Finding the Coefficient of Static Friction on an Incline

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  • เผยแพร่เมื่อ 19 ต.ค. 2024

ความคิดเห็น • 71

  • @CripShat27
    @CripShat27 9 ปีที่แล้ว +61

    This is the first time I've sat through a physics lesson without wanting to scream and cry with frustration. Thank you so much.

  • @chichiokoro1639
    @chichiokoro1639 11 ปีที่แล้ว +23

    I must say you are an marvelous teacher, as clear as broad day light. Please post . more. Thanks a lot

  • @Hotboiruben2
    @Hotboiruben2 9 ปีที่แล้ว +123

    So this will be a short video 22:44

    • @sreelakshmi_viswam
      @sreelakshmi_viswam 7 ปีที่แล้ว +2

      haha you should play at a faster speed. 1.5 times worked for me.

    • @d3m0nsh1n3
      @d3m0nsh1n3 4 ปีที่แล้ว +1

      lol so what would a long vid be?

    • @Jaxonyogi
      @Jaxonyogi 4 ปีที่แล้ว

      @@d3m0nsh1n3 ur mom lolll

    • @ukstevedouglas
      @ukstevedouglas 3 ปีที่แล้ว +1

      Maybe this is another meaning of the word 'short' that I wasn't previously aware of

  • @rogerdellerba5908
    @rogerdellerba5908 9 ปีที่แล้ว +8

    i have never come across anyone that has explained this as well as you have; detailed,interesting as simple, as you have done. Just brilliant.
    Thank you.

  • @mrw3440
    @mrw3440 10 ปีที่แล้ว +2

    THAAAAAANK you..
    You have no idea how long I spent and how many different sources I went through trying to get my head around this. And then your one video.. = problem solved.
    Cheers!!

  • @tinae.5051
    @tinae.5051 9 ปีที่แล้ว +4

    A tremendous THANK YOU for explaining this in a way that is very easy to understand. I'm so happy after 4 hours of sorting through websites, my book, my notes, and youtube videos, that I finally found this and now I GET IT!!! I also appreciate your pace. I think most of my class is having problems because of the extremely rapid speed that this information is explained.

  • @bolu2k578
    @bolu2k578 8 ปีที่แล้ว +1

    honestly i don't know what i would have done without this video. you have saved my lab report, amazing video

  • @thelmalutterodt4473
    @thelmalutterodt4473 2 ปีที่แล้ว

    Oh mine, I’m so pleased with this video, you are a life saver 💃

  • @spilledcoffee383
    @spilledcoffee383 ปีที่แล้ว

    Very thorough and very helpful, thanks

  • @jamhamza8004
    @jamhamza8004 2 ปีที่แล้ว

    Bro im in love with you man you just clear my doubts

  • @anonymousyoutuber3002
    @anonymousyoutuber3002 6 ปีที่แล้ว

    You talk a bit slow, but definitely helped me out!!!!!!!!!!!!!!!!!!!!!!!! thanks a lot!

  • @allansplace
    @allansplace 9 ปีที่แล้ว

    Thanks. You're a life saver. I hope you have lots of these types of videos.

  • @jackcamp6231
    @jackcamp6231 7 ปีที่แล้ว +1

    Great vid! I've been one step behind all semester and this really helped.

  • @lukeimurdad2465
    @lukeimurdad2465 3 ปีที่แล้ว

    From the bottom of my heart... thank you

  • @jnguyen1752
    @jnguyen1752 7 ปีที่แล้ว

    You are amazing. This is so clear and precise. THANKS SO MUCH

  • @yusuphukobo
    @yusuphukobo ปีที่แล้ว

    Your the best teacher -----keep it up (Study Hard for better life🤓🤓🤓🤓)

  • @HamzaFarooqui21
    @HamzaFarooqui21 10 ปีที่แล้ว +25

    "short video"...riiiight

  • @samarehart8047
    @samarehart8047 9 ปีที่แล้ว

    You just saved my lab group thank you friend

  • @Varghalur
    @Varghalur 6 ปีที่แล้ว

    I just wanted to thank you for this video! It really helped me!

  • @lesegomotselenyane1706
    @lesegomotselenyane1706 6 ปีที่แล้ว

    thanx,,, u the best,,,,, for a change i wasnt feeling sleepy through this lesson as usual in class

  • @Ariv002
    @Ariv002 2 ปีที่แล้ว +1

    Omg it’s been 8 years.., where are you?

  • @shadykane110
    @shadykane110 8 ปีที่แล้ว

    This is a very well made, sort of succinct (like 26 mins ;) ) video and thanks for it cause I've got a science project tomorrow and its 11 pm.

  • @SharanyaMarik
    @SharanyaMarik 10 ปีที่แล้ว

    Very good video.... made this troublesome topic very clear to me.

  • @yuzuki8959
    @yuzuki8959 ปีที่แล้ว

    Please post more teacher .Thank you.

  • @jasonandmelissanorris6029
    @jasonandmelissanorris6029 11 ปีที่แล้ว +1

    Excellent! Thank you Tony!

  • @mukulsharma5738
    @mukulsharma5738 10 ปีที่แล้ว

    Awesome explanation i have ever seen ! thank u sir

  • @donnairishb.esconde907
    @donnairishb.esconde907 2 ปีที่แล้ว

    Sir you helped me wth ths problem, thank youuu

  • @habeebatalimi4595
    @habeebatalimi4595 ปีที่แล้ว

    I am so impressed thanks a lot

  • @hollowbastion1662
    @hollowbastion1662 3 ปีที่แล้ว

    "Short video" Lasts almost half an hour

  • @jeromejeyz8499
    @jeromejeyz8499 2 ปีที่แล้ว

    Thanks bro u answered all the questions l had u amazing

  • @alexandergarcia3476
    @alexandergarcia3476 10 ปีที่แล้ว

    You just saved me from failing my test tmw, Thanx !!

