

    • @einsteingonzalez4336
      @einsteingonzalez4336 4 ปีที่แล้ว

      If you love this geometry,
      then you might love this higher geometry:
      mathworld.wolfram.com/QuadratrixofHippias.html

  • @philippereverdiau1087
    @philippereverdiau1087 4 ปีที่แล้ว +5

    This 9-sided polygon is not regular, neither the others (probably), except indeed the hexagon !

  • @muhammadwaseembaari
    @muhammadwaseembaari 4 ปีที่แล้ว +2

    Sir this is very good useful easy method important lecture thank you

  • @oussamaziani1551
    @oussamaziani1551 4 ปีที่แล้ว +1

    Thanks from algerian 😀

  • @ssakelvin1923
    @ssakelvin1923 4 ปีที่แล้ว +2

    Thank u alot ave really appreciated from Kenya😊

  • @roselyngbobor900
    @roselyngbobor900 2 ปีที่แล้ว +2

    l understanding it thanks for this good work

  • @OnlineToBrain
    @OnlineToBrain 8 ปีที่แล้ว +9

    But this is not a exact method. It is approximately method.

    • @Nameci-wo1ht
      @Nameci-wo1ht 8 ปีที่แล้ว +1

      This is an exact method if you already have constructed a line segment with the same length as the side of the regular polygon you want to construct.

    • @MustardPipeLibrary
      @MustardPipeLibrary 7 ปีที่แล้ว +2

      Nameci2718, you're just flat-out wrong. I would hope the creator didn't intend for this method to be seen as an always-exact method (one doesn't exist for general regular polygons with compass-and-straightedge only). I would assume that either he knows this is an approximation and didn't think that was worth saying, or he was duped as well.
      Rndm Dud, while what you've said is true, you're missing the point of what Online is saying. What Online is saying is that if you COULD use "perfect" methods perfectly, without any errors, you would get a perfect regular polygon, but if you likewise could use this method perfectly, without any errors, the resulting polygon would unavoidably be NOT regular.
      True, the error may be small enough for most practical purposes, and may easily be overshadowed by other factors when doing an actual physical construction - but again, that was not the point.

    • @MustardPipeLibrary
      @MustardPipeLibrary 7 ปีที่แล้ว +1

      I'm not entirely sure about that. Your expansion seems to be more along the lines of "No method can be perfect in the physical world" which is completely true. To be fair, I don't know exactly what Online's point was, but I took it to be "Even in a perfect world without physical limitations, the method is flawed." That is, dealing with it in a purely mathematical sense. Assuming that is what he meant, your point about physical limitations, while true in our universe, isn't really relevant for the purely mathematical one.
      As I'm typing this, I realize we may very well have the same opinions, just different focal points - your focus being on the physical world, mine being on the pure mathematics. I assume you would accept that, say, Euclid's construction of a regular pentagon is "perfect" in the pure mathematical sense, though it's impossible to perfectly replicate it in the physical world?

    • @MustardPipeLibrary
      @MustardPipeLibrary 7 ปีที่แล้ว

      Probably, yeah, the only difference is what we emphasize.

    • @MustardPipeLibrary
      @MustardPipeLibrary 7 ปีที่แล้ว +1

      You're welcome; I agree that too often TH-cam comments can be insulting and childish, and while I have a bad habit of sometimes being too blunt, I do try my best to not descend to quite that level. (I just hope I didn't go too far in my comment directed to Nameci...)

  • @rajasekaran5333
    @rajasekaran5333 6 ปีที่แล้ว +3

    useful for beginners

  • @nankundaarnold6486
    @nankundaarnold6486 3 ปีที่แล้ว +2

    extremely helpful. Thank you!!

  • @trevorallen3212
    @trevorallen3212 2 ปีที่แล้ว

    So I can in theory I can construct my own protractor 360 degree polygon? Sounds like a fun challenge.

  • @mnek742
    @mnek742 8 ปีที่แล้ว +7

    It was proven *CENTURIES* ago that not all polygons can be constructed with a straightedge and compass. See en.wikipedia.org/wiki/Constructible_polygon . For example, a 7-sided polygon is not constructible.
    It's very easy to prove that this method isn't correct and only produces approximately correct results in certain cases. Try using the C3 for a 3-sided polygon and it won't even work.

    • @kingfuff402
      @kingfuff402 6 ปีที่แล้ว

      A seven-sided polygon (a heptagon) is in fact able to be constructed.
      th-cam.com/video/cErccoHui9g/w-d-xo.html

