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The result of integral (first example), the denominator is: (x+2)^2 no (x+2)^3. Thank you for great lectuce!
Yes u are right
Very helpful and nicely explained:)
thank you sir for the lecture . its very useful !
Sir, why is H1,in and H2,in zero in first example?
The standard enthalpy of formation of a pure element is in its reference form its standard enthalpy formation is zero.
23:39 sir what is the value of X1 and X2 ????why you did not multiply with them ?
Directly simplified, as we know x1=n1/n, substituting it and multiplied with n. Their n cancelled out, remains n1
@@rajubudhoju5405 yes
@@rajubudhoju5405 u answered for every question in commentss topper you are
why can't we just take derivative wrt to x1 rather than changing to moles....because taking derivative wrt to x1, means we have taken 1 mole, so answer should match......... but in that case we get different answer......can anybody please explain it
Same doubt
Anbody 30:35 H2 & H3 = 0 ?
You are taking derivative(partial) of n2H2 and n3H3 wrt n1 at CONSTANT n2 and n3 that's why n3 and n2 becomes zero (not H2 and H3)...
The result of integral (first example), the denominator is: (x+2)^2 no (x+2)^3. Thank you for great lectuce!
Yes u are right
Very helpful and nicely explained:)
thank you sir for the lecture . its very useful !
Sir, why is H1,in and H2,in zero in first example?
The standard enthalpy of formation of a pure element is in its reference form its standard enthalpy formation is zero.
23:39 sir what is the value of X1 and X2 ????why you did not multiply with them ?
Directly simplified, as we know x1=n1/n, substituting it and multiplied with n. Their n cancelled out, remains n1
@@rajubudhoju5405 yes
@@rajubudhoju5405 u answered for every question in commentss topper you are
why can't we just take derivative wrt to x1 rather than changing to moles....because taking derivative wrt to x1, means we have taken 1 mole, so answer should match......... but in that case we get different answer......can anybody please explain it
Same doubt
Anbody 30:35 H2
& H3 = 0 ?
You are taking derivative(partial) of n2H2 and n3H3 wrt n1 at CONSTANT n2 and n3 that's why n3 and n2 becomes zero (not H2 and H3)...