  • @serinnnn-l9j
    @serinnnn-l9j 27 วันที่ผ่านมา

    Thank you!

  • @bencornell8300
    @bencornell8300 7 ปีที่แล้ว +1

    this was really helpful, thanks

  • @niswahshahrir95
    @niswahshahrir95 6 ปีที่แล้ว

    Finally i understand, thank you

  • @saraacevedo9813
    @saraacevedo9813 4 ปีที่แล้ว

    very helpful ! Thank you

  • @nevermore6073
    @nevermore6073 9 ปีที่แล้ว

    thanks a lot! That was really helpful

  • @luve1707
    @luve1707 6 ปีที่แล้ว

    Really helpful!

  • @usainphelps1491
    @usainphelps1491 6 ปีที่แล้ว

    So friction is the x component divided by the y component relative to the box

  • @chrismiles5816
    @chrismiles5816 7 ปีที่แล้ว

    So is the greek U another way to state coefficient of static friction? Or is that static friction on the object?

  • @adamzarith8740
    @adamzarith8740 ปีที่แล้ว

    thankss bro

  • @TheTomboy345
    @TheTomboy345 9 ปีที่แล้ว

    When would gravity be negative when dealing with ramp problems?

    • @austinsemeta
      @austinsemeta 9 ปีที่แล้ว

      +Martian Martain, Gravity is always positive, The negative and positive come from setting up a coordinate system within a problem.

    • @TheTomboy345
      @TheTomboy345 9 ปีที่แล้ว

      +Austin Semeta so on the diagram is gravity negative because it's usually the opposite force compare to thw other forces the side gravity is on?

    • @austinsemeta
      @austinsemeta 9 ปีที่แล้ว +1

      +Martian the coordinate system set up for this video was that weight or (mg) pushing down on the box except the box was angled, this is where cos theta comes into play. I think of cos as an x value so in flat problems we can also put cos but the angle is 0 and cos0 is just 1 so we usually dont put it there. on the other hand sin is the vertical force or sin(y) value, +-gsin(theta). since gravity is pushing down on the box and the ramp is absorbing the weight of the box, the ramp pushes back on the box in the perpendicular direction. the usual gravity is -9.8m/s^2 is negative because in just about every kinematic dimension problem the object falls back toward the orgin(ground). Gravity would be negative in this coordinate system if we set up the perpendicular values eqaul to each other. Fn=mgcos(theta) and then set the equation equal to zero by subtracting the right side via Fn - mgcos(theta) = 0.
      Long story short, Gravity is positive because Weight=mass*gravity, everything else depends on how your coordinate system is set up and how one manipulates the variables to solve for what is needed.

    • @TheTomboy345
      @TheTomboy345 9 ปีที่แล้ว

      Austin Semeta I really appreciate this.

  • @kissyatienza2287
    @kissyatienza2287 ปีที่แล้ว

    How about on flat ground?

  • @Caritoooo
    @Caritoooo 10 ปีที่แล้ว

    I just took my physics midterm and I got anxious when I found out that my coefficient of friction is less than 1.0. My professor told us that the coefficients are usually less than one. But I got an A on the midterm so I'm not sure. The number was 1.7 just like what you got in here haha.

  • @sasukeuchiha998
    @sasukeuchiha998 8 ปีที่แล้ว +1

    What about the coefficient of static friction on a surface, where the object is not in motion and stays stationary with no other forces on it besides Fn and mg?

    • @Jennifer72591
      @Jennifer72591 2 ปีที่แล้ว

      It’s been five years since you posted this lmao, but to answer your question, you wouldn’t be able to calculate static friction

  • @ronilynflores3726
    @ronilynflores3726 7 หลายเดือนก่อน

    next time give sample solution because I dont understand although I understand your leasson but I want an example.

  • @ilaila3504
    @ilaila3504 7 ปีที่แล้ว

    wow.... thank God for this video. but.... but.... like alllllll the other ones i don't know what mu units are because we don't use mu in my physics. I'm hoping it's Newtons but I'm still unsure what that final 1.73 actually is. would be nice if just one video would say that... what this mu unit is.

  • @Prince-lr4ky
    @Prince-lr4ky 10 ปีที่แล้ว

    like right now the whole thing isn't complicated no more....Wish I had ya as my prof :(

    • @theadchefer
      @theadchefer 10 ปีที่แล้ว +7

      speak english

  • @Madnessj
    @Madnessj 2 ปีที่แล้ว

    make more videos!!

  • @PANDORASBOXRELEASE
    @PANDORASBOXRELEASE 10 ปีที่แล้ว

    so, doesn't the surface type effect the result?

  • @Amlanjyotis73
    @Amlanjyotis73 10 หลายเดือนก่อน

  • @aaronevans1650
    @aaronevans1650 5 ปีที่แล้ว

    You could have started from 17 minuets till the end and we would have been good

  • @somerandometanker3455
    @somerandometanker3455 4 ปีที่แล้ว

    yah real shot my due

  • @STarzzi-
    @STarzzi- 6 ปีที่แล้ว +1

    So u want to find the friction 13:07

  • @Stvrfiire_
    @Stvrfiire_ 6 หลายเดือนก่อน

    Y’all just skip to 20:18 LOL

  • @paulsykes9333
    @paulsykes9333 5 ปีที่แล้ว

    Sat through 20 minutes only to realise you weren't going to bother to explain the Trigonometry involved. What a waste of time