    • @doublespoonco
      @doublespoonco 5 ปีที่แล้ว +1

      @@kingfuff402 Its close but not 100%

    • @ffggddss
      @ffggddss 5 ปีที่แล้ว

      @Murtaza Nek: That's right. In particular, the actual centers for those polygons would *not* be equally spaced.
      The constructible regular polygons are those whose side count, n, is a product of distinct Fermat ("Fair-mah" - it's French) primes, and any number of factors of 2 (including none).
      The known Fermat primes are 3, 5, 17, 257, 65537.
      [To generate these numbers, start with 2, square each term to get the next, then add 1 to all of the terms.]
      It's unknown whether there are any more (that are prime), but if there are, the next one is larger than an astronomically huge lower bound, and therefore, of absolutely no practical importance. For that matter, neither is 65537.
      The n-values up to 100 that are and aren't constructible, are:
      Yes: 3, 4, 5, 6, 8, 10, 12, 15, 16, 17, 20, 24, 30, 32, 34, 40, 48, 51, 60, 64, 68, 80, 85, 96
      No: 7, 9, 11, 13, 14, 18, 19, 21, 22, 23, 25, 26, 27, 28, 29, 31, 33, 35, 36, 37, 38, 39, 41, 42, 43, 44, 45, 46, 47, 49, 50, 52, 53, 54, 55, 56, 57, 58, 59, 61, 62, 63, 65, 66, 67, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 81, 82, 83, 84, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 97, 98, 99, 100
      But using an accurate ruler and some trig (or a good protractor, for that matter!), you can draw any regular polygon with a given side length.
      With side length s, the height, h, of the center (h is called the apothem of the regular polygon), is
      h = s/[2 tan(180º/n)]
      The method shown in this video is exact only for n=6, which is what it started with, anyway.
      Fred

    • @TheRojo387
      @TheRojo387 4 ปีที่แล้ว

      Straightedge yes, impossible, but marked rulers do make all other polygons constructible.
      And marked rulers render primitive straightedges obsolete.

  • @dr.facilier4322
    @dr.facilier4322 8 ปีที่แล้ว +2

    Nice job dude.,
    Really helpfull

  • @PBS-nm1uu
    @PBS-nm1uu 3 ปีที่แล้ว +2

    what is the angle of the T line??

  • @mr.perfect8750
    @mr.perfect8750 3 ปีที่แล้ว +2

    This guy sounds like the one from Organic chemistry tutor channel. 😅

  • @dddreslu3072
    @dddreslu3072 8 ปีที่แล้ว +2

    nice

  • @dudeyouhavenoidea
    @dudeyouhavenoidea 3 ปีที่แล้ว +1

    Neat

  • @official-obama
    @official-obama 2 ปีที่แล้ว

    Beware that this is only a really good approximation, if you want to draw 1-gons, you might run into some problems.

    • @official-obama
      @official-obama 2 ปีที่แล้ว

      And, the limit step is 1/pi, so by doing an inversion over a unit circle, pi can be obtained, which is impossible, so it also is an approximation going out to infinity, and will slowly become less and less accurate.

    • @official-obama
      @official-obama 2 ปีที่แล้ว

      A 7-gon cannot be constructed using a compass and straightedge.
      If it could only be created from a side, it could be "transported" to a circle using parallelograms.

  • @madhusudanlolge5068
    @madhusudanlolge5068 7 ปีที่แล้ว +1

    this method is not give accuracy which have

    • @ArthurGeometry
      @ArthurGeometry  7 ปีที่แล้ว

      Thank you for your contribution.
      This is an approximation method for drawing by hand, not for an accurate mathematical solution.

    • @VijayaKumar-el2yn
      @VijayaKumar-el2yn 7 ปีที่แล้ว

      Which method have you got ? Please share it.

    • @gottfriedschuss5999
      @gottfriedschuss5999 5 ปีที่แล้ว

      @@ArthurGeometry You are correct, sir, this is an approximation. Actually, it's plenty good enough for many "pencil" drawings. As an example, using your method to inscribe a tridecagon (13 sided polygon) with sides 2 units in length, gives a relative error of about 0.2% larger than the "true" circle should be. This is just fine for dividers that use pencil lead. However, with carefully sharpened machinist's dividers, working on metal, this error will be obvious. Similarly, the error will be quite obvious if using a CAD package with precision set smaller than 0.01 units.
      I'm sure you know this, but for the benefit of other readers, if machinist's/CAD accuracy is required, then a tiny bit of trigonometry will give a precisely accurate solution. As an example, take the above tridecagon with side 2 units long. The radius of the inscribing circle is 1/sin(180/13) = 8.373136 units. In general, the radius is (s/2)/sin(180/n), where s is the length of each side and n is the number of sides.
      Best regards,
      Gottfried

  • @elizacollate8967
    @elizacollate8967 6 ปีที่แล้ว +1

    This method is not accurate enough .All sides are not equal .Please rectify that

    • @okorarewhor7016
      @okorarewhor7016 6 ปีที่แล้ว +2

      construct yours and post for us to watch.

    • @ffggddss
      @ffggddss 5 ปีที่แล้ว

      There is no method with the classical tools - straightedge and compass - that will work for most numbers of sides, n; but with a ruler and some trig calculation (or a protractor), it can be done. As accurately as can be measured with those tools, anyway.
      With straightedge and compass, the scorecard reads as follows...
      Constructible: n = 3, 4, 5, 6, 8, 10, 12, 15, 16, 17, 20, 24, ...
      Not constructible: n = 7, 9, 11, 13, 14, 18, 19, 21, 22, 23, 25, ...
      Fred

  • @mathografixartdesignartdes5452
    @mathografixartdesignartdes5452 5 ปีที่แล้ว +1

    that is not what I am looking for

  • @cringequeen9376
    @cringequeen9376 4 ปีที่แล้ว

    I don't like this one

  • @wizrom3046
    @wizrom3046 9 หลายเดือนก่อน

    So there is not need at all to draw the silly hexagon and the smaller circle?
    Total waste of time all you need are the points A B and O which is just 2 arcs. And to divide A B by 2 so you can get T (that division is a weak point of this system).