Math Olympiad|Japanese|Algebra.

แชร์
ฝัง
  • เผยแพร่เมื่อ 2 พ.ย. 2024

ความคิดเห็น • 9

  • @suryanarayanabadithamani7686
    @suryanarayanabadithamani7686 หลายเดือนก่อน

    👌👌👌👏👏👏

  • @togelian
    @togelian หลายเดือนก่อน

    In the start of the video it sounded like you meant that (a^5 + b^5)(a^6 + b^6) = a^11 + b^11, but I'm glad you cleared that up at the end

  • @pedagogia8038
    @pedagogia8038 2 หลายเดือนก่อน

    Magnifique ,thank you

  • @key_board_x
    @key_board_x 2 หลายเดือนก่อน +1

    (a + b)² = a² + 2ab + b² → given: a² + b² = 2
    (a + b)² = 2 + 2ab → given: a + b = 1
    1 = 2 + 2ab
    2ab = - 1
    ab = - 1/2
    Resume:
    a + b = 1 ← this is the sum S
    ab = - 1/2 ← this is the product P
    a & b are the solution of the equation:
    x² - Sx + P = 0
    x² - x - (1/2) = 0
    Δ = (- 1)² - [4 * (- 1/2)] = 1 + 2 = 3
    x = (1 ± √3)/2
    a = (1 + √3)/2 and b = (1 - √3)/2 → or → b = (1 + √3)/2 and a = (1 - √3)/2
    (1 + √3)² = 1 + 2√3 + 3
    (1 + √3)² = 4 + 2√3
    (1 + √3)² = 2.(2 + √3)
    (1 + √3)³ = (1 + √3)².(1 + √3)
    (1 + √3)³ = 2.(2 + √3).(1 + √3)
    (1 + √3)³ = 2.(2 + 2√3 + √3 + 3)
    (1 + √3)³ = 2.(5 + 3√3)
    (1 + √3)⁴ = [(1 + √3)²]²
    (1 + √3)⁴ = [2.(2 + √3)]²
    (1 + √3)⁴ = 4.(2 + √3)²
    (1 + √3)⁴ = 4.(4 + 4√3 + 3)
    (1 + √3)⁴ = 4.(7 + 4√3)
    (1 + √3)⁸ = [(1 + √3)⁴]²
    (1 + √3)⁸ = [4.(7 + 4√3)]²
    (1 + √3)⁸ = 16.(7 + 4√3)²
    (1 + √3)⁸ = 16.(49 + 56√3 + 48)
    (1 + √3)⁸ = 16.(97 + 56√3)
    (1 + √3)¹¹ = (1 + √3)⁸. (1 + √3)³
    (1 + √3)¹¹ = [16.(97 + 56√3)].[2.(5 + 3√3)]
    (1 + √3)¹¹ = 32.(97 + 56√3).(5 + 3√3) → you can deduce that:
    (1 - √3)¹¹ = 32.(97 - 56√3).(5 - 3√3)]
    = (1 + √3)¹¹ + (1 - √3)¹¹
    = [32.(97 + 56√3).(5 + 3√3)] + [32.(97 - 56√3).(5 - 3√3)]
    = 32.[(97 + 56√3).(5 + 3√3) + (97 - 56√3).(5 - 3√3)]
    = 32.[(97 * 5) + (97 * 3√3) + (5 * 56√3) + (56 * 9) + (97 * 5) - (97 * 3√3) - (5 * 56√3) + (56 * 9)]
    = 32.[(97 * 5) + (56 * 9) + (97 * 5) + (56 * 9)]
    = 32.[2.(97 * 5) + 2.(56 * 9)]
    = 64.[(97 * 5) + (56 * 9)]
    = 64.[485 + 504]
    = 64 * 989
    = [(1 + √3)¹¹ + (1 - √3)¹¹]/2¹¹
    = (64 * 989)/2^(11)
    = 2^(6) * 989/2^(11)
    = 989/2^(5)
    = 989/32
    a¹¹ + b¹¹ = 989/32

  • @mkhan-893
    @mkhan-893 หลายเดือนก่อน

    using substitution and quadratic equation, you can find 2a^2 - 2a - 1 = 0, and then solve for a, and then substitute and solve for b, to get a = -0.366, and b = 1.366 or vice versa and then just take the power 11 to get the answer to be 30.9

  • @AnikeadeJustina-z7m
    @AnikeadeJustina-z7m 2 หลายเดือนก่อน

    Am sure I will understand this

  • @silasmusa5634
    @silasmusa5634 2 หลายเดือนก่อน

    Algebra the queen of mathematics 😂😂😂😂😂😂😂😂😂😂😂