Sir you should teach hole theoritical physics b.sc as well as m.sc on TH-cam , I understand you don't have much time, you can take more time because in this country students take b.sc and m.sc as a degree but there are many students who did not like any dgree but they want to work in physics like me, I think you're the hope of those students. Love you sir
Respected Sir, thank you for your great lecture. But in this lecture at time around 39:00, as I understand - for multiple particles there can be multiple variables to represent their position. But what I can't understand is - how can multiple particles have multiple dimensions ! Hope that as usual you do - you answer my question in such simple and detailed way so that I can understand. Thank you.
Assume zero number of constraints in this example. A single particle in 2D will have two variables (x1, y1). The second particle in the same 2D will have two variables (x2, y2). So, if you consider the set of two particles as our dynamical system, then we have a total of four variables (x1, y1, x2, y2). Similarly, in the 3D case, we have six variables (x1, y1, z1, x2, y2, z2). The set of all variables forms a mathematical space called configuration space.
Sir ur lectures are very useful to me I learnt alot, thank u sir...one doubt,... String of wire between two walls and on that there will be a small bead (bead is free to move), and that bead connected to a pendulum,.. In this what will be the constraint equation and dof for this?
At each time t, we need the location (x-coordinate) of the pendulum and the angle theta which the pendulum is making. So DOF = 2. That is first DOF is x-co-ordinate and 2nd DOF is theta. The length of pendulum is constant (L = C) , and this is the equation of constraint.
Kleppner's book is to be used for the BSc level Mechanics course. Classical Mechanics is at the MSc level, where we use the Goldstein book or equivalent. I will consider this when I handle the mechanics course for BSc Physics students.
Sir you should teach hole theoritical physics b.sc as well as m.sc on TH-cam , I understand you don't have much time, you can take more time because in this country students take b.sc and m.sc as a degree but there are many students who did not like any dgree but they want to work in physics like me, I think you're the hope of those students.
Love you sir
I m the same kind of guy i dont want degree i just need to understand deep about physics
Vry vry nice explaination of every difficult or new word used in msc physics
Thanks for the detailed description sir...Basics are the most important for learning the topic thanks a lot sir Need video's for statistical mechanics
Thanks alot
Also explain virtual work and principle of virtual work
Yes. It's coming.
On whole You tube you are best...
Thnq vry vry much sir for all ur vedios
❤ sir thanks for very clear explanation of every point of physics
Nice leecture sir, Thank you.
Thank you sir ,it was easy to understand
Thank you sir, nice explanation
Notations, transformation equation and equation of constraints... Well explained sir... Thank you
Happy to know that... Keep watching.
Thank you so much
Sir is Mechanics by Dr, jcupadyaya a good one to study alongwith your course
Yes, definitely.
Respected Sir, thank you for your great lecture. But in this lecture at time around 39:00, as I understand - for multiple particles there can be multiple variables to represent their position. But what I can't understand is - how can multiple particles have multiple dimensions !
Hope that as usual you do - you answer my question in such simple and detailed way so that I can understand.
Thank you.
Assume zero number of constraints in this example. A single particle in 2D will have two variables (x1, y1). The second particle in the same 2D will have two variables (x2, y2). So, if you consider the set of two particles as our dynamical system, then we have a total of four variables (x1, y1, x2, y2). Similarly, in the 3D case, we have six variables (x1, y1, z1, x2, y2, z2). The set of all variables forms a mathematical space called configuration space.
Thank you, sir.
Thank you sir!
Thank you sir !!!
Clearly understood. Thank you sir
Glad to hear that.
Thank you Sir.
Sir, Can we say that some of the non holonomic constraints are solvable
No. The meaning of non-holonomic is not solvable.
Tq sir , it means everything sir
For your lectures
It's my pleasure. Keep learning.
Well explained sir . Thank you
Glad you liked it.
Sir ur lectures are very useful to me
I learnt alot, thank u sir...one doubt,... String of wire between two walls and on that there will be a small bead (bead is free to move), and that bead connected to a pendulum,.. In this what will be the constraint equation and dof for this?
At each time t, we need the location (x-coordinate) of the pendulum and the angle theta which the pendulum is making. So DOF = 2. That is first DOF is x-co-ordinate and 2nd DOF is theta. The length of pendulum is constant (L = C) , and this is the equation of constraint.
@@ProfSivakumarRajagopalan Thank u sir🙏
Thank you sir.
Thanks sir
Nice explanation
Sir can u tell more about scleronomic and rheonomic constraints?
Hi, its there in Lecture Number 7 of the classical mechanics playlist. Best wishes.
Thank You Sir
Very nice lecture
Respected sir, if possible try to make videos on mechanics by daniel kleppner book.
Kleppner's book is to be used for the BSc level Mechanics course. Classical Mechanics is at the MSc level, where we use the Goldstein book or equivalent. I will consider this when I handle the mechanics course for BSc Physics students.
@@ProfSivakumarRajagopalan ok. Thank u sir.
Thank you Sir
Nice lectures sir
Thankyou
Thanks for liking.
Thankyou Sir
thanku sir
Sir please provide set coaching
Thank u soooo much sir
All the best.
I even see complete ads on this channel's video...
Joel Jeevan 1st msc physics
Thankyou sir
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